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OCR GCSE Maths (J560) · Probability
Mini-Lesson

Probability

This mini-lesson covers the Probability strand of OCR GCSE Maths (J560): the probability scale, sample space, relative & expected frequency, mutually exclusive and independent events, Venn diagrams, and the Higher-tier topics of tree diagrams and conditional probability.

0 ¼ ½ ¾ 1 impossible even chance certain
Every probability lives on this scale: 0 = impossible, 1 = certain, ½ = an even chance.

Work through each screen, answer the questions as you go (most are calculations) and collect ⭐ stars. Press Start when you're ready.

The probability scale

Measuring how likely

A probability measures how likely an event is. It is always a number between 0 and 1 (which you can also write as a fraction, decimal or percentage):

P(event) = successful outcomes ÷ total outcomesfor equally likely outcomes — e.g. a fair die or a well-shuffled pack
Worked example

A fair six-sided die is rolled. What is P(rolling an even number)?

Even numbers on the die: 2, 4, 6 → that is 3 successful outcomes.

Total outcomes = 6, so P(even) = 3/6 = 0.5

Key fact: the probabilities of all possible outcomes add up to 1. That means P(not A) = 1 − P(A).

Calculate

Your turn — a fair die

1A fair six-sided die is rolled. Work out P(rolling an even number). Give your answer as a decimal.
Hint: the even numbers are 2, 4 and 6, so 3 out of 6.
The complement rule

The probability of "not" happening

Because all the probabilities of an experiment add to 1, the chance of an event not happening is whatever is left over:

P(not A) = 1 − P(A)the event and its complement always add to 1
Worked example

The probability it rains tomorrow is P(rain) = 0.3.

P(no rain) = 1 − 0.3 = 0.7

Common slip: "not A" does not mean "half". It means everything else. If P(A) = 0.3, then P(not A) = 0.7, not 0.5.

Calculate

Your turn — the complement

2The probability that a bus is late is P(late) = 0.3. Work out P(the bus is not late). Give your answer as a decimal.
Hint: P(not late) = 1 − 0.3.
Sample space

Listing the sample space

The sample space is the set of all possible outcomes. Listing them (or drawing a two-way table) lets you count outcomes reliably:

5 red 3 blue 2 green 10 balls in total
A bag holds 5 red, 3 blue and 2 green balls — 10 outcomes in the sample space.
Worked example

One ball is taken at random. P(red) = 5/10 = 0.5; P(green) = 2/10 = 0.2.

P(not blue) = 1 − 3/10 = 7/10 = 0.7.

Tip: once you know the total (here 10), every single-pick probability is just "how many of that colour ÷ 10".

Calculate

Your turn — the bag of balls

3The bag holds 5 red, 3 blue and 2 green balls (10 in total). One ball is taken at random. Work out P(not blue). Give your answer as a decimal.
Hint: 7 of the 10 balls are not blue (5 red + 2 green).
Mutually exclusive events

Mutually exclusive events

Two events are mutually exclusive if they cannot both happen at the same time — for example, rolling a 2 and rolling a 5 on a single die. For such events you can simply add the probabilities:

P(A or B) = P(A) + P(B)only when A and B cannot happen together
Worked example

A spinner lands on red with probability 0.2 and on blue with probability 0.5. These can't both happen on one spin.

P(red or blue) = 0.2 + 0.5 = 0.7

Watch out: you can only add probabilities when the events are mutually exclusive. If events can overlap, adding double-counts the overlap — use a Venn diagram instead.

Quick check

Spot the mutually exclusive pair

?For a single roll of one fair die, which pair of events is mutually exclusive?
Calculate

Your turn — adding probabilities

4Events A and B are mutually exclusive with P(A) = 0.2 and P(B) = 0.5. Work out P(A or B). Give your answer as a decimal.
Hint: they can't happen together, so add: 0.2 + 0.5.
Relative & expected frequency

Relative frequency (experimental probability)

When outcomes are not equally likely (a biased spinner, a drawing pin), you estimate probability by experiment. This is the relative frequency:

relative frequency = number of times it happened ÷ number of trialsthe more trials, the closer this gets to the true probability
30 reds ÷ 200 spins 30 ÷ 200 = 0.15
A spinner landing on red 30 times in 200 spins gives a relative frequency of 0.15.

Expected frequency works the other way: if you know a probability, expected number = P(event) × number of trials. E.g. P(red) = 0.2 over 50 spins gives 0.2 × 50 = 10 reds.

Calculate

Your turn — relative frequency

5A spinner is spun 200 times and lands on red 30 times. Work out the relative frequency of landing on red. Give your answer as a decimal.
Hint: relative frequency = 30 ÷ 200.
Independent events

Independent events — the AND rule

Two events are independent if one happening does not change the probability of the other — like two separate coin flips. To find the chance of both happening, multiply:

P(A and B) = P(A) × P(B)only when A and B are independent
Worked example

A fair coin is flipped twice. What is P(heads then heads)?

Each flip: P(heads) = 0.5, and the flips are independent.

P(H and H) = 0.5 × 0.5 = 0.25

Remember: "or" (mutually exclusive) means add; "and" (independent) means multiply. Mixing them up is the most common probability error.

Quick check

And or or?

?A fair coin is flipped and a fair die is rolled. Which calculation gives P(heads and a 6)?
Calculate

Your turn — two coins

6A fair coin is flipped twice. Work out P(heads on the first flip and heads on the second flip). Give your answer as a decimal.
Hint: the flips are independent, so 0.5 × 0.5.
Match game

Event ⇄ probability

Tap an event on the left, then its matching probability on the right. (The bag has 5 red, 3 blue and 2 green balls.)

Venn diagrams

Venn diagrams & overlapping events

When two events can overlap, a Venn diagram keeps the counts straight. Each region is counted exactly once:

French Spanish 8 5 7 4 (neither) both
24 students in total. 5 study both languages; that overlap is counted once, not twice.

Reading a Venn diagram: P(studies French) uses everyone inside the French circle = (8 + 5) ÷ 24 = 13/24. The overlap belongs to both circles.

Tree diagrams · Higher

Tree diagrams (Higher tier)

A tree diagram shows the outcomes of two or more stages. You multiply along the branches, then add the results of the paths you want:

0.5 0.5 H T 0.50.5 0.50.5 HH → 0.25 HT → 0.25 TH → 0.25 TT → 0.25
Two coin flips. Each path multiplies: 0.5 × 0.5 = 0.25. The four paths add to 1.

Higher only — dependent events: if the first outcome changes the second (e.g. balls taken without replacement), the probabilities on the second set of branches change. That is conditional probability.

Conditional probability · Higher

Conditional probability (Higher tier)

A conditional probability is the chance of B given that A has already happened, written P(B | A). This matters when items are not replaced:

P(A and B) = P(A) × P(B | A)the second probability depends on the first outcome
Worked example

A bag has 5 red and 5 blue balls. Two are taken without replacement. P(both red)?

First red: 5/10. Now 4 red of 9 remain, so second red: 4/9.

P(both red) = 5/10 × 4/9 = 20/90 = 2/9

Higher only: tree diagrams for events without replacement and conditional probability are on the Higher tier of J560. The key is that the total and the counts drop by one after the first pick.

Quick check

Without replacement

?A bag has 4 red and 6 blue balls. One red ball is taken out and kept. A second ball is now drawn. What is P(second ball is red)?
Sort it

Add or multiply?

Sort each scenario by the rule you'd use. Mutually exclusive "or" events → add. Independent "and" events → multiply. Tap a card, then the box it belongs in.

➕ Mutually exclusive (add)

✖️ Independent (multiply)

Recap

The whole Probability strand

The scale: every probability is between 0 (impossible) and 1 (certain); all outcomes add to 1.

Complement: P(not A) = 1 − P(A).

Sample space: list all outcomes; P = successes ÷ total.

Mutually exclusive ("or"): P(A or B) = P(A) + P(B) — add.

Independent ("and"): P(A and B) = P(A) × P(B) — multiply.

Frequency: relative frequency = successes ÷ trials; expected = P × trials.

Venn diagrams: handle overlapping events; count each region once.

Higher only: tree diagrams and conditional probability P(B | A) — for events without replacement.

You've covered the Probability strand of OCR GCSE Maths (J560) — Foundation content plus the Higher-tier tree diagrams and conditional probability. Press Finish to see your score.

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