This mini-lesson covers the Geometry & Measures strand of OCR GCSE Maths (J560): angles, polygons, Pythagoras, trigonometry (SOHCAHTOA), area & volume, transformations, bearings, plus the Higher-tier topics of circle theorems and vectors.
Right-angled triangles unlock Pythagoras and trigonometry — the heart of this strand.
Work through each screen, answer the questions as you go (most are calculations) and collect ⭐ stars. Press Start when you're ready.
Angle facts
Angles on lines & around points
The three angle facts you use most often:
on a line = 180° · around a point = 360°and angles in a triangle add to 180° · angles in a quadrilateral add to 360°
Here x + 130° = 180°, so x = 50°.
Worked example
Three angles meet at a point: 120°, x and 100°.
They must total 360°: 120 + 100 = 220
x = 360 − 220 = 140°
Common slip: mixing up 180° (on a straight line) with 360° (all the way around a point). Draw the diagram and check which rule the angles sit on.
Calculate
Your turn — angles on a line
1Two angles sit on a straight line. One of them is 130°. Work out the other angle, in degrees.
°
Hint: angles on a straight line add to 180°, so 180 − 130.
Parallel lines
Parallel lines & around a point
When a straight line crosses parallel lines, equal angles appear in a pattern:
Corresponding angles (an "F" shape) are equal.
Alternate angles (a "Z" shape) are equal.
Co-interior angles (a "C" shape) add to 180°.
Alternate ("Z") angles are equal on parallel lines.
Watch out: these rules only work when the lines are parallel (shown by matching arrows). Without the arrows you can't assume the angles are equal.
Calculate
Your turn — angles around a point
2Three angles meet at a point and fill the whole turn: 120°, 150° and x. Work out x, in degrees.
°
Hint: angles around a point add to 360°. 360 − 120 − 150.
Polygons
Interior & exterior angles
For any polygon with n sides:
interior sum = (n − 2) × 180°each exterior angle of a regular polygon = 360° ÷ n · interior + exterior = 180°
A regular pentagon: (5 − 2) × 180 = 540°, so each interior angle = 540 ÷ 5 = 108°.
Worked example
Find each exterior angle of a regular hexagon (6 sides).
Exterior angles of any polygon add to 360°.
Regular, so each = 360 ÷ 6 = 60°
Key fact: the exterior angles of any polygon always add to 360°. For a regular polygon just divide 360 by the number of sides.
Quick check
Exterior angle of a hexagon
?Work out the size of one exterior angle of a regular hexagon (6 sides).
Calculate
Your turn — interior angle sum
3Work out the sum of the interior angles of a pentagon (5 sides), in degrees.
°
Hint: use (n − 2) × 180 with n = 5, so 3 × 180.
Pythagoras
Pythagoras' theorem
In a right-angled triangle, the square on the longest side (the hypotenuse) equals the sum of the squares on the other two sides:
a² + b² = c²c is always the hypotenuse — the side opposite the right angle
Legs 6 and 8: c² = 6² + 8² = 36 + 64 = 100, so c = 10.
Worked example
Legs 5 and 12. Find the hypotenuse.
c² = 5² + 12² = 25 + 144 = 169
c = √169 = 13
Common slip: to find a shorter side you subtract (c² − a²), not add. Only add when you're hunting the hypotenuse.
Calculate
Your turn — find the hypotenuse
4A right-angled triangle has legs of 6 cm and 8 cm. Work out the length of the hypotenuse, in cm.
cm
Hint: c² = 6² + 8² = 36 + 64 = 100, then take the square root.
Trigonometry
Trigonometry — SOHCAHTOA
In a right-angled triangle the three trig ratios link an angle θ to the sides opposite, adjacent and hypotenuse:
SOH · CAH · TOAsin θ = O ÷ H · cos θ = A ÷ H · tan θ = O ÷ A
Angle 30°, hypotenuse 10: O = H × sin 30° = 10 × 0.5 = 5.
Worked example
Angle 30°, hypotenuse 10. Find the opposite side.
We have O and H → use SOH: sin 30° = O ÷ 10
O = 10 × sin 30° = 10 × 0.5 = 5
Learn the exact values: sin 30° = 0.5, cos 60° = 0.5, tan 45° = 1. These are worth memorising for non-calculator marks.
Calculate
Your turn — trigonometry
5A right-angled triangle has an angle of 30° and a hypotenuse of 10 cm. Work out the length of the side opposite the 30° angle, in cm. (sin 30° = 0.5)
Area is measured in square units (cm²); volume in cubic units (cm³). The most-used formulae:
triangle = ½ × b × h · circle = π r²cuboid volume = length × width × height · circumference = π × diameter
Volume of a cuboid = length × width × height = 4 × 3 × 2 = 24 cm³.
Worked example
Triangle with base 10 cm and height 6 cm.
Area = ½ × base × height = ½ × 10 × 6
= 30 cm²
Watch the height: for a triangle use the perpendicular height (straight up from the base), not a slanted side.
Quick check
Area of a triangle
?A triangle has a base of 10 cm and a perpendicular height of 6 cm. What is its area?
Calculate
Your turn — volume of a cuboid
6A cuboid has dimensions 2 cm by 3 cm by 4 cm. Work out its volume, in cm³.
cm³
Hint: volume of a cuboid = length × width × height = 2 × 3 × 4.
Match game
Setup ⇄ formula
Tap a shape or ratio on the left, then its matching formula on the right.
Transformations
Transformations
Four ways to move a shape on a grid. Only one changes the shape's size:
Translation — slide it; describe with a column vector.
Reflection — flip it in a mirror line.
Rotation — turn it about a centre (angle + direction).
Enlargement — resize by a scale factor from a centre.
Translation, reflection and rotation keep the shape congruent (same size). Only enlargement changes size.
Remember: translation, reflection and rotation all produce a congruent image. An enlargement produces a similar shape (same angles, scaled lengths).
Bearings
Bearings
A bearing is a direction measured clockwise from North, always written with three figures (e.g. 070°, not 70°).
back bearing = bearing ± 180°add 180° if the bearing is under 180°; subtract 180° if it is 180° or more
The bearing of B from A here is 070°.
Worked example
The bearing of B from A is 070°. Find the bearing of A from B (the back bearing).
070° is under 180°, so add 180°: 070 + 180
= 250°
Three figures always: write a bearing of 70 degrees as 070°. A missing leading zero loses marks in exams.
Quick check
Back bearing
?The bearing of B from A is 070°. What is the bearing of A from B?
Circle theorems · Higher only
Circle theorems (Higher tier)
The circle theorems relate angles made by chords, radii and tangents. Three you meet most:
Angle at the centre = twice the angle at the circumference (same arc).
Angle in a semicircle is 90°.
A tangent meets a radius at 90°.
The angle at the centre (2x) is twice the angle at the circumference (x) from the same arc.
Higher only: circle theorems are on the Higher tier of J560. Always state the theorem you used to earn the reasoning mark.
Vectors · Higher only
Vectors (Higher tier)
A vector has both size and direction, written as a column vector — top number is movement across, bottom is up/down:
(3 over 2) means 3 right, 2 upadd vectors by adding the tops together and the bottoms together
Worked example
Add the vectors (3 over 2) and (1 over 4).
Tops: 3 + 1 = 4. Bottoms: 2 + 4 = 6.
Result = (4 over 6)
Higher only: vector geometry (and proofs using vectors) sits on the Higher tier. A negative vector reverses the direction, e.g. −(3 over 2) = (−3 over −2).
Sort it
Acute or obtuse?
An acute angle is less than 90°; an obtuse angle is between 90° and 180°. Tap an angle, then tap the box it belongs in.
◿ Acute (<90°)
◔ Obtuse (>90°)
Recap
The whole Geometry & Measures strand
Angles: on a line = 180°, around a point = 360°; parallel-line rules (corresponding, alternate, co-interior).
Polygons: interior sum = (n − 2) × 180°; exterior angles add to 360°.
Pythagoras: a² + b² = c² for right-angled triangles.
Trigonometry: SOHCAHTOA links an angle to opposite, adjacent & hypotenuse.
Area & volume: triangle = ½bh, circle = πr², cuboid = l×w×h.
Bearings: clockwise from North, three figures; back bearing ± 180°.
Higher only: circle theorems & vectors.
You've covered the Geometry & Measures strand of OCR GCSE Maths (J560) — Foundation content plus the Higher-tier circle theorems and vectors. Press Finish to see your score.
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