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Edexcel International GCSE Physics (4PH1) · Section 5 — Solids, liquids and gases
Mini-Lesson

Solids, Liquids & Gases

This mini-lesson covers the whole of 4PH1 Section 5: density and pressure, pressure in a liquid column, change of state and the particle model, and the kinetic theory of gases with the Kelvin scale and the gas laws.

Make a guess: why is a litre of steel so heavy?

  1. Mission 1Why is a litre of steel so heavy?
  2. Mission 2Same push, so why does only one knife cut?
  3. Mission 3Why does iron warm up more than water?
  4. Mission 4Why does squashed air push back harder?

Work through each screen, answer the questions as you go (some wordy, some calculations) and collect ⭐ stars. Press Start when you're ready.

Spec 5.1 / 5.2P · Units

The units you must use

Section 5 expects you to work confidently in these SI units:

  • °C degree Celsius and K kelvin — temperature
  • kg kilogram — mass; m, m², m³ — length, area, volume
  • kg/m³ — density; Pa pascal — pressure; N newton — force
  • J joule — energy; m/s and m/s² — speed and acceleration

Paper 2 only (5.2P): for specific heat capacity you also use J/kg °C (joules per kilogram per degree Celsius).

Spec 5.3–5.4 · Density

Density: how tightly packed

Density tells you how much mass is squeezed into each cubic metre of a material:

ρ = m / Vdensity (kg/m³) = mass (kg) ÷ volume (m³)

Measuring it (5.4 practical): find the mass on a balance. For a regular solid, measure its sides and calculate the volume; for an irregular solid, use a displacement can or measuring cylinder; for a liquid, pour it into a measuring cylinder. Then divide.

Worked example

A metal block has mass 240 g (= 0.24 kg) and volume 0.00003 m³.

ρ = 0.24 ÷ 0.00003 = 8000 kg/m³ (about the density of steel).

Calculate

Your turn — density

1An aluminium block has a mass of 5.4 kg and a volume of 0.002 m³. Calculate its density.
kg/m³
Hint: ρ = m ÷ V = 5.4 ÷ 0.002.
Mission 1 check

Why is a litre of steel so heavy?

?A steel block and a wooden block each have a volume of 10 cm³. The steel block's mass is 78 g. The wooden block's mass is 6 g. Which statement explains the difference?
Mission 2 of 4

Same push, so why does only one knife cut?

Make a guess: why does only the sharp knife cut?

Spec 5.5–5.6 · Pressure

Pressure: force spread over area

Pressure is the force acting on each square metre of a surface:

p = F / Apressure (Pa) = force (N) ÷ area (m²)

The same force over a smaller area gives a bigger pressure — which is why a sharp knife or a drawing pin works.

Acts in all directions (5.6): at any point in a gas or a liquid at rest, the pressure pushes equally in every direction — up, down and sideways — not just downwards.

Worked example

A box pushes down with a force of 600 N over an area of 0.5 m².

p = 600 ÷ 0.5 = 1200 Pa

Calculate

Your turn — pressure

2A crate exerts a force of 900 N on the floor through a base of area 0.3 m². Calculate the pressure it exerts.
Pa
Hint: p = F ÷ A = 900 ÷ 0.3.
Mission 2 check

Same push, so why does only one knife cut?

?A woman walks across a soft lawn in flat shoes, then in stiletto heels. Her weight is the same both times, but the stilettos sink into the grass. Why?
Spec 5.7 · Pressure in a liquid

Pressure grows with depth

Dive deeper and the weight of water above you grows, so the pressure difference increases:

p = h × ρ × gpressure difference (Pa) = height/depth (m) × density (kg/m³) × g (N/kg)
surface small pbigger pbiggest p depth h
Longer arrows = larger pressure. Only the depth and the liquid's density matter — not the shape or width of the container.

Watch out: pressure in a liquid depends on depth and density, not the shape of the container or how much liquid there is in total. A narrow tube and a wide tank give the same pressure at the same depth.

Worked example

Depth 2 m, water density 1000 kg/m³, g = 10 N/kg.

p = 2 × 1000 × 10 = 20 000 Pa

Calculate

Your turn — depth pressure

3A diver is 5 m below the surface of seawater of density 1030 kg/m³. Using g = 10 N/kg, calculate the pressure difference due to the water.
Pa
Hint: p = h × ρ × g = 5 × 1030 × 10.
Mission 3 of 4

Why does iron warm up more than water?

Make a guess: why does iron warm up more than water?

Spec 5.8P–5.10P · Paper 2 only

Three states, three arrangements

The kinetic theory explains the states by how the particles are arranged and moving:

SOLIDLIQUIDGAS regular, fixed;vibrate in place touching, random;slide past far apart;fast, random
Solid: regular, fixed, only vibrating. Liquid: close but mobile. Gas: widely spaced, fast and random.

Heating (5.8P–5.9P): heating raises the energy stored in the particles, so the temperature rises or the state changes — a solid melts, then the liquid evaporates/boils to a gas. During a change of state the temperature stays constant while the forces between particles are overcome.

Quick check · Paper 2 only

Which state?

?In which state are the particles far apart, moving fast in random directions, with almost no forces between them?
Spec 5.12P–5.14P · Paper 2 only

Specific heat capacity

The specific heat capacity c is the energy needed to change the temperature of 1 kg by 1 °C:

ΔQ = m × c × ΔTchange in thermal energy (J) = mass (kg) × s.h.c. (J/kg °C) × temperature change (°C)

Water has a high c (4200 J/kg °C), so it heats and cools slowly — useful in radiators and for the climate near the sea.

Practical (5.14P): heat a known mass with an electric heater, measure the energy supplied and the temperature rise, then find c = ΔQ ÷ (m × ΔT). A temperature–time graph (5.11P) shows the flat region while a substance changes state.

Worked example

Heating 0.5 kg of water (c = 4200) by 30 °C:

ΔQ = 0.5 × 4200 × 30 = 63 000 J (63 kJ)

Calculate · Paper 2 only

Your turn — thermal energy

4How much thermal energy is needed to raise the temperature of 3 kg of water (c = 4200 J/kg °C) by 20 °C?
J
Hint: ΔQ = m × c × ΔT = 3 × 4200 × 20.
Mission 3 check

Why does iron warm up more than water?

?A student gives 1 kg of cooking oil and 1 kg of water the same amount of energy. The oil's temperature rises by twice as much. What is the best explanation?
Mission 4 of 4

Why does squashed air push back harder?

Make a guess: why does squashed air push back harder?

Spec 5.15 · Gas pressure

Where gas pressure comes from

Gas molecules have random motion. Each time one hits a wall it bounces off, exerting a tiny force. Huge numbers of collisions every second add up to a steady pressure:

red arrows: force of each hit on the wall many collisions every second → pressure
Dashed lines show molecules arriving at a wall; they rebound, and each hit pushes on the wall (red arrows). The total effect of all these impacts is gas pressure.

Watch out: gas pressure is not the gas "pressing because it is heavy" — it is the result of countless molecular collisions with the container walls.

Sort it

What raises the pressure?

For a fixed amount of gas, tap how the molecular collisions explain each change.

Spec 5.16–5.17 · The Kelvin scale

Absolute zero and kelvin

Cool a gas and its molecules slow down. At −273 °C they have the least possible energy — you cannot go colder. This is absolute zero, the start of the Kelvin scale:

T (K) = θ (°C) + 273θ (°C) = T (K) − 273
−273 °C0 °C100 °C 0 K273 K373 K °C + 273 = KK − 273 = °C
Drawn to scale: the two scales have the same size of degree — they are just shifted by 273.

Absolute zero = 0 K = −273 °C. There is no such thing as a negative kelvin temperature.

Calculate

Your turn — convert to kelvin

5A gas is at a temperature of 27 °C. Convert this temperature into kelvin.
K
Hint: T (K) = θ (°C) + 273 = 27 + 273.
Spec 5.18–5.19 · Temperature & energy

Hotter means faster

Raising the temperature gives molecules more energy, so on average they move faster. In fact:

Kelvin temperature ∝ average kinetic energydouble the Kelvin temperature → double the average kinetic energy of the molecules

This is why temperature is measured from absolute zero: at 0 K the average kinetic energy is (as near as possible) zero, so it makes sense to say the energy is proportional to the Kelvin temperature — that statement would fail with the Celsius scale.

Link to pressure: faster molecules hit the walls harder and more often, so for a fixed volume a higher temperature gives a higher pressure.

Quick check

Temperature and motion

?The Kelvin temperature of a fixed mass of gas is doubled. What happens to the average kinetic energy of its molecules?
Spec 5.20 / 5.22 · p–V at constant T

Squeeze it: pressure ∝ 1/volume

For a fixed mass of gas at constant temperature, squeezing it into a smaller volume packs the same molecules into less space, so they hit the walls more often and the pressure rises:

p₁V₁ = p₂V₂pressure × volume stays constant when temperature is fixed
pressure p volume V small V, big p big V, small p constant temperature
The curve falls away: halve the volume and the pressure doubles. p and V are inversely proportional.
Worked example

Gas at 100 000 Pa in 0.6 m³ is compressed to 0.2 m³ at constant temperature.

p₂ = p₁V₁ ÷ V₂ = (100 000 × 0.6) ÷ 0.2 = 300 000 Pa

Calculate

Your turn — Boyle's law

6A fixed mass of gas at 200 000 Pa occupies 0.4 m³. At constant temperature it is compressed to 0.1 m³. Calculate the new pressure.
Pa
Hint: p₂ = (p₁ × V₁) ÷ V₂ = (200 000 × 0.4) ÷ 0.1.
Spec 5.20 / 5.21 · p–T at constant V

Heat it: pressure ∝ Kelvin temperature

For a fixed mass of gas at constant volume, raising the Kelvin temperature makes the molecules hit the walls harder and more often, so the pressure rises in proportion:

p₁ / T₁ = p₂ / T₂T must be the temperature in KELVIN, not °C

Watch out — use kelvin! The gas laws only work with Kelvin temperatures. Putting °C into p₁/T₁ = p₂/T₂ gives the wrong answer (and dividing by 0 °C is meaningless). Always convert first.

Worked example

Gas at 100 000 Pa and 300 K is heated to 450 K at constant volume.

p₂ = p₁ × T₂ ÷ T₁ = 100 000 × 450 ÷ 300 = 150 000 Pa

Calculate

Your turn — the pressure law

7A sealed rigid can of gas is at 120 000 Pa and 250 K. It is warmed to 400 K with the volume unchanged. Calculate the new pressure.
Pa
Hint: p₂ = p₁ × T₂ ÷ T₁ = 120 000 × 400 ÷ 250.
Quick check

The classic trap

?A student uses p₁/T₁ = p₂/T₂ but puts the temperatures in °C instead of kelvin. What is wrong?
Mission 4 check

Why does squashed air push back harder?

?A heavy box is placed slowly on a sealed football. The ball's volume falls, but the temperature of the air inside stays the same. Why does the air pressure inside rise?
Match them

Equation to job

Tap an equation, then tap what it is used for.

Recap

The equations to know

Density: ρ = m / V

Pressure: p = F / A

Pressure in a liquid: p = h × ρ × g

Thermal energy (P): ΔQ = m × c × ΔT

°C → K: T = θ + 273 (absolute zero = 0 K = −273 °C)

Boyle's law: p₁V₁ = p₂V₂ (constant T)

Pressure law: p₁/T₁ = p₂/T₂ (constant V, use kelvin!)

You've covered the key ideas in 4PH1 Section 5 — units, density & pressure, change of state, and ideal gas molecules. Press Finish to see your score.

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