5 missions. Guess, learn, then check. Your place is saved.
Mission 1Can asking 1,000 people tell you what a whole country thinks?
Mission 2Same data, two headlines: "soaring" and "flat". How?
Mission 3A firm's average pay is £60,000, yet 9 in 10 staff earn £25,000. How?
Mission 4Ice-cream sales and sunburn rise together. Does ice cream cause it?
Mission 5Two classes have the same median mark. Were their results the same?
The specification points and sources are listed under the lesson: see Sources.
Mission 1
Can asking 1,000 people tell you what a whole country thinks?
Make a guess: Can asking 1,000 people tell you what a whole country thinks?
Statistics · sampling and types of data
Populations and samples
The population is the whole group you want to know about. A sample is the part of it you actually collect data from.
Samples are quicker and cheaper; sometimes testing destroys the item (testing how long batteries last).
You use the sample to infer (estimate) facts about the population.
Limitations: a sample gives only an estimate, and a different sample would give slightly different results.
Statistics · sampling and types of data
Random samples and bias
In a simple random sample, every member of the population has an equal chance of being chosen.
Method: number every member, then use a random number generator (or names from a hat); ignore repeats.
A sample is biased if it is likely to misrepresent the population, e.g. asking people at a gym how often they exercise.
Larger random samples give more reliable estimates. A larger biased sample is still biased.
Sort it
?Is each sampling method random or likely to be biased?
Tap a statement, then tap the group it belongs in. Then press Check.
Worked exampleStatistics · sampling and types of data
Estimating a population from a sample
Question
A wood has 900 trees. In a random sample of 40 of them, 14 are oaks. Estimate the number of oaks in the wood.
1
Find the proportion in the sample: 4014=0.3514/40 = 0.35
2
Assume the sample represents the wood, so the same proportion applies to all 900 trees
3
Multiply: 0.35×900=3150.35 × 900 = 315
Answer
about 315 oaks
⚠️ Watch out
this is an estimate; it is only sensible because the sample is random and not too small.
Calculate
?A school has 1,200 students. In a random sample of 80 students, 28 cycle to school. Estimate the number of students at the school who cycle to school.
Statistics · sampling and types of data
Types of data
Qualitative (categorical) data are words or categories: favourite sport, eye colour.
Quantitative data are numbers. Discrete data are counted and take separate values (number of siblings). Continuous data are measured and can take any value in a range (height, time, mass).
The type of data decides which charts and averages make sense.
Sort it
?Classify each kind of data.
Tap a statement, then tap the group it belongs in. Then press Check.
Calculate
?A school has 1,500 students. Two random samples are taken. In the first, 12 of 50 students are left-handed. In the second, 44 of 200 students are left-handed. Use all the data to estimate the number of left-handed students in the school.
Mission check
?Can asking 1,000 people tell you what a whole country thinks?
Yes, as an estimate. A simple random sample of 1,000 gives everyone an equal chance, so it usually represents the population well. A biased sample, such as 5,000 people from one website, can be badly wrong however large it is.
Mission 2
Same data, two headlines: "soaring" and "flat". How?
Make a guess: Same data, two headlines: "soaring" and "flat". How?
Statistics · charts and diagrams
Tally charts, frequency tables and pictograms
A tally chart records data as you collect it, in groups of five strokes.
A frequency table lists each category or value with its frequency (how many). A two-way table sorts by two features at once.
A pictogram uses a symbol for a fixed number of items, shown in a key: if one car symbol = 4 cars, then 32131/2 symbols = 14 cars.
Part-symbols must be easy to read: halves or quarters.
Statistics · charts and diagrams
Bar charts: single, dual and composite
A bar chart shows categorical or discrete data: equal widths, gaps between bars, and an even frequency scale from 0.
A dual bar chart puts bars for two groups side by side, with a key.
A composite (stacked) bar chart stacks the groups in one bar: its total height is the total frequency.
A vertical line chart uses thin lines instead of bars, for ungrouped discrete data such as goals scored.
Check what each small square is worth first.
Calculate
?The dual bar chart shows the number of library books borrowed by Year 7 and Year 8 from Monday to Thursday. How many more books did Year 8 borrow than Year 7 altogether over the four days?
Worked exampleStatistics · charts and diagrams
Drawing a pie chart
Question
60 students chose their favourite sport: Football 21, Netball 15, Swimming 9, Tennis 15. Work out the angle for each sector of a pie chart.
1
A pie chart's angles total 360∘360°, so each student gets 360∘÷60=6∘360° ÷ 60 = 6° (angle =totalfrequency×360∘= frequency/total × 360°)
2
Multiply each frequency by 6∘6°: Football 21×6=126∘21 × 6 = 126°, Netball 15×6=90∘15 × 6 = 90°
Football 126∘126°, Netball 90∘90°, Swimming 54∘54°, Tennis 90∘90°
⚠️ Watch out
using the frequencies as angles (a 21∘21° sector) gives a pie that does not fill the circle. To read a pie chart, reverse it: frequency =360∘angle×= angle/(360°) × total.
Calculate
?A pie chart shows how 180 visitors travelled to a museum. The sector for bus is 72∘72° and the sector for car is 130∘130°. How many more visitors came by car than by bus? (Non-calculator.)
Statistics · charts and diagrams
Line graphs: time series and frequency polygons
A time series graph plots a quantity against time (horizontal axis), with points joined by straight lines.
Look for the trend (general rise or fall) and any seasonal pattern that repeats each year. Here sales peak every third quarter.
A frequency polygon shows grouped data: plot each frequency at its class midpoint (5, 15, 25, … for 0–10, 10–20, …) and join with straight lines.
Two polygons on the same axes are easy to compare.
Worked exampleStatistics · charts and diagrams
Reading a stem-and-leaf diagram
Question
An ordered stem-and-leaf diagram shows the ages of 11 people. Key: 3∣43 | 4 means 34. Rows: 1∣2551 | 2 5 5, 2∣1382 | 1 3 8, 3∣04443 | 0 4 4 4, 4∣14 | 1. Find the mode and the range.
1
Use the key: the stem is the tens digit and each leaf a units digit, so the ages are 12, 15, 15, 21, 23, 28, 30, 34, 34, 34, 41
2
Mode: the leaf 4 appears three times on stem 3, so the mode is 34
3
Range: largest −− smallest =41−12=29= 41 − 12 = 29
Answer
mode 34 years, range 29 years
⚠️ Watch out
a stem-and-leaf diagram needs ordered leaves and a key. Subtracting the stems only (4−1=34 − 1 = 3) ignores the leaves.
Statistics · charts and diagrams
How graphs can mislead
Read the vertical axis before the picture. If it does not start at 0 (and has no break mark), small differences look huge.
In chart B the April bar looks 7 times as tall as January's, yet April's 1,030 members are only 3% more than January's 1,000.
Other tricks: unequal steps on a scale, missing labels, pictogram symbols of different sizes, tilted 3-D pie charts.
To say what is misleading, name the feature and its effect.
Sort it
?Is each chart feature fair or misleading?
Tap a statement, then tap the group it belongs in. Then press Check.
Mission check
?Two papers plot the same members (1,000, 1,010, 1,020, 1,030). One says "soaring", the other "flat". How?
The data are identical: membership rose from 1,000 to 1,030, just 3%. The "soaring" chart starts its vertical axis at 995, so the April bar is drawn 7 times as tall as January's. Always read the scale before you believe the picture.
Mission 3
A firm's average pay is £60,000, yet 9 in 10 staff earn £25,000. How?
Make a guess: A firm's average pay is £60,000, yet 9 in 10 staff earn £25,000. How?
Statistics · averages and spread
Mean, median, mode and range
Mean: add all the values and divide by how many there are.
Median: put the values in order; the median is the middle one. With an even number of values it is halfway between the middle two. Its position is the 2n+1(n+1)/2th value.
Mode: the value that occurs most often (there can be more than one, or none).
Range== largest value −− smallest value. It measures spread: how varied the data are.
Worked exampleStatistics · averages and spread
Four measures from a list
Question
8 students spent these times (minutes) on homework: 25, 30, 20, 30, 35, 30, 40, 110. Find the mean, median, mode and range.
1
Order the list: 20, 25, 30, 30, 30, 35, 40, 110
2
Mean: 320÷8=40320 ÷ 8 = 40 minutes
3
Median: n=8n = 8, so halfway between the 4th and 5th values: 230+30=30(30 + 30)/2 = 30 minutes
mean 40 min, median 30 min, mode 30 min, range 90 min
⚠️ Watch out
110 is an outlier. It lifts the mean to 40, above 6 of the 8 values. Without it the mean is 30. Finding the "middle" of the unordered list gives 230+35=32.5(30+35)/2 = 32.5, which is wrong.
Statistics · averages and spread
Averages from a frequency table
In a frequency table each value xx occurs ff times, so each row totals fxfx.
mean=∑f∑fx=number of valuestotal of all valuesmean = (Σ fx)/(Σ f) = (total of all values)/(number of values)
Mode: the value with the highest frequency. Median: find its position, 2n+1(n+1)/2, then use running totals.
Pets owned by 25 people (0 pets: 7, 1: 9, 2: 6, 3: 2, 4: 1): the median is the 13th person, and running totals 7, 16, … show they own 1 pet. The mode is also 1.
Divide by ∑fΣ f, not by the number of rows.
Calculate
?Use the pets table: 0 pets: 7 people, 1 pet: 9, 2 pets: 6, 3 pets: 2, 4 pets: 1. Work out the mean number of pets per person. Give your answer as a decimal.
Statistics · averages and spread
Estimated mean from grouped data
In grouped data you do not know the exact values, so use the midpoint of each class to stand for every value in it.
Estimated mean =∑f∑(midpoint×f)= (Σ (midpoint × f))/(Σ f). It is an estimate because the values are not all at the midpoint.
The modal class is the class with the highest frequency.
The median class is the class containing the 2n+1(n+1)/2th value.
The range can only be estimated: largest possible value minus smallest possible value.
Worked exampleStatistics · averages and spread
Estimating a mean from a grouped table
Question
40 students recorded their journey time to school, tt minutes: 0<t≤100 < t ≤ 10: 8, 10<t≤2010 < t ≤ 20: 14, 20<t≤3020 < t ≤ 30: 12, 30<t≤4030 < t ≤ 40: 6. Estimate the mean and state the modal class.
Divide by the total frequency: 760÷40=19760 ÷ 40 = 19
Answer
estimated mean 19 minutes; modal class 10<t≤2010 < t ≤ 20
⚠️ Watch out
using the upper class limits (10, 20, 30, 40) gives 24 minutes, and dividing by 4 classes instead of 40 students gives 190.
Calculate
?A courier weighs 50 parcels. Mass mm kg: 0<m≤20 < m ≤ 2: 9 parcels, 2<m≤42 < m ≤ 4: 16, 4<m≤64 < m ≤ 6: 15, 6<m≤106 < m ≤ 10: 10. The courier claims the mean mass is under 4 kg. Work out an estimate of the mean mass. Give your answer to 2 decimal places.
kg
Statistics · averages and spread
Choosing an average and comparing data
Mean: uses every value, but an outlier (far from the rest) can drag it a long way.
Median: not affected by a few extreme values; best for data like pay or house prices.
Mode: the only average for categorical data, such as favourite colour.
To compare two data sets, compare an average and the range, in context: "P spent less time on average, and their times were more consistent."
An outlier may be an error: check it before removing it.
Quick check
?Homework times: Class P mean 32 minutes, range 15 minutes; Class Q mean 35 minutes, range 60 minutes. Which comparison is correct?
Mission check
?A firm says average pay is £60,000, yet 9 of its 10 staff earn £25,000. How?
The owner earns £375,000. Total pay is 9×25,000+375,000=£600,0009 × 25,000 + 375,000 = £600,000, and 600,000÷10=£60,000600,000 ÷ 10 = £60,000: a true mean, but higher than 9 of the 10 salaries. The median and mode, both £25,000, describe a typical worker far better.
Mission 4
Ice-cream sales and sunburn rise together. Does ice cream cause it?
Make a guess: Ice-cream sales and sunburn rise together. Does ice cream cause it?
Statistics · scatter graphs
Scatter graphs and correlation
A scatter graph plots pairs of data (two variables for each item) as points, usually crosses. Each axis has its own scale.
Positive correlation: as one variable increases, the other tends to increase.
Negative correlation: as one increases, the other tends to decrease.
No correlation: no clear pattern.
Points close to a line show strong correlation; points loosely spread show weak correlation.
Sort it
?Which correlation would you expect?
Tap a statement, then tap the group it belongs in. Then press Check.
Statistics · scatter graphs
Lines of best fit
A line of best fit is a single straight ruled line, drawn by eye, that follows the trend.
It runs across the whole data set with roughly the same number of points on each side. It need not pass through any point or the origin.
Ignore any outlier (a point that does not fit the pattern).
To estimate, go from a known value to the line, then across to the other axis.
Worked exampleStatistics · scatter graphs
Estimating from a line of best fit
Question
The line of best fit for ice-cream sales passes through (15, 120) and (30, 300), where xx is temperature in °C and yy is sales. Estimate the sales on a day at 24 °C.
1
Find the gradient: 30−15300−120=15180=12(300 − 120)/(30 − 15) = 180/15 = 12 more sales per °C
2
Count up from the known point (15, 120): 24 °C is 9 °C warmer
on a paper you would read this straight off the line on the graph. Working out 24×12=28824 × 12 = 288 forgets that the line does not go through the origin.
Calculate
?Using the same line of best fit, estimate the temperature on a day when 192 ice creams were sold.
°C
Statistics · scatter graphs
Interpolation, extrapolation and outliers
Interpolation: estimating inside the range of the data. Usually reliable if the correlation is strong.
Extrapolation: estimating outside the range of the data. Risky: the trend may not continue.
An outlier may be an error or an unusual case (a day the shop shut early). Leave it out of the line.
A small sample or weak correlation gives only rough estimates.
Quick check
?The ice-cream data covers 12 °C to 31 °C. A student uses the line to predict 480 sales at 45 °C. How reliable is this?
Calculate
?A teacher plots hours of revision (xx) against test mark (yy) for 20 students who revised between 1 and 11 hours. Her line of best fit passes through (2, 40) and (10, 80). Estimate the mark for a student who revised for 7 hours.
Statistics · scatter graphs
Correlation does not prove causation
Correlation shows that two variables change together. It does not show that one causes the other.
Often a third factor drives both. Example: over a summer, sales of electric fans and of cold drinks rise together; hot weather causes both.
Sometimes the link is coincidence, especially with small data sets.
To show cause you need more than a scatter graph, such as a controlled experiment. In an exam, say "correlation does not mean causation" and name a possible third factor.
Mission check
?Ice-cream sales and sunburn cases show strong positive correlation. Does ice cream cause sunburn?
The two variables are correlated because both depend on the weather: sunny days bring more ice creams and more sunburn. Correlation shows variables move together; it never proves that one causes the other.
Mission 5
Two classes have the same median mark. Were their results the same?
Make a guess: Two classes have the same median mark. Were their results the same?
Statistics · cumulative frequency and histograms
Quartiles and the interquartile range (Higher)
In ordered data the median splits it in half; the lower and upper quartiles (LQ, UQ) split it into quarters.
For nn listed values: LQ is the 4n+1(n+1)/4th value, median the 2n+1(n+1)/2th, UQ the 43(n+1)(3(n+1))/4th.
Interquartile range (IQR) == UQ −− LQ: the spread of the middle half, unaffected by outliers.
For 3, 4, 5, 7, 8, 9, 12: LQ is the 2nd value (4), median the 4th (7), UQ the 6th (9): IQR =5= 5.
Calculate
?The marks of 11 students are 23, 15, 30, 18, 12, 28, 20, 35, 17, 25, 22. Find the interquartile range.
Statistics · cumulative frequency and histograms
Cumulative frequency graphs (Higher)
Cumulative frequency is a running total: how many values are up to each upper class boundary.
Plot each total at the upper class boundary, start with 0 at the lowest boundary, and join with a smooth curve.
For nn values, read across from 2nn/2 (median), 4nn/4 (LQ) and 43n3n/4 (UQ), then down.
For how many are more than a value, read up from it and subtract from nn.
Worked exampleStatistics · cumulative frequency and histograms
Median and IQR from a cumulative frequency graph (Higher)
Question
The journey times tt (minutes) of 80 commuters: 0<t≤100 < t ≤ 10: 6, 10<t≤2010 < t ≤ 20: 14, 20<t≤3020 < t ≤ 30: 20, 30<t≤4030 < t ≤ 40: 20, 40<t≤5040 < t ≤ 50: 20. Draw a cumulative frequency graph and estimate the median and IQR.
1
Running totals: 6, 20, 40, 60, 80
2
Plot (0, 0), (10, 6), (20, 20), (30, 40), (40, 60), (50, 80) and join with a smooth curve
3
Median: read across from 80÷2=4080 ÷ 2 = 40 to the curve, then down: 30 minutes
4
LQ from 80÷4=2080 ÷ 4 = 20: 20 minutes. UQ from 43×80=603/4 × 80 = 60: 40 minutes
5
IQR =40−20=20= 40 − 20 = 20 minutes
Answer
median 30 minutes, IQR 20 minutes
⚠️ Watch out
plotting at the class midpoints (5, 15, 25, …) shifts the whole curve left by 5 minutes. Plot at the upper boundaries.
Statistics · cumulative frequency and histograms
Comparing distributions (Higher)
Two data sets can share a median yet be very different. Compare an average (the median) and a spread (the IQR).
A smaller IQR means the middle half of the data is more consistent (closer together).
Write each comparison in context: "The median time for Group A was lower, so on average Group A was quicker. Group A's IQR was smaller, so their times were more consistent."
Use like for like: median with IQR, or mean with range.
Worked exampleStatistics · cumulative frequency and histograms
Drawing a box plot (Higher)
Question
For the 80 commuters, the shortest journey was 3 minutes and the longest 49 minutes. Draw a box plot.
1
Collect the five values: lowest 3, LQ 20, median 30, UQ 40, highest 49
2
Draw a scale from 0 to 50 minutes
3
Draw the box from the LQ (20) to the UQ (40), with a line at the median (30)
4
Draw whiskers from the box out to the lowest (3) and highest (49) values
Answer
a box plot showing 3, 20, 30, 40, 49 on the scale
⚠️ Watch out
the box length is the IQR (20 minutes), not the range (46 minutes). To compare two groups, draw both box plots on the same scale.
Quick check
?Journey times: Group A median 34 minutes, IQR 12 minutes; Group B median 41 minutes, IQR 20 minutes. Which comparison is correct?
Statistics · cumulative frequency and histograms
Histograms and frequency density (Higher)
A histogram shows continuous data with no gaps between bars. When class widths are unequal, the vertical axis is frequency density.
frequency density=class widthfrequencyfrequency density = frequency/(class width)
The area of each bar represents the frequency: frequency=frequency density×class widthfrequency = frequency density × class width.
Example: the class 20<h≤3020 < h ≤ 30 has frequency 15 and width 10, so its bar has height 15÷10=1.515 ÷ 10 = 1.5.
With equal class widths the vertical axis can simply show frequency.
Calculate
?The histogram shows the heights hh cm of some plants. The frequency densities are: 0<h≤100 < h ≤ 10: 1.2, 10<h≤1510 < h ≤ 15: 3.6, 15<h≤2015 < h ≤ 20: 4, 20<h≤3020 < h ≤ 30: 1.5, 30<h≤5030 < h ≤ 50: 0.5. How many plants are taller than 15 cm?
Mission check
?Class X: median 62, LQ 55, UQ 68. Class Y: median 62, LQ 44, UQ 76. Were their results the same?
The same median only tells you the middle marks match. Class X's IQR is 68−55=1368 − 55 = 13 and Class Y's is 76−44=3276 − 44 = 32, so X's marks were much more consistent, while Y had both weaker and stronger students. Always compare an average and a spread.
Recap
Big ideas
A sample is used to estimate facts about a population; the estimate is only as good as the sample.
Random samples avoid bias; bigger random samples are more reliable, but size never cures bias.
Data are qualitative or quantitative; quantitative data are discrete (counted) or continuous (measured).
Choose the chart for the data: pictogram, bar chart (dual or composite) or pie chart for categories; read every value against the scale and key.
Pie chart angle = frequency ÷ total × 360°; reverse it to find a frequency.
A vertical axis that does not start at 0 can make a tiny change look dramatic.
Time series show trends and seasonal patterns; frequency polygons plot frequencies at class midpoints.
Stem-and-leaf diagrams keep every value: ordered leaves and a key.
Mean =number of valuestotal= total/(number of values); median = middle value of the ordered list; mode = most common; range = largest −− smallest.
From a table, mean =∑f∑fx= (Σ fx)/(Σ f); for grouped data use midpoints, and the answer is an estimate.
Outliers drag the mean, not the median: choose the average that fits the data, and compare an average and a spread in context.
Scatter graphs show positive, negative or no correlation.
Describe the strength too: strong or weak.
A line of best fit is a straight ruled line through the trend; use it to estimate, trusting interpolation more than extrapolation.
Correlation does not mean causation: look for a third factor.
Quartiles split ordered data into quarters; IQR = UQ − LQ measures the spread of the middle half.
Cumulative frequency: plot running totals at upper class boundaries; read across from 2nn/2, 4nn/4, 43n3n/4.
A box plot shows lowest, LQ, median, UQ, highest on a scale; compare box plots on the same scale.
Histograms: frequency density = frequency ÷ class width, and bar area gives frequency.
🏆
Mini-lesson complete!
⭐⭐⭐
You've worked through Statistics for OCR GCSE Maths (J560). 🎉
Mission 1Can asking 1,000 people tell you what a whole country thinks?
Mission 2Same data, two headlines: "soaring" and "flat". How?
Mission 3A firm's average pay is £60,000, yet 9 in 10 staff earn £25,000. How?
Mission 4Ice-cream sales and sunburn rise together. Does ice cream cause it?
Mission 5Two classes have the same median mark. Were their results the same?