This mini-lesson walks you through the whole of Edexcel Topic 10 — Electricity and circuits: circuit symbols, what current, charge and potential difference really are, resistance and V = IR, series vs parallel, the I–V graphs, special components, the core practicals, electrical energy and power, and a.c./d.c. with UK mains safety.
A source of potential difference (the cell) drives a current of charge around the loop — energy is transferred to the lamp.
Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Press Start when you're ready.
Spec 10.2 · Circuit symbols
Reading a circuit diagram
Edexcel expects you to draw and use circuit diagrams with the standard symbols, using the conventions of positive (+) and negative (−) terminals. Conventional current flows from + to − outside the cell.
The Edexcel symbol set. An ammeter (A) goes in series to read current; a voltmeter (V) goes in parallel across a component to read p.d.
Watch out: the ammeter is connected in series with a component, but the voltmeter is connected in parallel with it. Mixing these up is one of the most common diagram errors.
Quick check
Which symbol?
?You want to measure the current through a lamp. Which meter do you use, and how is it connected?
Spec 10.8–10.9 · Current & charge
Current is the rate of flow of charge
An electric current is the rate of flow of charge. In a metal, that current is a flow of electrons. The more charge that passes a point each second, the bigger the current:
Q = I × tcharge (coulomb, C) = current (ampere, A) × time (second, s)
The water-circuit analogy helps: think of the cell as a pump, the current as the rate of water flow, and a resistor as a narrow section of pipe that holds the flow back.
Current is conserved — the same flow leaves the pump, passes the resistor and returns. The pump does not "use water up".
Watch out: current is not "used up" by components. The reading on an ammeter before a lamp equals the reading after it — what changes is the energy the charges carry, not how many there are.
Worked example
A current of 3 A flows for 20 s.
Q = I × t = 3 × 20 = 60 C
Calculate
Your turn — charge
1A current of 0.5 A flows through a torch bulb for 4 minutes. Calculate the charge that passes through it. (Remember: 4 min = 240 s.)
C
Hint: Q = I × t = 0.5 × 240.
Spec 10.4–10.6 · Potential difference
Potential difference moves energy
Potential difference (p.d., or voltage) is the energy transferred per unit charge passing through a component. So the volt is a joule per coulomb (1 V = 1 J/C):
E = Q × Venergy transferred (joule, J) = charge moved (coulomb, C) × potential difference (volt, V)
A voltmeter is connected in parallel across a component to measure the p.d. across it — the energy each coulomb of charge gives up as it passes through.
Watch out: p.d. is measured across a component (parallel), current is measured through it (series). Saying "the voltage through a resistor" is a giveaway error.
Worked example
15 C of charge passes through a lamp with 6 V across it.
E = Q × V = 15 × 6 = 90 J
Spec 10.12–10.13 · Resistance
Resistance and V = I R
Resistance opposes the flow of charge. The bigger the resistance, the smaller the current for a given p.d. The three are linked by:
V = I × Rpotential difference (volt, V) = current (ampere, A) × resistance (ohm, Ω)
You can change the current in a circuit with a variable resistor (a rheostat): increasing its resistance decreases the current.
Slide the variable resistor up (more resistance) and the current — so the lamp's brightness — falls.
Worked example
A 12 V supply drives 0.4 A through a resistor. Find R.
R = V ÷ I = 12 ÷ 0.4 = 30 Ω
Calculate
Your turn — resistance
2There is a potential difference of 9 V across a resistor and a current of 0.3 A through it. Calculate the resistance.
Ω
Hint: rearrange V = I R to R = V ÷ I = 9 ÷ 0.3.
Spec 10.3, 10.11, 10.14 · Series & parallel
Series vs parallel
In a series circuit there is one loop: the same current flows everywhere, and the p.d. of the supply is shared between components. In a parallel circuit components sit on separate branches: each gets the full supply p.d., and the branch currents add up to the total (current is conserved at a junction).
Adding a second loop in parallel gives the charge an extra path, so the overall resistance falls and more total current flows.
Series resistance rule: Rtotal = R1 + R2 + … Two resistors in parallel always give a combined resistance smaller than the smallest single one.
Calculate
Your turn — series resistance
3Three resistors of 12 Ω, 18 Ω and 20 Ω are connected in series. Calculate the total resistance of the combination.
Ω
Hint: in series the resistances simply add: 12 + 18 + 20.
Quick check
Current at a junction
?In a parallel circuit, 0.6 A flows in one branch and 0.9 A flows in the other. What is the current drawn from the cell?
Spec 10.18 · I–V characteristics
I–V graphs tell you the resistance
Plotting current against potential difference shows how a component behaves. A steeper line means a lower resistance (more current per volt).
A fixed resistor at constant temperature is ohmic (straight line through the origin). A filament lamp curves because heating raises its resistance. A diode only lets current flow one way.
Why the lamp curves: as current heats the filament, the metal ions vibrate more, electrons collide with them more often, so resistance increases — the line bends towards the p.d. axis.
Quick check
Reading the graph
?Which component gives a straight line through the origin on an I–V graph, showing constant resistance?
Spec 10.19–10.20 · Sensing components
LDRs and thermistors
Two components change their resistance in response to their surroundings:
LDR (light-dependent resistor): resistance falls as light intensity rises (bright = low R, dark = high R). Used in light sensors, e.g. automatic street lights and camera light meters.
Thermistor (NTC — negative temperature coefficient): resistance falls as temperature rises (hot = low R, cold = high R). Used in temperature sensors, e.g. thermostats and fire alarms.
Both curves slope down: more light (LDR) or more heat (thermistor) means less resistance.
Watch out: for GCSE Edexcel you only need the NTC thermistor — resistance decreases with rising temperature. Don't write the opposite.
Match
Component → behaviour
Tap a component, then tap its correct behaviour.
Spec 10.17 · Core practicals
The core practicals
Edexcel sets one named Core Practical on circuits. You construct electrical circuits to:
(a) investigate the relationship between p.d., current and resistance for a resistor and a filament lamp — varying the p.d., recording I and V, and plotting an I–V graph;
(b) test series and parallel circuits using resistors and filament lamps.
Ammeter in series reads the current; voltmeter in parallel reads the p.d. across the test component. The variable resistor lets you take many I–V readings.
Tip: take readings both ways round (reverse the cell) so you can plot the graph through negative values, and keep currents low so the component doesn't heat up between readings.
Spec 10.27–10.31 · Energy & power
Electrical energy and power
When charge flows through a component, energy is transferred. Over a time t:
E = I × V × tenergy transferred (J) = current (A) × p.d. (V) × time (s)
Power is the energy transferred per second (measured in watts). For any circuit device:
P = I × V and P = I² × Relectrical power (W) = current (A) × p.d. (V) = current² (A²) × resistance (Ω)
Heating effect: when there's a current in a resistor, energy is dissipated as thermal energy — caused by electrons colliding with the ions in the metal lattice. Useful in a kettle or toaster, wasteful in long cables.
Worked example
A heater draws 5 A from the 230 V mains.
P = I × V = 5 × 230 = 1150 W
Calculate
Your turn — power (P = I V)
4A hairdryer takes a current of 4 A from the 230 V UK mains. Calculate its power.
W
Hint: P = I × V = 4 × 230.
Calculate
Your turn — power (P = I²R)
5A current of 3 A flows through a 20 Ω heating element. Calculate the power dissipated using P = I² × R.
W
Hint: P = I² × R = 3² × 20 = 9 × 20.
Calculate
Your turn — energy transferred
6A 60 W lamp is left on for 120 s. Calculate the energy it transfers. (Use E = P × t.)
J
Hint: E = P × t = 60 × 120.
Spec 10.33–10.36 · a.c. vs d.c.
a.c. vs d.c.
In direct current (d.c.) the charge moves in one direction only. Cells and batteries supply d.c. In alternating current (a.c.) the movement of charge keeps changing direction. The UK mains supply is a.c.
The mains a.c. waveform reverses 50 times every second — its frequency is 50 Hz.Spec 10.36–10.41 · UK mains & safety
UK mains and the three-pin plug
The UK domestic supply is a.c. at about 230 V and 50 Hz. A three-pin plug has three wires you must know — their colours, their jobs and their potential differences:
Brown = live (~230 V), blue = neutral (≈ 0 V), green-and-yellow = earth (0 V). The fuse and switch are placed in the live wire.
The live wire carries the alternating supply (~230 V). The neutral completes the circuit and stays near 0 V.
The earth wire (0 V) is a safety wire: if a fault makes the metal case live, charge flows safely to earth.
A fuse (or circuit breaker) melts/trips if the current gets too big, cutting off the supply. It goes in the live wire so the appliance is isolated from the dangerous voltage.
Touching the live wire while connected to earth gives a large p.d. across you — a dangerous shock.
Sort it
Safe or dangerous?
Tap a statement, then tap the box it belongs in.
✅ Safe practice
⚠️ Dangerous
Quick check
Energy in appliances
?An electric drill is plugged into the mains. Which describes the main energy transfer while it is running?
Recap
The equations to know
Charge: Q = I × t
Energy & p.d.: E = Q × V
Resistance: V = I × R
Series resistance: Rtotal = R1 + R2 + …
Energy: E = I × V × t (and E = P × t)
Power: P = I × V and P = I² × R
You've covered the whole of Edexcel Topic 10 — symbols, current and charge, p.d. and resistance, series & parallel, I–V graphs, LDRs & thermistors, the core practicals, electrical energy & power, a.c./d.c. and mains safety. Press Finish to see your score.
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