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Cambridge IGCSE Physics (0625) · Topic 1 — Motion, forces and energy
Mini-Lesson

Motion, Forces & Energy

This mini-lesson walks you through the whole of Cambridge IGCSE Physics Topic 1: physical quantities, motion graphs, mass & weight, density, forces, momentum, energy, work & power, and pressure.

force F applied motion & energy change F = ma work is done · energy is transferred

Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. SUPP badges mark Supplement (Extended-only) content. Press Start when you're ready.

1.1 Physical quantities

Measuring length, volume & time

Physics rests on careful measurement. Cambridge expects you to choose the right instrument and to improve precision by measuring multiples:

  • Length — a ruler (mm scale); read at eye level to avoid parallax error.
  • Volume — a measuring cylinder for liquids; for an irregular solid that sinks, use displacement of water.
  • Time — a clock or digital timer. For a short interval, time many repeats and divide. For a pendulum, time 10 swings and divide by 10 to get one period.
40 cm³ 62 cm³ volume of solid 62 − 40 = 22 cm³
Displacement: the rise in water level equals the volume of the submerged solid.

Why multiples? A single stopwatch reading carries your reaction-time error. Timing 10 oscillations and dividing by 10 shrinks that error tenfold.

1.1 Supplement

Scalars vs vectors SUPP

A scalar has magnitude (size) only. A vector has magnitude and direction.

  • Scalars: distance, speed, time, mass, energy, temperature.
  • Vectors: force, weight, velocity, acceleration, momentum, electric & gravitational field strength.

Two vectors at right angles combine into a resultant found by Pythagoras (its size) and a direction:

3 N 4 N 5 N resultant = √(3² + 4²) = √25 = 5 N
For perpendicular vectors only: combine "tip-to-tail"; the resultant is the hypotenuse.
Quick check

Scalar or vector?

?Which one of these is a vector quantity?
1.2 Motion

Speed, velocity & acceleration

Speed is the distance travelled per unit time. Velocity is speed in a stated direction (a vector).

v = s ÷ tspeed (m/s) = distance (m) ÷ time (s)
a = Δv ÷ tSupplement: acceleration (m/s²) = change in velocity (m/s) ÷ time (s)

An object near Earth's surface accelerates downward under gravity at g ≈ 9.8 m/s² — the acceleration of free fall. A deceleration is simply a negative acceleration.

Worked example

A sprinter covers 80 m in 10 s. Average speed v = 80 ÷ 10 = 8 m/s.

Calculate

Your turn — average speed

1A train travels 100 m in 8 s at a steady rate. Calculate its average speed.
m/s
Hint: v = 100 ÷ 8.
1.2 Motion graphs

Reading a speed–time graph

On a speed–time graph two features carry all the information:

  • The gradient (slope) = the acceleration.
  • The area under the line = the distance travelled.
speed (m/s) time (s) 0 10 20 8 area = distance ½ × 8 × 20 = 80 m rise 20 run 8 s gradient = a = 20/8 = 2.5 m/s²
From 0 to 20 m/s in 8 s: acceleration = 20 ÷ 8 = 2.5 m/s²; distance = area = ½ × 8 × 20 = 80 m.

Watch out: a horizontal line on a speed–time graph means constant speed (zero acceleration), not "stopped". On a distance–time graph a horizontal line does mean at rest.

Calculate

Your turn — acceleration from a graph

2A car's speed rises in a straight line from 0 to 24 m/s in 6 s. Read the gradient: calculate its acceleration.
m/s²
Hint: a = Δv ÷ t = 24 ÷ 6.
1.3 Mass & weight

Mass is not weight

Mass is the quantity of matter in an object — measured in kg, the same everywhere. Weight is the gravitational force on that mass — measured in newtons (N).

W = m gweight (N) = mass (kg) × gravitational field strength (N/kg)

Gravitational field strength g = W ÷ m. On Earth g ≈ 9.8 N/kg, and this number is equal to the acceleration of free fall (9.8 m/s²).

Watch out — the classic trap: your mass on the Moon is unchanged, but your weight is smaller because the Moon's g is only ~1.6 N/kg. Mass uses kg; weight uses N.

Worked example

A 7.5 kg bowling ball on Earth (g = 9.8 N/kg):

W = 7.5 × 9.8 = 73.5 N

Calculate

Your turn — weight

3A school bag has a mass of 5 kg. Using g = 9.8 N/kg, calculate its weight on Earth.
N
Hint: W = m g = 5 × 9.8.
1.4 Density

Density & the float/sink rule

Density is mass per unit volume — how tightly matter is packed:

ρ = m ÷ Vdensity (kg/m³ or g/cm³) = mass ÷ volume
ρ < water floats ρ > water sinks
An object floats if its density is less than the fluid's, and sinks if it is greater. SUPP one liquid floats on another (that won't mix) by the same rule.

To measure density: find mass on a balance; find volume with a measuring cylinder (liquid), ruler (regular solid) or displacement (irregular solid). Then ρ = m ÷ V.

Calculate

Your turn — density

4A metal block has a mass of 480 g and a volume of 60 cm³. Calculate its density.
g/cm³
Hint: ρ = m ÷ V = 480 ÷ 60.
1.5.1 Effects of forces

Hooke's law & spring constant

A force can change an object's size and shape. For a spring, the extension is proportional to the load — up to the limit of proportionality:

k = F ÷ xSupplement: spring constant (N/m) = force (N) ÷ extension (m)
load / N extension / mm limit of proportionality straight = proportional curves: no longer proportional
Below the limit of proportionality the line is straight through the origin — load ∝ extension. The gradient gives the spring constant k.

Watch out: x is the extension (the increase in length), not the spring's total length. Past the limit of proportionality the graph curves and Hooke's law no longer holds.

Calculate SUPP

Your turn — spring constant

5A force of 10 N stretches a spring by an extension of 0.04 m, within its limit of proportionality. Calculate the spring constant.
N/m
Hint: k = F ÷ x = 10 ÷ 0.04.
1.5.1 Resultant force

Resultant force & F = ma

Add forces along a straight line to find the resultant. The resultant decides the motion:

  • Zero resultant → the object stays at rest or keeps moving in a straight line at constant speed.
  • Non-zero resultant → the velocity changes (speed and/or direction).
F = m aSupplement: resultant force (N) = mass (kg) × acceleration (m/s²) — same direction

Friction (drag) is the force between surfaces, or on an object moving through a liquid or gas (air resistance). It opposes motion and produces heating.

Watch out: balanced forces do not mean "stopped". A car at a steady 30 m/s has zero resultant force — constant velocity. Force causes acceleration, not velocity itself.

Calculate SUPP

Your turn — F = ma

6A resultant force accelerates a 1200 kg car at 3 m/s². Calculate the size of the resultant force.
N
Hint: F = m a = 1200 × 3.
1.5.1 Supplement

Circular motion SUPP

An object moving in a circle is constantly changing direction, so its velocity changes — it is accelerating. A force points toward the centre to keep it on the circle.

force → centre velocity (tangent) Same mass & radius: ↑ force → ↑ speed Same mass & speed: ↑ force → ↓ radius
The force is always perpendicular to the motion, pointing to the centre. (F = mv²/r is not required.)
1.5.2 Turning effect

The moment of a force

A moment is the turning effect of a force about a pivot:

moment = F × dmoment (N·m) = force (N) × perpendicular distance from pivot (m)

When there is no resultant force and no resultant moment, an object is in equilibrium. The principle of moments: for a balanced beam, total clockwise moments = total anticlockwise moments.

pivot 30 N 2 m 20 N 3 m 30 × 2 = 60 N·m = 20 × 3 = 60 N·m → balanced
The beam balances: anticlockwise moment (30 × 2) equals clockwise moment (20 × 3).

Watch out: the distance is the perpendicular distance from the pivot to the line of the force. A force acting through the pivot has zero moment.

Calculate

Your turn — moment

7A spanner is turned by a force of 15 N applied at a perpendicular distance of 0.4 m from the bolt. Calculate the moment.
N·m
Hint: moment = F × d = 15 × 0.4.
1.5.3 Centre of gravity

Centre of gravity & stability

The centre of gravity is the single point where an object's whole weight seems to act. You can find it for a flat lamina by hanging it freely from two points and using a plumb line.

stable low C of G, wide base topples high C of G, narrow base
An object is more stable with a low centre of gravity and a wide base. It topples once the centre of gravity passes outside the base.
Quick check

Which is most stable?

?Which design of bus is the most stable (least likely to topple)?
1.6 Momentum — Supplement

Momentum, impulse & conservation SUPP

All of Topic 1.6 is Extended-only. Momentum measures "how hard it is to stop" a moving object — mass × velocity (a vector):

p = m vmomentum (kg·m/s) = mass (kg) × velocity (m/s)
impulse = F t = Δ(mv)impulse (N·s) = force × time = change in momentum

The principle of conservation of momentum: in a collision with no external force, total momentum before = after. Resultant force can also be written as the rate of change of momentum, F = Δp ÷ t.

before 2 kg, 3 m/s 1 kg, at rest collide after 3 kg coupled p before = 6 = p after
Before: p = (2 × 3) + (1 × 0) = 6 kg·m/s. After: the 3 kg pair moves at 2 m/s, so p = 3 × 2 = 6 kg·m/s — conserved.
Calculate SUPP

Your turn — momentum

8A 0.5 kg football is kicked so it moves at 8 m/s. Calculate its momentum.
kg·m/s
Hint: p = m v = 0.5 × 8.
1.7.1 Energy

Energy stores & conservation

Energy may be stored as: kinetic, gravitational potential, chemical, elastic (strain), nuclear, electrostatic and internal (thermal). It is transferred between stores by forces (mechanical work), electric currents (electrical work), heating, and waves.

The principle of conservation of energy: energy cannot be created or destroyed — only transferred or stored.

g.p.e. max k.e. = 0 k.e. max, g.p.e. min
A swing: energy sloshes between the gravitational store (top) and kinetic store (bottom) — the total stays constant.

Watch out: energy is never "used up" or "lost" — only dissipated (spread to the surroundings, usually by heating) so it is no longer useful. The total is always conserved.

1.7.1 Supplement

Kinetic & gravitational equations SUPP

The energy in the kinetic store and the change in the gravitational potential store are (Extended only):

Ek = ½ m v²kinetic energy (J) = ½ × mass (kg) × speed² (m/s)²
ΔEp = m g Δhchange in g.p.e. (J) = mass × g (N/kg) × change in height (m)

Because speed is squared, doubling the speed gives four times the kinetic energy — one reason braking distance grows so quickly.

Worked example

A 1000 kg car at 20 m/s: Ek = ½ × 1000 × 20² = ½ × 1000 × 400 = 200 000 J (200 kJ).

Calculate SUPP

Your turn — kinetic energy

9A 2 kg ball moves at 6 m/s. Calculate the energy in its kinetic store.
J
Hint: Ek = ½ × 2 × 6². (6² = 36)
Calculate SUPP

Your turn — gravitational store

10A 3 kg bag is lifted 5 m onto a shelf. Using g = 9.8 N/kg, calculate the change in its gravitational potential energy.
J
Hint: ΔEp = m g Δh = 3 × 9.8 × 5.
1.7.2 / 1.7.4 Work & power

Work & power

Mechanical work done equals the energy transferred when a force moves through a distance:

W = F d = ΔEwork (J) = force (N) × distance moved in the direction of the force (m)

Power is the rate of doing work or transferring energy:

P = W ÷ t = ΔE ÷ tpower (W) = work or energy (J) ÷ time (s)

One watt is one joule per second (1 W = 1 J/s).

Worked example

Pushing a box with 50 N for 4 m: W = 50 × 4 = 200 J. If that takes 5 s, P = 200 ÷ 5 = 40 W.

Calculate

Your turn — power

11A motor transfers 9000 J of energy in 30 s. Calculate its power output.
W
Hint: P = E ÷ t = 9000 ÷ 30.
1.7.3 Efficiency

Efficiency & Sankey diagrams

In every transfer some energy is dissipated to the surroundings. Efficiency is the fraction that ends up useful:

efficiency = useful output ÷ total input(× 100 for a %). Supplement: also useful power ÷ total power input.
input 100 J useful 25 J wasted (heat) 75 J
Width ∝ energy. Here efficiency = 25 ÷ 100 = 0.25 = 25%; the other 75 J is dissipated as heat.

Efficiency is always between 0 and 1 (0–100%) — you can never get more useful energy out than you put in.

Calculate

Your turn — efficiency

12A lamp is supplied with 200 J and transfers 50 J usefully as light. Calculate its efficiency as a percentage.
%
Hint: (50 ÷ 200) × 100.
1.7.3 Energy resources

Where our energy comes from

Useful energy — or generated electricity — comes from many resources. Many drive a boiler → turbine → generator:

  • Fossil fuels & biofuels (chemical store, burned).
  • Water — waves, tides, hydroelectric dams.
  • Geothermal, nuclear fuel, and the Sun (solar cells for electricity; solar panels to heat water).

SUPP Radiation from the Sun is the source of almost all our resources (except geothermal, nuclear and tidal). The Sun's energy is released by nuclear fusion; research aims to harness fusion for power on Earth.

Renewable ☀️ solar💨 wind 🌊 tidal🌊 waves 💧 hydro🌋 geothermal 🌱 biofuel Non-renewable 🪨 coal🛢️ oil 🔥 natural gas ☢️ nuclear fuel

Trade-offs: fossil fuels are reliable but release CO₂. Renewables are cleaner, but solar/wind/tidal are intermittent. Compare on renewability, availability, reliability, scale and environmental impact.

Sort it

Renewable or not?

Tap a resource, then tap the box it belongs in.

♻️ Renewable

⛽ Non-renewable

1.8 Pressure

Pressure = force ÷ area

Pressure is the force acting per unit area:

p = F ÷ Apressure (Pa = N/m²) = force (N) ÷ area (m²)

Spreading a force over a large area gives low pressure (snowshoes, camel feet); concentrating it on a small area gives high pressure (a sharp knife, a drawing pin).

Worked example

A 200 N force on an area of 0.04 m²: p = 200 ÷ 0.04 = 5000 Pa.

Calculate

Your turn — pressure

13A box exerts a force of 600 N on the floor through a base area of 0.5 m². Calculate the pressure.
Pa
Hint: p = F ÷ A = 600 ÷ 0.5.
1.8 Pressure in liquids

Pressure beneath a liquid

The pressure inside a liquid increases with depth and with the liquid's density. The deeper you go, the more liquid weighs down on you:

Δp = ρ g ΔhSupplement: change in pressure (Pa) = density (kg/m³) × g (N/kg) × change in depth (m)
depth Δh small p (shallow) large p (deep)
Pressure acts in all directions and grows with depth and density. A denser liquid (e.g. mercury) gives a bigger pressure at the same depth.

Watch out: liquid pressure depends on depth and density onlynot on the shape or width of the container, and not on the total amount of liquid.

Calculate SUPP

Your turn — pressure in a liquid

14Find the increase in pressure 2 m below the surface of water (density 1000 kg/m³, g = 9.8 N/kg).
Pa
Hint: Δp = ρ g Δh = 1000 × 9.8 × 2.
Recap

The equations to know

Speed: v = s ÷ t  ·  Acceleration: a = Δv ÷ t SUPP

Weight: W = m g  ·  Field strength: g = W ÷ m

Density: ρ = m ÷ V

Force: F = m a SUPP  ·  Spring: k = F ÷ x SUPP

Moment: M = F × d

Momentum: p = m v SUPP  ·  impulse = F t = Δp

Energy: Ek = ½ m v² SUPP  ·  ΔEp = m g Δh SUPP

Work: W = F d  ·  Power: P = W ÷ t = E ÷ t

Efficiency: useful ÷ total (× 100%)

Pressure: p = F ÷ A  ·  Δp = ρ g Δh SUPP

You've covered all eight sub-areas of Cambridge IGCSE Physics Topic 1. Press Finish to see your score.

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