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Edexcel International GCSE Physics (4PH1) · Section 2 — Electricity
Mini-Lesson

Electricity

This mini-lesson walks you through the whole of Edexcel iGCSE Physics Section 2 — Electricity: the units, mains electricity and safety, power and energy equations, charge and current, the rules for series and parallel circuits, resistance and I–V graphs, and static electricity.

+ cell lamp conventional current I
A cell pushes a current around the circuit, transferring energy to the lamp. Conventional current flows from + to .

Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Some sub-topics are Paper-2 only and are flagged. Press Start when you're ready.

2.1 · Units

The units you must use

Section 2 is built on a small set of SI units. Get these straight first — examiners drop easy marks for wrong units.

Aampere · current Ccoulomb · charge Vvolt · voltage Ωohm · resistance Wwatt · power Jjoule · energy ssecond · time
The seven Section 2 units: ampere (A), coulomb (C), volt (V), ohm (Ω), watt (W), joule (J), second (s).

Energy at home is also metered in kilowatt-hours (kWh) — a much bigger unit than the joule, handy for billing. 1 kWh is the energy a 1 kW device uses in 1 hour.

Quick check

Match the unit

?Which physical quantity is measured in coulombs (C)?
2.14–2.16 · Charge & current

Current is the flow of charge

Electric current is the rate of flow of charge. In a solid metal it is a flow of negatively charged electrons — but by convention we draw conventional current flowing from + to , the opposite way to the electrons.

Q = I × tcharge (C) = current (A) × time (s)
metal wire electrons drift this way (− to +) conventional current I (+ to −)
The electrons drift one way; the conventional current is defined the opposite way.
Worked example

A current of 3 A flows for 20 s.

Q = I × t = 3 × 20 = 60 C

Calculate

Your turn — charge

1A current of 0.5 A flows through a torch bulb for 120 s. Calculate the charge that passes.
C
Hint: Q = I × t = 0.5 × 120.
2.13, 2.20–2.21 · Voltage & resistance

Voltage, energy and resistance

Voltage (potential difference) is the energy transferred per unit charge. One volt is one joule per coulomb (1 V = 1 J/C).

E = Q × Venergy transferred (J) = charge (C) × voltage (V)

Resistance opposes the current. The key relationship links voltage, current and resistance:

V = I × Rvoltage (V) = current (A) × resistance (Ω)

Rearranging: R = V ÷ I and I = V ÷ R. The bigger the resistance, the smaller the current for the same voltage.

Worked example

A 12 V supply drives 0.4 A through a resistor.

R = V ÷ I = 12 ÷ 0.4 = 30 Ω

Calculate

Your turn — resistance

2A potential difference of 6 V drives a current of 0.25 A through a resistor. Calculate its resistance.
Ω
Hint: R = V ÷ I = 6 ÷ 0.25.
2.7, 2.17–2.19 · Series & parallel

Series vs parallel circuits

How components are connected changes how current and voltage behave. Here is a correct series circuit and a correct parallel circuit:

SERIES + switch A ammeter one path · same current everywhere PARALLEL cell V voltmeter (in parallel) branches share the supply · same voltage across each
An ammeter goes in series (in the line) to read current; a voltmeter goes in parallel (across a component) to read voltage.
  • Series: current is the same everywhere; the supply voltage is shared between components.
  • Parallel: the voltage across components in parallel is the same; current splits between branches and is conserved at a junction.
Quick check

Reading a series circuit

Misconception buster: current is not "used up" as it goes round. In a series circuit the same current passes through every component — it is conserved. It is the voltage that is shared out.

?Two identical lamps are in series with a cell. The ammeter near the cell reads 0.3 A. What does an ammeter placed between the two lamps read?
Analogy · the water circuit

Think of a water circuit

A circuit is hard to see, so picture water pumped round pipes:

pump = cell narrow pipe = resistor flow rate = current pump pressure = voltage · flow rate = current · narrow pipe = resistance
  • The pump is the cell — it raises the pressure (the voltage).
  • The flow rate of water is the current.
  • A narrow pipe is a resistor — it makes the water harder to push, so less flows.

Like all analogies it isn't perfect, but it makes V = I × R feel natural: more pressure → more flow; narrower pipe → less flow.

2.9, 2.12 · I–V characteristics

How current varies with voltage

Plotting current (y) against voltage (x) for a component gives its I–V characteristic. The shape tells you how it behaves:

I V fixed resistor straight line · ohmic I V filament lamp S-shaped · curve flattens I V diode one direction only
Resistor: straight line through the origin (constant resistance). Filament lamp: S-shaped — as it heats up its resistance rises, so the line curves and flattens. Diode: only conducts one way.

Why the lamp curves: as more current flows, the filament gets hotter, its resistance increases, so the current rises less steeply — the line bends over.

Quick check

Name that graph

?An I–V graph is a straight line passing through the origin. Which component is it, and what does it tell you?
2.10–2.11 · LDR & thermistor

Resistance that changes

Two components have a resistance that changes with their surroundings:

R light intensity LDR: more light → less R R temperature thermistor: hotter → less R
An LDR's resistance falls as light increases. A thermistor's resistance falls as temperature increases.

Remember the direction: for both, more of the input (light / heat) means lower resistance — useful in light sensors and temperature sensors. Lamps and LEDs can be used to show when a current is flowing.

Quick check

Sensing the dark

?A street-lamp circuit uses an LDR. As night falls and the light level drops, what happens to the LDR's resistance?
2.2, 2.6 · Mains electricity

Mains electricity & safety

Mains electricity is alternating current (a.c.) — it repeatedly changes direction. A cell or battery supplies direct current (d.c.), which flows one way only.

  • Earthing — a metal case is connected to earth, so a fault current flows safely to ground instead of through you.
  • Fuses & circuit breakers — break the circuit if the current gets too large.
  • Insulation & double insulation — plastic casing means no exposed metal can become live.

Misconception buster: a fuse protects the cable (and appliance) from too large a current — it does not protect you from a shock. If too much current flows, the thin fuse wire heats up and melts, breaking the circuit.

2.2 · The three-pin plug

Wiring a three-pin plug

Know the colours and where the fuse goes. The fuse is always fitted on the live wire.

earth green/yellow neutral blue fuse live brown cable grip
Live = brown (carries the fuse), Neutral = blue, Earth = green/yellow (longest pin, top). The fuse sits on the live wire.
Quick check

Plug colours & the fuse

?In a correctly wired three-pin plug, which wire carries the fuse, and what colour is it?
2.3–2.4 · Electrical power

Electrical power

A current in a resistor transfers energy and makes it warmer (useful in kettles and heaters). The power — the rate of transfer — is:

P = I × Vpower (W) = current (A) × voltage (V)

This is used to choose the right fuse: work out the normal current (I = P ÷ V) and pick a fuse rated just above it.

Worked example

A 230 V hairdryer has a power of 1150 W.

I = P ÷ V = 1150 ÷ 230 = 5 A → fit a 5 A or next-size-up fuse.

Calculate

Your turn — power

3An immersion heater draws a current of 9 A from the 230 V mains. Calculate its power.
W
Hint: P = I × V = 9 × 230.
2.5 · Energy & cost

Energy transferred & the cost

Over a time t, the energy transferred by an electrical device is:

E = I × V × tenergy (J) = current (A) × voltage (V) × time (s)

Since P = I × V, this is the same as E = P × t. For home bills we use kilowatt-hours (kWh):

energy (kWh) = power (kW) × time (hours)cost = energy (kWh) × price per kWh
Worked example

A 2 kW heater runs for 3 hours; electricity costs 30p per kWh.

Energy = 2 × 3 = 6 kWh → cost = 6 × 30 = 180p = £1.80

Calculate

Your turn — running cost

4A 0.5 kW television is on for 4 hours. Electricity costs 30p per kWh. Calculate the cost in pence.
p
Hint: energy = 0.5 × 4 = 2 kWh; cost = 2 × 30.
2.22P–2.26P · Static electricity · Paper 2 only

Static electricity

Rub two insulators together and electrons are transferred from one to the other by friction:

  • The material that gains electrons becomes negatively charged.
  • The material that loses electrons is left positively charged.
  • Like charges repel; unlike charges attract.
rod (gains e⁻ → −) cloth (loses e⁻ → +) electrons transfer by friction + + like → repel + unlike → attract
Charging is electron transfer. Like charges repel; unlike charges attract.

Misconception buster: objects are charged by moving electrons, never protons. Protons are locked in the nucleus and do not move. "Positive" just means a shortage of electrons.

Quick check · Paper 2

Charging by friction

?A plastic rod is rubbed with a cloth and becomes negatively charged. What has happened?
2.27P–2.28P · Dangers & uses · Paper 2 only

Static: dangers and uses

A build-up of static charge can discharge as a spark — sometimes dangerous, sometimes useful.

  • Danger — refuelling: when fuel flows through a pipe into an aircraft or tanker, friction builds up charge. A spark could ignite the fuel vapour, so the pipe and vehicle are earthed (bonded) to let the charge flow away safely.
  • Use — photocopiers & inkjet printers: charged toner or ink droplets are attracted to oppositely charged paper, placing the image exactly where it is needed.

Sort it out next: decide whether each scenario is a danger or a use of static electricity.

Sort it · Paper 2

Danger or use of static?

Tap a scenario, then tap the box it belongs in.

✅ Use of static

⚠️ Danger of static

Recap

The equations to know

Charge: Q = I × t

Voltage & resistance: V = I × R

Energy per charge: E = Q × V  (1 V = 1 J/C)

Electrical power: P = I × V

Energy transferred: E = I × V × t (= P × t)

Home energy: energy (kWh) = power (kW) × time (h); cost = kWh × price

You've covered all four parts of 4PH1 Section 2 — units, mains electricity, energy & voltage in circuits, and electric charge (static). Press Finish to see your score.

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