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OCR A-level Mathematics A (H240) ยท 2.02 Data Presentation and Interpretation
Mini-Lesson

Data presentation

OCR section 2.02 asks you to present, summarise and above all interpret data: histograms, box plots, measures of location and spread, outliers, correlation and regression.

Diagrams Location & spread Correlation & regression the marks are in the interpretation, not the arithmetic

Questions here are often set in the context of OCR's pre-release large data set. Work through each screen, answer the questions as you go and collect ⭐ stars. Press Start when you're ready.

Data · histograms

Histograms and frequency density

A histogram is not a bar chart. The bars touch, the widths can differ, and the crucial rule is:

AREA = frequency   ⇒   frequency density = frequency ÷ class widththe vertical axis is frequency DENSITY, never frequency
Worked example

The class 20 ≤ x < 30 has frequency 45.

Class width = 30 − 20 = 10.

Frequency density = 45 ÷ 10 = 4.5.

Reading a histogram backwards: to find a frequency, compute area = frequency density × class width. And to estimate the frequency in part of a bar, assume the data is evenly spread across the class and take that fraction of the area.

Calculate

Your turn โ€” frequency density

1A histogram class 20 ≤ x < 30 has a frequency of 45. Find its frequency density.
Hint: frequency density = frequency ÷ class width = 45 ÷ 10.
Quick check

What does the bar mean?

?On a histogram with unequal class widths, what represents the frequency?
Data · location and spread

Measures of location and spread

  • Location: mean (uses every value; distorted by outliers), median (the middle; resistant to outliers), mode (most common).
  • Spread: range, interquartile range IQR = Q₃ − Q₁ (resistant to outliers), variance and standard deviation.
variance = (Σx²)/n − (mean)²   ·   standard deviation = √variancethe standard deviation has the same units as the data; the variance does not
Worked example

n = 10, Σx = 250, Σx² = 6500.

mean = 250/10 = 25.

variance = 6500/10 − 25² = 650 − 625 = 25.

standard deviation = √25 = 5.

A useful check: the variance can never be negative. If Σx²/n comes out less than the mean squared, you have made an arithmetic error.

Calculate

Your turn โ€” standard deviation

2For a data set with n = 10, Σx = 250 and Σx² = 6500, find the standard deviation.
Hint: mean = 25. Variance = 6500/10 − 25² = 650 − 625 = 25. Then take the square root.
Data · outliers

Outliers โ€” two rules

An outlier is a value that is far from the rest. OCR uses two definitions, and the question will tell you which:

Rule 1: below Q₁ − 1.5 × IQR, or above Q₃ + 1.5 × IQRRule 2: more than 2 standard deviations from the mean, i.e. outside mean ยฑ 2sd
Worked example โ€” the IQR rule

Q₁ = 14, Q₃ = 26. So IQR = 26 − 14 = 12, and 1.5 × IQR = 18.

Upper fence = Q₃ + 18 = 26 + 18 = 44.

Lower fence = Q₁ − 18 = 14 − 18 = −4.

So any value above 44 or below −4 is an outlier. If the data cannot be negative (a time, a length), the lower fence catches nothing โ€” perfectly normal.

Worked example โ€” the mean plus or minus 2sd rule

mean = 50, sd = 6. Accepted range = 50 ± 2(6) = 50 ± 12, i.e. 38 to 62.

Anything above 62 or below 38 is flagged as an outlier.

Do not just delete outliers. An outlier may be a genuine extreme value or a recording error. OCR wants you to identify it, then comment on whether it should be removed and why.

Calculate

Your turn โ€” upper fence

3A data set has Q₁ = 14 and Q₃ = 26. Using the 1.5 × IQR rule, find the value above which a data point is an outlier.
Hint: IQR = 26 − 14 = 12, so 1.5 × IQR = 18. Upper fence = Q₃ + 18 = 26 + 18.
Calculate

Your turn โ€” lower fence

4Same data set (Q₁ = 14, Q₃ = 26). Using the 1.5 × IQR rule, find the value below which a data point is an outlier.
Hint: lower fence = Q₁ − 1.5 × IQR = 14 − 18. The answer is negative.
Calculate

Your turn โ€” the 2sd rule

5A data set has mean 50 and standard deviation 6. Using the mean ± 2 standard deviations rule, find the upper limit of the accepted (non-outlier) range.
Hint: 50 + 2 × 6 = 50 + 12.
Data · box plots

Box plots and skew

A box plot displays five numbers: minimum, Q₁, median, Q₃, maximum โ€” with outliers marked separately as crosses.

The shape reveals the skew:

  • Symmetric โ€” the median sits centrally in the box and the whiskers are of similar length.
  • Positive skew โ€” the median is closer to Q₁, and the upper whisker is longer. The tail stretches to the right. (Typically mean > median.)
  • Negative skew โ€” the median is closer to Q₃, and the lower whisker is longer.

Comparing two box plots earns marks for one comment on location and one on spread, both in context: “Group A has a higher median (so was typically faster) and a smaller IQR (so was more consistent).”

Quick check

Reading the skew

?On a box plot the median lies much closer to Q₁ than to Q₃, and the upper whisker is long. The distribution is:
Data · correlation

Correlation and regression

A scatter diagram shows two variables together. The product moment correlation coefficient r measures the strength of the linear relationship:

−1 ≤ r ≤ 1r near +1: strong positive linear ยท r near โˆ’1: strong negative linear ยท r near 0: no LINEAR correlation

The regression line of y on x, y = a + bx, is the best-fit line for predicting y from x. Here x is the explanatory (independent) variable and y the response (dependent) variable.

Worked example โ€” a regression line

Data collected for x between 2 and 12 gives the regression line y = 3.2 + 1.8x.

Predicting at x = 5 (inside the data range): y = 3.2 + 1.8(5) = 12.2. This is interpolation and is reliable.

Predicting at x = 40 (far outside the range): y = 3.2 + 72 = 75.2. This is extrapolation and is unreliable โ€” you have no evidence the linear pattern continues that far.

Interpreting b: for every 1 unit increase in x, y increases by about 1.8 units.

Correlation is not causation. Ice cream sales correlate with drownings; neither causes the other. Both are driven by a third variable โ€” hot weather. OCR loves this point.

Quick check

Interpolation or extrapolation?

?Data was collected for x between 2 and 12, giving the regression line y = 3.2 + 1.8x. A student uses it to predict y when x = 40. What is the problem?
Quick check

Interpreting r

?A data set has a product moment correlation coefficient of r = −0.92. This indicates:
Sort it

Location, spread or neither?

Tap a statistic, then tap what it measures.

๐Ÿ“ Location

โ†”๏ธ Spread

โŒ Neither

Match it

Definitions

Tap a term on the left, then its definition or formula.

Term
Definition
Recap

The big ideas to know

Histograms: area = frequency; height = frequency density = frequency ÷ class width

Location: mean (uses all data, distorted by outliers), median (resistant), mode

Spread: IQR = Q₃ − Q₁; variance = Σx²/n − mean²; sd = √variance

Outliers: 1.5 × IQR beyond the quartiles, or outside mean ± 2sd โ€” identify, then comment

Box plots: median near Q₁ ⇒ positive skew; compare location and spread in context

Correlation: −1 ≤ r ≤ 1; measures linear association only โ€” and never proves causation

Regression: interpolation is reliable; extrapolation is not

That is OCR 2.02 โ€” and it is where the pre-release large data set most often appears. Press Finish to see your score.

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