Cambridge IGCSE Physics (0625) · Topic 6 — Space physics
Mini-Lesson
Space physics
This mini-lesson covers the whole of Cambridge IGCSE Topic 6 — Space physics: the Earth and the Solar System (day, night, seasons, orbits and the v = 2πr/T equation) and Stars and the Universe (the Sun, galaxies, the light-year, the life cycle of stars, redshift and the expanding universe).
Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Screens marked Supplement are Extended-tier only (0625). Press Start when you're ready.
The Earth and the Solar System
Day, night and the year
The Earth has two key motions, and they explain the rhythms of our sky:
The Earth rotates on its axis once in about 24 hours — this gives day and night and the apparent daily motion of the Sun and stars across the sky (rising in the east, setting in the west).
The Earth orbits the Sun once in about 365 days (one year). Combined with the tilted axis, this orbit produces the seasons and the seasonal change in the Sun's path.
The Moon orbits the Earth once in about one month.
Earth's rotation turns the day side into night. The tilt of the axis (with the year-long orbit) gives the seasons.
Watch out: the Sun and stars only appear to move across the sky. It is the Earth that is rotating — the apparent motion is the reverse of the Earth's spin.
Quick check
What causes the seasons?
?Which combination correctly explains the seasons on Earth?
Components of the Solar System
What's in the Solar System
The Solar System is everything held by the Sun's gravity. You need to know its components and the order of the eight planets:
The Sun — our one star, holding almost all the mass.
The eight planets, in order outward: Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune.
Dwarf planets (e.g. Pluto) and asteroids (rocky, mostly in the belt between Mars and Jupiter).
Moons (natural satellites that orbit planets) and comets (icy bodies on long, stretched orbits).
Inner four planets are small and rocky; outer four are large and gaseous (not to scale).Sort it
Order the inner planets
Tap the four inner planets in order, starting nearest the Sun.
Gravity and orbits
Gravity holds the orbit
The Sun is so massive (about 99.8% of the Solar System's mass) that its gravitational attraction reaches out and pulls each planet. This gravitational force provides the inward (centripetal) force that keeps a planet curving around the Sun instead of flying off in a straight line.
The force is always directed towards the Sun; the velocity is tangential to the orbit.
Misconception buster: there is no mysterious "outward" force throwing the planet out. Gravity is the only force, and it acts as the centripetal force — continuously bending the planet's straight-line motion into a curve.
Quick check
Why doesn't a planet fly off?
?A planet moves in a near-circular orbit around the Sun. What provides the force needed to keep it in orbit?
Supplement · Equation
Average orbital speed Supplement
For an object in a (roughly) circular orbit, the distance covered in one full orbit is the circumference, 2πr. Dividing by the time for one orbit — the period T — gives the average speed:
v = (2 × π × r) ÷ Taverage orbital speed (m/s) = (2 × π × orbital radius (m)) ÷ orbital period (s)
Because a larger orbit also has a longer period, planets further from the Sun move more slowly: Mercury races round, Neptune crawls.
Worked example
The Earth orbits at r = 1.5 × 10¹¹ m with a period T = 3.15 × 10⁷ s (one year).
Units matter: radius in metres, period in seconds. If a question gives days or km, convert first (1 day = 86 400 s).
Supplement · Calculate
Your turn — orbital speed Supplement
1A satellite orbits a planet at radius r = 8.0 × 10⁶ m with a period T = 5.0 × 10³ s. Calculate its average orbital speed. Give your answer to 2 significant figures.
2A planet has an average orbital speed of 2.0 × 10⁴ m/s and an orbital period of 6.0 × 10⁷ s. Calculate the radius r of its orbit, to 2 significant figures.
m
Hint: rearrange to r = (v × T) ÷ (2 × π). Type it like 1.9e11.
Supplement
Comets and the Sun's field Supplement
The Sun's gravitational field strength decreases with distance — gravity gets weaker the further out you go. This shapes how objects on stretched orbits move.
A comet follows a long elliptical orbit, with the Sun off-centre. By conservation of energy:
Close to the Sun the field is strong, gravitational potential energy is low, so the comet's kinetic energy is high — it moves fastest.
Far from the Sun the field is weak, potential energy is high, so kinetic energy is low — it moves slowest.
The comet speeds up as it swings in past the Sun and slows down as it heads back out.Supplement · Quick check
Comet speed Supplement
?A comet is on an elliptical orbit around the Sun. Where on its orbit is it moving fastest?
Stars and the Universe
The Sun is a star
Our Sun is a star of medium size. Like other stars it is made mostly of hydrogen and helium.
Its energy source is nuclear fusion: in the core, hydrogen nuclei fuse together to form helium, releasing huge amounts of energy as electromagnetic radiation (infrared, visible light and ultraviolet).
Hydrogen fuses to helium in the Sun's core, releasing energy that radiates into space.Galaxies and distances
Galaxies and the light-year
A galaxy is a huge collection of many billions of stars. Our Sun is just one star in the Milky Way galaxy — and the Milky Way is just one of many billions of galaxies that make up the Universe.
Distances between stars are so vast that we use the light-year:
1 light-year = the distance light travels in one year≈ 9.5 × 10¹⁵ m (light moves at 3.0 × 10⁸ m/s)
Misconception buster: a light-year is a distance, not a time. "The star is 4 light-years away" means light needs 4 years to cross that gap — but the light-year itself measures how far, like a very long ruler.
Quick check
What is a light-year?
?A star is described as "8 light-years away". What does this tell you?
Calculate
Your turn — light-year reasoning
3A galaxy is 3.0 × 10⁶ light-years from Earth. Using 1 light-year = 9.5 × 10¹⁵ m, calculate this distance in metres. Give your answer to 2 significant figures.
m
Hint: multiply (3.0 × 10⁶) × (9.5 × 10¹⁵). Type it like 2.9e22.
Supplement
The life cycle of a star Supplement
Every star begins the same way, then its fate depends on its mass. All stars start as a nebula (a cloud of gas and dust) that gravity pulls together into a protostar, which heats until fusion begins and it becomes a stable (main-sequence) star. Then the two branches split:
The branch a star takes depends on its mass: Sun-like → white dwarf; much more massive → supernova → neutron star or black hole.Supplement · Sort it
Order a massive star's life Supplement
Tap the stages of a much more massive star in order, from birth to final remnant.
The expanding universe
Redshift
When we look at light from distant galaxies, the lines in its spectrum are shifted towards the red (longer-wavelength) end. This is redshift: the observed wavelength has increased because the galaxy is moving away from us.
The dark spectral lines shift towards the red end. The more distant the galaxy, the greater the redshift.
Almost all galaxies are redshifted, and the more distant a galaxy is, the greater its redshift (the faster it recedes). This is the key evidence that the Universe is expanding, supporting the Big Bang theory. Supplement Further evidence comes from the microwave background radiation — radiation reaching us uniformly from all directions, the stretched-out "afterglow" of the early hot Universe.
Misconception buster: redshift here is mainly space itself stretching the wavelengths as the Universe expands — the galaxies aren't ploughing through space like cars. And greater distance means greater recession speed, not a longer light travel time alone.
Quick check
Reading the redshift
?Astronomers find that galaxy B has a much larger redshift than galaxy A. What can they conclude?
Supplement
The Hubble constant and the age of the Universe Supplement
The recession speed v of a galaxy is proportional to its distance d. The constant of proportionality is the Hubble constant H₀:
If the expansion rate has stayed roughly constant, then running the expansion backwards gives an estimate for the age of the Universe:
age of Universe ≈ 1 ÷ H₀using H₀ ≈ 2.2 × 10⁻¹⁸ s⁻¹ gives about 4.5 × 10¹⁷ s ≈ 14 billion years
Worked example
With H₀ = 2.2 × 10⁻¹⁸ s⁻¹:
age ≈ 1 ÷ (2.2 × 10⁻¹⁸) = 4.5 × 10¹⁷ s (≈ 1.4 × 10¹⁰ years, i.e. ~14 billion years)
Supplement · Calculate
Your turn — age of the Universe Supplement
4Take the Hubble constant as H₀ = 2.5 × 10⁻¹⁸ s⁻¹. Estimate the age of the Universe in seconds using age ≈ 1 ÷ H₀. Give your answer to 2 significant figures.
s
Hint: age ≈ 1 ÷ (2.5 × 10⁻¹⁸). Type it like 4.0e17.
Recap
The key ideas to know
Earth & Solar System: rotation → day/night; orbit + tilt → seasons; Moon orbits Earth (~1 month); 8 planets in order; gravity provides the orbit force.
Orbital speed: v = (2 × π × r) ÷ T Supplement
Comets & field: elliptical orbits, fastest near the Sun; field weakens with distance Supplement
Stars: the Sun is a star of H & He, powered by fusion; galaxies hold billions of stars; the Milky Way is one of billions.
Light-year: a distance ≈ 9.5 × 10¹⁵ m.
Life cycle: nebula → protostar → main sequence → (Sun-like) red giant → white dwarf, or (massive) red supergiant → supernova → neutron star/black hole Supplement
Expanding universe: redshift (more distant = greater); evidence for the Big Bang; microwave background Supplement; age ≈ 1/H₀ Supplement
You've covered both halves of Cambridge IGCSE Topic 6 — the Earth & the Solar System and Stars & the Universe. Press Finish to see your score.
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