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Cambridge IGCSE Physics (0625) · Topic 4 — Electricity and magnetism
Mini-Lesson

Electricity and magnetism

This mini-lesson covers the whole of Cambridge 0625 Topic 4: magnetism, electrical quantities, electric circuits, electrical safety and electromagnetic effects — Core content plus the Supplement statements flagged as you go.

magnetism electricity electro- magnetism a current makes a field · a changing field makes a current

Work through each screen, answer the questions as you go (words and calculations) and collect ⭐ stars. Press Start when you're ready.

4.1 · Simple magnetism

Poles, attraction and repulsion

A magnet has two polesnorth (N) and south (S) — where the magnetic effect is strongest. The forces between poles follow one rule:

  • Like poles repel (N–N or S–S push apart).
  • Unlike poles attract (N–S pull together).
N S unlike → attract N N like → repel
By convention we colour N red and S blue. Only repulsion proves an object is itself a magnet.

Magnetic materials: iron, steel, cobalt and nickel are attracted by magnets. Most other materials (plastic, wood, copper, aluminium) are not magnetic.

4.1 · Magnetic field

The field around a bar magnet

A magnetic field is the region where a magnetic force acts. We draw it with field lines. Two rules you must get right:

  • Field lines run from N to S outside the magnet (and S to N inside).
  • The lines are closest together where the field is strongest — at the poles.
N S field lines leave N, enter S
Plot the field with a small plotting compass: its needle always points along the line, N-end leading.

Misconception: field lines never cross, and outside the magnet they always point N → S, never the other way.

Quick check

Which way do they point?

?Outside a bar magnet, in which direction do the magnetic field lines point?
4.1 · Materials & electromagnets

Soft iron vs hard steel

Magnetic materials behave very differently when you magnetise or demagnetise them:

  • Soft magnetic material (e.g. iron) — easy to magnetise but loses its magnetism easily. Ideal for an electromagnet core and the core of a transformer.
  • Hard magnetic material (e.g. steel) — harder to magnetise but keeps its magnetism. Ideal for a permanent magnet.

Induced magnetism: a magnetic material placed in a field becomes a magnet itself (this is why a magnet can pick up a chain of unmagnetised nails). You can magnetise by stroking with a magnet or with a d.c. coil, and demagnetise by hammering, heating, or using a.c. in a coil.

soft iron core N S current on → magnet · current off → no magnet
An electromagnet can be switched on/off and made stronger with more turns, more current, or a soft iron core.
Match it

Soft, hard or induced?

Tap a description on the left, then its matching term on the right.

Description
Term
4.2 · Static electricity

Charge: positive and negative

There are two kinds of electric charge. Like charges repel; unlike charges attract — the same pattern as magnetic poles.

  • Conductors (metals, graphite) let charge flow freely; insulators (plastic, rubber) do not.
  • Charging by friction: rubbing transfers electrons. The object that gains electrons becomes negative; the one that loses them becomes positive. (Only electrons move — never protons.)

Electric field: a charge is surrounded by an electric field — the region where it exerts a force on other charges. Field lines point away from + and towards –.Supplement Charging an isolated conductor by electrostatic induction (without contact) is also Supplement.

+ field points away from + field points towards –
4.2 · Current & charge

Current is the flow of charge

Current (I) is the rate of flow of electric charge, measured in amperes (A) with an ammeter in series. Charge is measured in coulombs (C):

Q = I tcharge (C) = current (A) × time (s)

Conventional current vs electron flow: conventional current flows from + to – around the circuit. The electrons (the actual moving charge in a metal) drift the opposite way, from – to +. Both describe the same circuit — exam answers use conventional current.

Worked example

A current of 3 A flows for 20 s.

Q = I × t = 3 × 20 = 60 C

Calculate

Your turn — charge

1A current of 0.5 A flows through a lamp for 2 minutes. How much charge passes through it? (Watch the units of time!)
C
Hint: convert 2 minutes to seconds first, then Q = I × t = 0.5 × 120.
4.2 · e.m.f., p.d. & resistance

Voltage and resistance

  • e.m.f. (electromotive force) — the electrical work done by a source per unit charge driven round a complete circuit. Unit: volt (V) = joule per coulomb.
  • Potential difference (p.d.) — the work done by the current per unit charge across a component. Measured with a voltmeter in parallel.
  • Resistance (R) — how much a component opposes the current:
R = V ÷ Iresistance (Ω) = potential difference (V) ÷ current (A)

Supplement For a wire, resistance is proportional to length and inversely proportional to cross-sectional area: R = ρL/A. A longer, thinner wire has more resistance.

Calculate

Your turn — rearranging R = V/I

2A resistor of resistance 30 Ω has a potential difference of 6 V across it. Calculate the current through it.
A
Hint: rearrange R = V ÷ I to I = V ÷ R = 6 ÷ 30.
4.2 · I–V characteristics

I–V graphs: resistor vs lamp

Plotting current against potential difference tells you whether resistance is constant:

  • A fixed (ohmic) resistor at constant temperature gives a straight line through the origin — constant resistance, I ∝ V.
  • A filament lamp gives an S-shaped curve: as the current rises the filament gets hotter, so its resistance increases and the line bends away from the current axis.
V I resistor filament lamp origin
Both pass through the origin. The lamp's gradient (and so its resistance) changes; the resistor's does not.
Quick check

Reading the lamp's graph

?Why does the I–V graph for a filament lamp curve, instead of being a straight line?
4.2 · Electrical energy & power

Electrical power and energy

Electrical power is the rate at which energy is transferred:

P = I Vpower (W) = current (A) × potential difference (V)

and the energy transferred over a time t:

E = I V t  =  P tenergy (J) = current (A) × p.d. (V) × time (s)

Supplement Combining P = IV with V = IR gives two more forms: P = I²R and P = V²/R.

Worked example

A 230 V hairdryer draws a current of 4 A.

P = I × V = 4 × 230 = 920 W

Calculate

Your turn — electrical power

3A torch bulb runs at a potential difference of 3 V and carries a current of 0.4 A. Calculate the power transferred by the bulb.
W
Hint: P = I × V = 0.4 × 3.
Calculate

Your turn — electrical energy

4A 60 W lamp is left on for 5 minutes. How much energy does it transfer? (Convert the time to seconds.)
J
Hint: E = P × t = 60 × (5 × 60).
4.3 · Circuit symbols

Drawing circuit diagrams

You must recognise and draw the standard symbols. A few that catch people out:

cell battery resistor lamp A — ammeter V — voltmeter switch variable resistor A V
Note the longer line = + on a cell. An ammeter (A) goes in series; a voltmeter (V) goes in parallel.
4.3 · Series & parallel

Series vs parallel circuits

SERIES one loop · current same everywhere PARALLEL branches · p.d. same across each
  • Series: current is the same at every point; the e.m.f. is shared (p.d. splits) between components; total resistance R = R₁ + R₂ + …
  • Parallel: the p.d. is the same across each branch; the current splits and recombines; the combined resistance is less than the smallest branch.Supplement 1/R = 1/R₁ + 1/R₂ + …
  • Cells in series add their e.m.f.s (two 1.5 V cells give 3 V).

Misconceptions: current is not "used up" by the first bulb in series — it is the same all round. In parallel, p.d. is equal across the branches, not shared.

Calculate

Your turn — combined resistance

5Three resistors of 4 Ω, 6 Ω and 10 Ω are connected in series. Calculate their total resistance.
Ω
Hint: in series just add them — R = R₁ + R₂ + R₃.
Quick check

Where does the voltage go?

?Two identical lamps are connected in parallel to a 6 V battery. What is the potential difference across each lamp?
4.3 · Supplement

Potential dividers & sensors Supplement

A potential divider is two resistors in series that share the supply voltage. The larger resistor takes the larger share of the p.d.

Swap one resistor for an input transducer and the output voltage responds to the surroundings:

  • Thermistor (NTC): resistance falls as temperature rises — used in temperature sensors and fire alarms.
  • Light-dependent resistor (LDR): resistance falls as light gets brighter — used in light sensors and automatic lights.
+V 0 V V out thermistor fixed R Hotter → thermistor R falls → its share of voltage drops → V out across fixed R rises
4.4 · Electrical safety

Hazards and safety features

Mains electricity is dangerous. The common hazards are: damaged insulation, overheating cables, damp conditions, and overloading sockets (too much current).

The UK mains plug uses three wires: live (brown), neutral (blue) and earth (green/yellow). Key safety features:

  • Fuse — a thin wire in the live wire that melts and breaks the circuit if the current gets too high.
  • Circuit breaker — a switch that trips on a large current (resets faster than a fuse).
  • Earthing — connects a metal case to earth; if the live wire touches the case, a large current flows to earth and blows the fuse.
  • Double insulation — a plastic case means no earth wire is needed (shown by the ▣ symbol).
fuse live (brown) in → → to appliance
The fuse always goes in the live wire, so it isolates the appliance from the live supply when it blows.

Choosing a fuse: pick the standard fuse just above the appliance's normal current. For a 920 W heater on 230 V, I = P/V = 920/230 = 4 A, so a 5 A fuse is correct (a 13 A fuse would not protect it).

Quick check

Choosing the right fuse

?A toaster is rated at 230 V, 690 W. Fuses available are 3 A, 5 A and 13 A. Which fuse should be fitted?
4.5 · Electromagnetic induction

Inducing an e.m.f.

When a conductor cuts magnetic field lines (or the field through a coil changes), an e.m.f. is induced across it. If the circuit is complete, an induced current flows. The induced e.m.f. is larger when you:

  • move the conductor (or magnet) faster;
  • use a stronger magnet;
  • use more turns on the coil.

Supplement The induced current always opposes the change that caused it (its direction is given by Lenz's law) — a consequence of conservation of energy.

A N S move
Push the magnet in and the meter deflects; hold it still and the reading is zero — only a change induces an e.m.f.
4.5 · a.c. generator

The a.c. generator

Spin a coil in a magnetic field and the sides cut field lines, inducing an alternating e.m.f. The coil connects to the circuit through two slip rings and brushes.

The output reverses every half-turn, giving a sine-shaped alternating current (a.c.). Spinning faster increases both the frequency and the peak voltage.

V t e.m.f. alternates: + then – each rotation
4.5 · Force on a conductor

The motor effect & Fleming's left-hand rule

A current-carrying conductor in a magnetic field feels a force (the motor effect). The force is biggest when the current is at right angles to the field.

F = B I Lforce (N) = magnetic flux density (T) × current (A) × length (m) · Supplement

Fleming's left-hand rule gives the direction. Hold the thumb and first two fingers of your left hand mutually at right angles:

  • First finger → Field (N → S);
  • seCond finger → Current (conventional, + → –);
  • thuMbMotion (the force).
Motion (thuMb) Field N→S (First finger) Current (seCond) all three mutually perpendicular — use your LEFT hand
Reverse the current or the field and the force reverses; reverse both and it stays the same.
Calculate · Supplement

Your turn — force on a conductor Supplement

6A wire of length 0.20 m carries a current of 5 A at right angles to a magnetic field of flux density 0.4 T. Calculate the force on the wire.
N
Hint: F = B × I × L = 0.4 × 5 × 0.20.
4.5 · d.c. motor

The d.c. motor

A coil in a magnetic field carries a current. By Fleming's left-hand rule, the two sides feel opposite forces — one up, one down — so the coil turns.

A split-ring commutator reverses the current in the coil every half-turn, so the coil keeps spinning the same way instead of stopping. The motor turns faster with more current, a stronger field, or more turns.

N S split-ring commutator force up force down
Opposite forces on the two sides create a turning effect; the commutator keeps the spin going one way.
4.5 · Transformers

Transformers

A transformer changes the size of an alternating voltage. It has a primary coil and a secondary coil wound on a soft iron core. The a.c. in the primary makes a changing magnetic field in the core, which induces an a.c. e.m.f. in the secondary.

iron core V p · N p a.c. in V s · N s a.c. out more turns on secondary → step-up (V s > V p)
V p / V s = N p / N sprimary/secondary voltage = primary/secondary turns

Supplement For an ideal (100% efficient) transformer, power in = power out: V p I p = V s I s. So a step-up transformer that increases voltage decreases the current by the same factor.

Misconception: transformers only work with a.c. — a steady d.c. gives a constant field, no change of flux, and so no induced e.m.f. in the secondary.

Calculate

Your turn — transformer turns

7A transformer has 200 turns on the primary and 1000 turns on the secondary. The primary voltage is 12 V. Calculate the secondary voltage.
V
Hint: V s = V p × (N s ÷ N p) = 12 × (1000 ÷ 200).
4.5 · Supplement

Transformers in the National Grid Supplement

Power stations send electricity across the country at very high voltage. Step-up transformers raise the voltage (and lower the current) for transmission; step-down transformers lower it again for homes.

Why high voltage? The power lost as heat in the cables is P = I²R. Transmitting at high voltage means a much smaller current for the same power, so far less energy is wasted heating the cables.

powerstation step-up↑V ↓I cables (low I) step-down↓V ↑I homes
Quick check

Why transmit at high voltage?

?Electricity is sent across the National Grid at very high voltage. What is the main reason?
Recap

The equations to know

Charge: Q = I t

Resistance: R = V ÷ I  (R = ρL/A — Supp.)

Power: P = I V  (= I²R = V²/R — Supp.)

Energy: E = I V t = P t

Series R: R = R₁ + R₂ + …  (parallel 1/R = 1/R₁ + … — Supp.)

Transformer: V p/V s = N p/N s  (V pI p = V sI s — Supp.)

Motor effect: F = B I L — Supp.

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