Cambridge IGCSE Physics (0625) · Topic 1 — Motion, forces and energy
Mini-Lesson
Motion, Forces & Energy
This mini-lesson walks you through the whole of Cambridge IGCSE Physics Topic 1: physical quantities, motion graphs, mass & weight, density, forces, momentum, energy, work & power, and pressure.
Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. SUPP badges mark Supplement (Extended-only) content. Press Start when you're ready.
1.1 Physical quantities
Measuring length, volume & time
Physics rests on careful measurement. Cambridge expects you to choose the right instrument and to improve precision by measuring multiples:
Length — a ruler (mm scale); read at eye level to avoid parallax error.
Volume — a measuring cylinder for liquids; for an irregular solid that sinks, use displacement of water.
Time — a clock or digital timer. For a short interval, time many repeats and divide. For a pendulum, time 10 swings and divide by 10 to get one period.
Displacement: the rise in water level equals the volume of the submerged solid.
Why multiples? A single stopwatch reading carries your reaction-time error. Timing 10 oscillations and dividing by 10 shrinks that error tenfold.
1.1 Supplement
Scalars vs vectors SUPP
A scalar has magnitude (size) only. A vector has magnitude and direction.
Scalars: distance, speed, time, mass, energy, temperature.
Vectors: force, weight, velocity, acceleration, momentum, electric & gravitational field strength.
Two vectors at right angles combine into a resultant found by Pythagoras (its size) and a direction:
For perpendicular vectors only: combine "tip-to-tail"; the resultant is the hypotenuse.Quick check
Scalar or vector?
?Which one of these is a vector quantity?
1.2 Motion
Speed, velocity & acceleration
Speed is the distance travelled per unit time. Velocity is speed in a stated direction (a vector).
v = s ÷ tspeed (m/s) = distance (m) ÷ time (s)
a = Δv ÷ tSupplement: acceleration (m/s²) = change in velocity (m/s) ÷ time (s)
An object near Earth's surface accelerates downward under gravity at g ≈ 9.8 m/s² — the acceleration of free fall. A deceleration is simply a negative acceleration.
Worked example
A sprinter covers 80 m in 10 s. Average speed v = 80 ÷ 10 = 8 m/s.
Calculate
Your turn — average speed
1A train travels 100 m in 8 s at a steady rate. Calculate its average speed.
m/s
Hint: v = 100 ÷ 8.
1.2 Motion graphs
Reading a speed–time graph
On a speed–time graph two features carry all the information:
The gradient (slope) = the acceleration.
The area under the line = the distance travelled.
From 0 to 20 m/s in 8 s: acceleration = 20 ÷ 8 = 2.5 m/s²; distance = area = ½ × 8 × 20 = 80 m.
Watch out: a horizontal line on a speed–time graph means constant speed (zero acceleration), not "stopped". On a distance–time graph a horizontal line does mean at rest.
Calculate
Your turn — acceleration from a graph
2A car's speed rises in a straight line from 0 to 24 m/s in 6 s. Read the gradient: calculate its acceleration.
m/s²
Hint: a = Δv ÷ t = 24 ÷ 6.
1.3 Mass & weight
Mass is not weight
Mass is the quantity of matter in an object — measured in kg, the same everywhere. Weight is the gravitational force on that mass — measured in newtons (N).
W = m gweight (N) = mass (kg) × gravitational field strength (N/kg)
Gravitational field strength g = W ÷ m. On Earth g ≈ 9.8 N/kg, and this number is equal to the acceleration of free fall (9.8 m/s²).
Watch out — the classic trap: your mass on the Moon is unchanged, but your weight is smaller because the Moon's g is only ~1.6 N/kg. Mass uses kg; weight uses N.
Worked example
A 7.5 kg bowling ball on Earth (g = 9.8 N/kg):
W = 7.5 × 9.8 = 73.5 N
Calculate
Your turn — weight
3A school bag has a mass of 5 kg. Using g = 9.8 N/kg, calculate its weight on Earth.
N
Hint: W = m g = 5 × 9.8.
1.4 Density
Density & the float/sink rule
Density is mass per unit volume — how tightly matter is packed:
ρ = m ÷ Vdensity (kg/m³ or g/cm³) = mass ÷ volume
An object floats if its density is less than the fluid's, and sinks if it is greater. SUPP one liquid floats on another (that won't mix) by the same rule.
To measure density: find mass on a balance; find volume with a measuring cylinder (liquid), ruler (regular solid) or displacement (irregular solid). Then ρ = m ÷ V.
Calculate
Your turn — density
4A metal block has a mass of 480 g and a volume of 60 cm³. Calculate its density.
g/cm³
Hint: ρ = m ÷ V = 480 ÷ 60.
1.5.1 Effects of forces
Hooke's law & spring constant
A force can change an object's size and shape. For a spring, the extension is proportional to the load — up to the limit of proportionality:
k = F ÷ xSupplement: spring constant (N/m) = force (N) ÷ extension (m)
Below the limit of proportionality the line is straight through the origin — load ∝ extension. The gradient gives the spring constant k.
Watch out:x is the extension (the increase in length), not the spring's total length. Past the limit of proportionality the graph curves and Hooke's law no longer holds.
Calculate SUPP
Your turn — spring constant
5A force of 10 N stretches a spring by an extension of 0.04 m, within its limit of proportionality. Calculate the spring constant.
N/m
Hint: k = F ÷ x = 10 ÷ 0.04.
1.5.1 Resultant force
Resultant force & F = ma
Add forces along a straight line to find the resultant. The resultant decides the motion:
Zero resultant → the object stays at rest or keeps moving in a straight line at constant speed.
Non-zero resultant → the velocity changes (speed and/or direction).
F = m aSupplement: resultant force (N) = mass (kg) × acceleration (m/s²) — same direction
Friction (drag) is the force between surfaces, or on an object moving through a liquid or gas (air resistance). It opposes motion and produces heating.
Watch out: balanced forces do not mean "stopped". A car at a steady 30 m/s has zero resultant force — constant velocity. Force causes acceleration, not velocity itself.
Calculate SUPP
Your turn — F = ma
6A resultant force accelerates a 1200 kg car at 3 m/s². Calculate the size of the resultant force.
N
Hint: F = m a = 1200 × 3.
1.5.1 Supplement
Circular motion SUPP
An object moving in a circle is constantly changing direction, so its velocity changes — it is accelerating. A force points toward the centre to keep it on the circle.
The force is always perpendicular to the motion, pointing to the centre. (F = mv²/r is not required.)1.5.2 Turning effect
The moment of a force
A moment is the turning effect of a force about a pivot:
moment = F × dmoment (N·m) = force (N) × perpendicular distance from pivot (m)
When there is no resultant force and no resultant moment, an object is in equilibrium. The principle of moments: for a balanced beam, total clockwise moments = total anticlockwise moments.
The beam balances: anticlockwise moment (30 × 2) equals clockwise moment (20 × 3).
Watch out: the distance is the perpendicular distance from the pivot to the line of the force. A force acting through the pivot has zero moment.
Calculate
Your turn — moment
7A spanner is turned by a force of 15 N applied at a perpendicular distance of 0.4 m from the bolt. Calculate the moment.
N·m
Hint: moment = F × d = 15 × 0.4.
1.5.3 Centre of gravity
Centre of gravity & stability
The centre of gravity is the single point where an object's whole weight seems to act. You can find it for a flat lamina by hanging it freely from two points and using a plumb line.
An object is more stable with a low centre of gravity and a wide base. It topples once the centre of gravity passes outside the base.Quick check
Which is most stable?
?Which design of bus is the most stable (least likely to topple)?
1.6 Momentum — Supplement
Momentum, impulse & conservation SUPP
All of Topic 1.6 is Extended-only. Momentum measures "how hard it is to stop" a moving object — mass × velocity (a vector):
p = m vmomentum (kg·m/s) = mass (kg) × velocity (m/s)
impulse = F t = Δ(mv)impulse (N·s) = force × time = change in momentum
The principle of conservation of momentum: in a collision with no external force, total momentum before = after. Resultant force can also be written as the rate of change of momentum, F = Δp ÷ t.
Before: p = (2 × 3) + (1 × 0) = 6 kg·m/s. After: the 3 kg pair moves at 2 m/s, so p = 3 × 2 = 6 kg·m/s — conserved.Calculate SUPP
Your turn — momentum
8A 0.5 kg football is kicked so it moves at 8 m/s. Calculate its momentum.
kg·m/s
Hint: p = m v = 0.5 × 8.
1.7.1 Energy
Energy stores & conservation
Energy may be stored as: kinetic, gravitational potential, chemical, elastic (strain), nuclear, electrostatic and internal (thermal). It is transferred between stores by forces (mechanical work), electric currents (electrical work), heating, and waves.
The principle of conservation of energy: energy cannot be created or destroyed — only transferred or stored.
A swing: energy sloshes between the gravitational store (top) and kinetic store (bottom) — the total stays constant.
Watch out: energy is never "used up" or "lost" — only dissipated (spread to the surroundings, usually by heating) so it is no longer useful. The total is always conserved.
1.7.1 Supplement
Kinetic & gravitational equations SUPP
The energy in the kinetic store and the change in the gravitational potential store are (Extended only):
Ek = ½ m v²kinetic energy (J) = ½ × mass (kg) × speed² (m/s)²
ΔEp = m g Δhchange in g.p.e. (J) = mass × g (N/kg) × change in height (m)
Because speed is squared, doubling the speed gives four times the kinetic energy — one reason braking distance grows so quickly.
Worked example
A 1000 kg car at 20 m/s: Ek = ½ × 1000 × 20² = ½ × 1000 × 400 = 200 000 J (200 kJ).
Calculate SUPP
Your turn — kinetic energy
9A 2 kg ball moves at 6 m/s. Calculate the energy in its kinetic store.
J
Hint: Ek = ½ × 2 × 6². (6² = 36)
Calculate SUPP
Your turn — gravitational store
10A 3 kg bag is lifted 5 m onto a shelf. Using g = 9.8 N/kg, calculate the change in its gravitational potential energy.
J
Hint: ΔEp = m g Δh = 3 × 9.8 × 5.
1.7.2 / 1.7.4 Work & power
Work & power
Mechanical work done equals the energy transferred when a force moves through a distance:
W = F d = ΔEwork (J) = force (N) × distance moved in the direction of the force (m)
Power is the rate of doing work or transferring energy:
P = W ÷ t = ΔE ÷ tpower (W) = work or energy (J) ÷ time (s)
One watt is one joule per second (1 W = 1 J/s).
Worked example
Pushing a box with 50 N for 4 m: W = 50 × 4 = 200 J. If that takes 5 s, P = 200 ÷ 5 = 40 W.
Calculate
Your turn — power
11A motor transfers 9000 J of energy in 30 s. Calculate its power output.
W
Hint: P = E ÷ t = 9000 ÷ 30.
1.7.3 Efficiency
Efficiency & Sankey diagrams
In every transfer some energy is dissipated to the surroundings. Efficiency is the fraction that ends up useful:
efficiency = useful output ÷ total input(× 100 for a %). Supplement: also useful power ÷ total power input.
Width ∝ energy. Here efficiency = 25 ÷ 100 = 0.25 = 25%; the other 75 J is dissipated as heat.
Efficiency is always between 0 and 1 (0–100%) — you can never get more useful energy out than you put in.
Calculate
Your turn — efficiency
12A lamp is supplied with 200 J and transfers 50 J usefully as light. Calculate its efficiency as a percentage.
%
Hint: (50 ÷ 200) × 100.
1.7.3 Energy resources
Where our energy comes from
Useful energy — or generated electricity — comes from many resources. Many drive a boiler → turbine → generator:
Fossil fuels & biofuels (chemical store, burned).
Water — waves, tides, hydroelectric dams.
Geothermal, nuclear fuel, and the Sun (solar cells for electricity; solar panels to heat water).
SUPP Radiation from the Sun is the source of almost all our resources (except geothermal, nuclear and tidal). The Sun's energy is released by nuclear fusion; research aims to harness fusion for power on Earth.
Trade-offs: fossil fuels are reliable but release CO₂. Renewables are cleaner, but solar/wind/tidal are intermittent. Compare on renewability, availability, reliability, scale and environmental impact.
Sort it
Renewable or not?
Tap a resource, then tap the box it belongs in.
♻️ Renewable
⛽ Non-renewable
1.8 Pressure
Pressure = force ÷ area
Pressure is the force acting per unit area:
p = F ÷ Apressure (Pa = N/m²) = force (N) ÷ area (m²)
Spreading a force over a large area gives low pressure (snowshoes, camel feet); concentrating it on a small area gives high pressure (a sharp knife, a drawing pin).
Worked example
A 200 N force on an area of 0.04 m²: p = 200 ÷ 0.04 = 5000 Pa.
Calculate
Your turn — pressure
13A box exerts a force of 600 N on the floor through a base area of 0.5 m². Calculate the pressure.
Pa
Hint: p = F ÷ A = 600 ÷ 0.5.
1.8 Pressure in liquids
Pressure beneath a liquid
The pressure inside a liquid increases with depth and with the liquid's density. The deeper you go, the more liquid weighs down on you:
Δp = ρ g ΔhSupplement: change in pressure (Pa) = density (kg/m³) × g (N/kg) × change in depth (m)
Pressure acts in all directions and grows with depth and density. A denser liquid (e.g. mercury) gives a bigger pressure at the same depth.
Watch out: liquid pressure depends on depth and density only — not on the shape or width of the container, and not on the total amount of liquid.
Calculate SUPP
Your turn — pressure in a liquid
14Find the increase in pressure 2 m below the surface of water (density 1000 kg/m³, g = 9.8 N/kg).
Pa
Hint: Δp = ρ g Δh = 1000 × 9.8 × 2.
Recap
The equations to know
Speed: v = s ÷ t · Acceleration: a = Δv ÷ t SUPP
Weight: W = m g · Field strength: g = W ÷ m
Density: ρ = m ÷ V
Force: F = m a SUPP · Spring: k = F ÷ x SUPP
Moment: M = F × d
Momentum: p = m v SUPP · impulse = F t = Δp
Energy: Ek = ½ m v² SUPP · ΔEp = m g Δh SUPP
Work: W = F d · Power: P = W ÷ t = E ÷ t
Efficiency: useful ÷ total (× 100%)
Pressure: p = F ÷ A · Δp = ρ g Δh SUPP
You've covered all eight sub-areas of Cambridge IGCSE Physics Topic 1. Press Finish to see your score.
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