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Edexcel GCSE Physics (1PH0) · Topic 15 — Forces and matter
Mini-Lesson

Forces and matter

This mini-lesson covers the whole of Edexcel Topic 15 — Forces and matter: how forces change the shape of objects (Hooke's law and the energy stored in a spring), and how pressure works in fluids — with depth, density, upthrust and the atmosphere.

force F pressure grows with depth

Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Some screens are marked HT only (higher tier) or separate science. Press Start when you're ready.

Changing shape (15.1–15.2)

It takes more than one force

To stretch, bend or compress an object you need more than one force acting on it. A single force would just make it accelerate away — to deform it, the object must be held or squeezed from at least two sides.

Edexcel splits the result of that deformation into two types:

  • Elastic deformation — the object returns to its original shape when the forces are removed (e.g. a spring inside its limit).
  • Inelastic (plastic) deformation — the object stays permanently changed after the forces are removed (e.g. an over-stretched spring, or bending a paperclip).

Analogy: a trampoline springs back (elastic); chewing gum stretched and let go stays stretched (inelastic).

Quick check

Elastic or inelastic?

?A metal coat-hanger is bent into a new shape and stays bent after you let go. How is this best described?
Equation · Hooke's law (15.3)

Hooke's law: force and extension

For a spring stretched elastically, the force is directly proportional to the extension:

F = k × xforce on a spring (N) = spring constant (N/m) × extension (m)

The spring constant k measures stiffness: a stiffer spring needs a bigger force for the same extension. Rearrange to find it: k = F ÷ x.

Watch out: x is the extension (how much longer the spring becomes), not its total length. Always subtract the original (natural) length first.

Worked example

A force of 12 N stretches a spring by 0.04 m.

k = F ÷ x = 12 ÷ 0.04 = 300 N/m

Calculate

Your turn — Hooke's law

1A spring has a spring constant of 25 N/m. It is stretched by an extension of 0.30 m. Calculate the force applied to the spring.
N
Hint: F = k × x = 25 × 0.30.
Force–extension graph · Core Practical (15.5–15.6)

The limit of proportionality

Plot force against extension and at first you get a straight line through the origin — a linear relationship where Hooke's law holds. Beyond the limit of proportionality the line bends: the relationship becomes non-linear and Hooke's law no longer applies.

extension x (m) force F (N) area = energy stored limit of proportionality linear (Hooke's law) non-linear
Core Practical: hang masses on a spring, measure the extension for each force, and plot F (y) against x (x). The straight part confirms Hooke's law; the gradient = the spring constant.

Watch out: Hooke's law only holds up to the limit of proportionality. Past it, equal extra forces give bigger and bigger extensions, so F = k×x can no longer be used.

Quick check

Reading the graph

?On a force–extension graph for a spring, what does the limit of proportionality mark?
Equation · work done (15.4)

Energy stored in a stretched spring

Stretching a spring does work, which is transferred to its elastic potential store. The energy stored is the area under the force–extension line (a triangle) — which gives:

E = ½ × k × x²energy stored in stretching (J) = ½ × spring constant (N/m) × (extension (m))²

Because the area under the straight line is a triangle, its area = ½ × base × height = ½ × x × F, and since F = k×x this rearranges to ½ k x².

Watch out: the extension is squared, so doubling the extension stores four times the energy. Use this equation only within the limit of proportionality.

Worked example

A spring (k = 200 N/m) is stretched by 0.10 m.

E = ½ × 200 × 0.10² = ½ × 200 × 0.01 = 1.0 J

Calculate

Your turn — energy stored

2A spring with spring constant 800 N/m is stretched by an extension of 0.05 m. Calculate the energy stored in the spring.
J
Hint: E = ½ × 800 × 0.05². (0.05² = 0.0025)
Sort it

Elastic or inelastic deformation?

Tap a situation, then tap the box it belongs in.

↩️ Elastic (springs back)

🔧 Inelastic (stays changed)

Equation · pressure (15.9–15.11 · separate science)

Pressure in fluids: p = F ÷ A

A fluid (a liquid or a gas) presses on every surface it touches. The force always acts normal (at right angles) to the surface. Pressure is that force spread over an area:

p = F ÷ Apressure (Pa) = force normal to surface (N) ÷ area (m²)

One pascal (Pa) is one newton per square metre. The smaller the area, the bigger the pressure for the same force — which is why a sharp knife or a drawing pin works.

Separate science: this and the rest of Topic 15 from here on (15.7–15.17) are Physics-only (not Combined Science).

Worked example

A force of 40 N acts on an area of 0.02 m².

p = F ÷ A = 40 ÷ 0.02 = 2000 Pa

Calculate

Your turn — pressure

3A box pushes down with a force of 600 N on the floor through a base area of 1.5 m². Calculate the pressure it exerts.
Pa
Hint: p = F ÷ A = 600 ÷ 1.5.
Pressure with depth (15.8, 15.12 · separate science)

Deeper means more pressure

Pressure in a fluid is partly atmospheric pressure (the air pushing down on top) and partly the weight of the fluid above. So the pressure in a liquid increases with depth — and is greater in a denser liquid, because a deeper or denser column weighs more.

deeper = higher pressure depth h
Water squirts hardest from the lowest hole — the pressure there is greatest because of the extra liquid above it.

Watch out: liquid pressure depends only on depth and density (and g) — not on the shape of the container or the area of its base. At the same depth, the pressure is the same in a thin tube and a wide tank.

Equation · HT only (15.13–15.14 · separate science)

Pressure due to a column of liquid

The pressure from the liquid itself (above any atmospheric pressure) can be calculated:

p = h × ρ × gpressure from a liquid column (Pa) = height (m) × density (kg/m³) × gravitational field strength (N/kg)

To find the difference in pressure between two depths, use the difference in height (Δh) in the equation. Use g = 9.8 N/kg (some questions use 10).

Worked example

Depth 2.0 m in water (ρ = 1000 kg/m³, g = 10 N/kg).

p = h × ρ × g = 2.0 × 1000 × 10 = 20 000 Pa

HT only. This equation and the explanation of why liquid pressure varies with depth and density are Higher Tier.

Calculate · HT

Your turn — liquid column pressure

4Calculate the pressure due to a column of seawater (density 1030 kg/m³) at a depth of 5.0 m. Use g = 10 N/kg.
Pa
Hint: p = h × ρ × g = 5.0 × 1030 × 10.
Upthrust · HT only (15.15–15.17 · separate science)

Upthrust: why things float or sink

Because pressure is greater at the bottom of a submerged object than at the top, the fluid pushes up more than it pushes down. This net upward force is the upthrust. It equals the weight of the fluid displaced.

upthrust weight FLOATS: upthrust = weight upthrust SINKS: weight > upthrust
If the object is less dense than the fluid it floats (upthrust can balance its weight); if it is more dense it sinks (its weight beats the upthrust).

Float or sink? Compare the density of the object with the density of the fluid: less dense → floats; more dense → sinks. A floating object displaces its own weight of fluid. HT only.

Decide · HT

Float or sink?

Tap the correct outcome for each object placed in water (density 1000 kg/m³).

Atmospheric pressure (15.7 · separate science)

Why air pressure falls with height

The atmosphere is a "sea" of air. Its pressure comes from the weight of the air above you. As you go higher, there is less air above pressing down, and the air is less dense — so atmospheric pressure decreases with height.

ground high up: few molecules → low pressure near ground: many molecules → high pressure
Air molecules are packed more closely lower down (where the weight of all the air above compresses them), so pressure is highest at sea level.
Quick check

Up a mountain

?A climber goes from sea level to the top of a tall mountain. What happens to the atmospheric pressure, and why?
Recap

Topic 15 — the essentials

Deformation: elastic (springs back) vs inelastic/plastic (stays changed); deforming needs >1 force.

Hooke's law: F = k × x (only up to the limit of proportionality).

Energy stored: E = ½ × k × x² (area under the force–extension line).

Pressure: p = F ÷ A — force normal to a surface ÷ area. (separate science)

Liquid column (HT): p = h × ρ × g — pressure rises with depth & density.

Upthrust (HT): = weight of fluid displaced; float if less dense than the fluid.

Atmosphere: pressure falls with height (less air above).

You've covered all of Edexcel Topic 15 — Forces and matter, with the HT and separate-science parts flagged. Press Finish to see your score.

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