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Edexcel International GCSE Maths A (4MA1) · Geometry & Trigonometry
Mini-Lesson

Geometry & Trigonometry

This mini-lesson walks you through the whole of Edexcel 4MA1 Section 4 — Geometry & Trigonometry: angle rules, polygons, symmetry, bearings, constructions & loci, circle theorems, Pythagoras, trigonometry (SOHCAHTOA & the sine/cosine rules), mensuration, surface area & volume, and similarity.

angles & polygons Pythagoras & trig area & volume

Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Items marked Higher are for the Higher tier only. Press Start when you're ready.

4.1 · Angles, lines & triangles

Angles at a point and on a line

The first job of geometry is to find missing angles using rules you can quote:

  • Angles on a straight line add to 180°.
  • Angles around a point add to 360°.
  • Vertically opposite angles (where two lines cross) are equal.
  • Angles in a triangle add to 180°; in a quadrilateral to 360°.
b a a + b = 180° (angles on a straight line)

Reasoning matters (4.7): in the exam you often must state the rule you used — e.g. "angles on a straight line sum to 180°" — to earn full marks.

Calculate

Your turn — missing angle

1Three angles meet on a straight line: 52°, 74° and x. Work out x.
°
Hint: they sum to 180°, so x = 180 − 52 − 74.
4.1 · Parallel lines

Angles in parallel lines

When a straight line (a transversal) crosses two parallel lines, special equal and supplementary pairs appear:

a a b c corresponding (a = a) · alternate (b = c) · co-interior sum to 180°
  • Corresponding angles (in "F" shapes) are equal.
  • Alternate angles (in "Z" shapes) are equal.
  • Co-interior / allied angles (in "C/U" shapes) sum to 180°.
Quick check

Name that angle pair

?A transversal crosses two parallel lines. One angle is 110°. Its co-interior partner (same side of the transversal, between the lines) is…
4.1 · Triangles & quadrilaterals

Naming triangles & quadrilaterals

You must know the properties of each special shape — sides, angles and symmetry:

  • Equilateral triangle — 3 equal sides, all angles 60°.
  • Isosceles triangle — 2 equal sides and 2 equal base angles.
  • Scalene triangle — all sides and angles different.
  • Square, rectangle, parallelogram, rhombus, trapezium, kite — each with its own side, angle and diagonal properties.
50° 50° 80° isosceles: equal sides ⇒ equal base angles (50° + 50° + 80° = 180°)

Watch out: in an isosceles triangle the two equal angles sit under the two equal sides — not next to the "odd" side.

4.2 · Polygons

Interior & exterior angles

A polygon with n sides can be split into n − 2 triangles, so its interior angles add up to:

sum of interior angles = (n − 2) × 180°e.g. pentagon (n = 5): (5 − 2) × 180 = 540°
interior 108° exterior 72° interior + exterior = 180° at each corner
exterior angles of ANY polygon sum to 360°for a REGULAR polygon: each exterior angle = 360° ÷ n

Common trap: the exterior angles always sum to 360° (not the interior angles). Interior + exterior at each vertex = 180°.

Calculate

Your turn — regular polygon

2A regular polygon has 8 sides (an octagon). Work out the size of one exterior angle.
°
Hint: exterior angle = 360° ÷ number of sides.
Quick check

Interior angle of a hexagon

?What is the size of one interior angle of a regular hexagon (n = 6)?
4.3 · Symmetry

Line & rotational symmetry

Two kinds of symmetry are tested:

  • Line symmetry — the number of mirror lines that fold a shape exactly onto itself. A square has 4; a rectangle has 2.
  • Rotational symmetry — how many times a shape looks identical in one full turn. A square has order 4; an equilateral triangle has order 3.
4 lines of symmetry, rotational order 4
4.5 · Construction & loci

Constructions and loci

Using only a ruler and a pair of compasses (leave your arcs showing — they earn marks), you must be able to construct:

  • The perpendicular bisector of a line (the locus of points equidistant from its two ends).
  • The bisector of an angle (the locus of points equidistant from its two arms).
  • A perpendicular from a point to a line.

A locus is the set of all points obeying a rule. The locus of points a fixed distance r from a point is a circle of radius r; a fixed distance from a line is a "racetrack" of two parallels joined by semicircles.

A B perpendicular bisector
4.6 · Circle theorems · Higher

Circle theorems

On the Higher tier you use these circle rules (with reasons):

  • The angle at the centre is twice the angle at the circumference on the same arc.
  • The angle in a semicircle is 90°.
  • Angles in the same segment are equal.
  • Opposite angles of a cyclic quadrilateral sum to 180°.
  • A tangent meets a radius at 90°; two tangents from a point are equal.
  • Alternate segment theorem: the angle between a tangent and a chord equals the angle in the alternate segment.
  • A radius perpendicular to a chord bisects the chord.
2x x
Angle at the centre (2x) = twice the angle at the circumference (x) on the same arc.
Quick check · Higher

Angle in a semicircle

?Points A and B are the ends of a diameter. P is any other point on the circle. What is angle APB?
4.8 · Pythagoras' theorem

Pythagoras' theorem

In any right-angled triangle, the square on the longest side (the hypotenuse) equals the sum of the squares on the other two:

a² + b² = c²c is the hypotenuse — the side OPPOSITE the right angle
a b c (hypotenuse)
The hypotenuse c is always opposite the right angle — the longest side.
Worked example

Legs a = 3 cm and b = 4 cm.

c² = 3² + 4² = 9 + 16 = 25, so c = √25 = 5 cm

Misconception: the hypotenuse is the side opposite the right angle, not just "the sloping one." To find a shorter side, rearrange to a² = c² − b² and subtract.

Calculate

Your turn — Pythagoras

3A right-angled triangle has the two shorter sides 5 cm and 12 cm. Work out the length of the hypotenuse.
cm
Hint: c = √(5² + 12²) = √(25 + 144) = √169.
4.8 · Right-angled trigonometry

SOHCAHTOA

In a right-angled triangle, label the sides relative to the angle θ: the hypotenuse (opposite the right angle), the opposite (facing θ) and the adjacent (next to θ):

θ adjacent opposite hypotenuse
Opposite = across from θ · Adjacent = beside θ · Hypotenuse = opposite the right angle.
sin θ = O/H · cos θ = A/H · tan θ = O/ASOH — CAH — TOA
Worked example

Opposite = 6 cm, angle θ = 30°, find the hypotenuse H.

sin 30° = 6 / H ⇒ H = 6 ÷ sin 30° = 6 ÷ 0.5 = 12 cm

Misconception: you must pick the ratio that uses the two sides you know/want. Using sin when you only have opposite & adjacent (that's tan) is the classic slip.

Calculate

Your turn — SOHCAHTOA

4In a right-angled triangle the side opposite angle θ is 8 cm and the adjacent side is 8 cm. Work out θ (to the nearest degree).
°
Hint: opposite & adjacent ⇒ tan θ = 8/8 = 1, so θ = tan⁻¹(1).
Sort it

Which ratio or rule?

Tap the correct method for each triangle situation.

4.4 · Bearings

Bearings

A bearing gives a direction as an angle measured:

  • clockwise,
  • from north,
  • always written with three figures (e.g. 060°, 135°, 285°).
N 060° measured clockwise, from north, three figures.

The bearing of B from A and the bearing of A from B differ by 180° (a "back bearing"). Trigonometry and Pythagoras are often used to solve bearing problems.

4.8 · Sine rule · Higher

The sine rule

For non-right-angled triangles (Higher tier), use the sine rule when you have a matching side–angle pair:

a / sin A = b / sin B = c / sin Ceach side over the sine of its OPPOSITE angle
Worked example

In triangle ABC, a = 7, angle A = 30°, angle B = 45°. Find side b.

b = a × sin B ÷ sin A = 7 × sin 45° ÷ sin 30° = 7 × 0.7071 ÷ 0.5 ≈ 9.90

Use the sine rule when you know a side and its opposite angle. If instead you know two sides and the angle between them, you'll need the cosine rule (next).

4.8 · Cosine rule & area · Higher

The cosine rule & ½ab sin C

The cosine rule handles the two cases the sine rule can't: two sides and the included angle, or all three sides:

a² = b² + c² − 2bc cos Arearrange to cos A = (b² + c² − a²) / (2bc) to find an angle

The area of any triangle (given two sides and the angle between them) is:

Area = ½ ab sin CC is the angle BETWEEN sides a and b
Worked example — cosine rule

b = 5, c = 7, angle A = 60°. Find a.

a² = 5² + 7² − 2×5×7×cos 60° = 25 + 49 − 70×0.5 = 74 − 35 = 39

a = √39 ≈ 6.24

Calculate · Higher

Your turn — area of a triangle

5A triangle has sides a = 6 cm and b = 10 cm with the angle between them C = 30°. Work out its area (½ab sin C).
cm²
Hint: ½ × 6 × 10 × sin 30° = ½ × 60 × 0.5.
4.8 · 3D trigonometry · Higher

Trigonometry in 3D

Higher-tier problems apply Pythagoras and trigonometry in three dimensions — for example finding the length of the space diagonal of a cuboid, or the angle between a line and a plane.

space diagonal
Find a diagonal on the base first (Pythagoras), then use it as one side of a second right triangle going up.

Strategy: identify a right-angled triangle inside the solid, solve it, then use the answer in the next triangle. The angle between a line and a plane sits between the line and its "shadow" on the plane.

4.9 · Mensuration

Perimeter, area, circles & sectors

You must know the standard 2D formulas:

  • Rectangle area = base × height; triangle = ½ × base × height.
  • Parallelogram = base × height; trapezium = ½(a + b) × h.
  • Circle: circumference = πd = 2πr; area = πr².
arc length = (θ/360) × 2πrsector area = (θ/360) × πr² (θ = the angle of the sector)
θ r A sector is a "pizza slice" — a fraction θ/360 of the whole circle.
Calculate

Your turn — area of a circle

6A circle has radius 7 cm. Work out its area, using π = 3.14 (to the nearest whole cm²).
cm²
Hint: area = πr² = 3.14 × 7² = 3.14 × 49.
4.10 · 3D shapes & volume

Surface area & volume of solids

For a prism (uniform cross-section), volume = area of cross-section × length. Key formulas:

  • Cuboid: V = length × width × height.
  • Cylinder: V = πr²h; curved surface area = 2πrh.
  • Cone: V = ⅓πr²h; curved surface area = πrl.
  • Sphere: V = 4⁄3 πr³; surface area = 4πr².
  • Pyramid: V = ⅓ × base area × height.
r h cylinder: V = πr²h
Calculate

Your turn — volume of a prism

7A cuboid measures 4 cm × 5 cm × 10 cm. Work out its volume.
cm³
Hint: V = length × width × height = 4 × 5 × 10.
Match it

Match each shape to its formula

Tap a shape on the left, then its matching formula on the right.

Shape
Formula
4.11 · Congruence & similarity

Similar shapes & scale factors

Congruent shapes are identical (same size & shape). Similar shapes are the same shape but enlarged by a linear scale factor k (equal ratios of corresponding sides).

length SF = kAREA scale factor = k² · VOLUME scale factor = k³ (Higher)
3×2 (area 6) 6×4 (area 24) length ×2 ⇒ area ×2² = ×4

Misconception: the area scale factor is k² (not k), and the volume scale factor is k³. Double the lengths ⇒ 4× the area, 8× the volume.

Calculate · Higher

Your turn — area scale factor

8Two similar triangles have a linear scale factor of 3. The small one has area 8 cm². Work out the area of the larger triangle.
cm²
Hint: area SF = k² = 3² = 9, so area = 8 × 9.
Quick check · Higher

Volume scale factor

?Two similar solids have a length scale factor of 2. By what factor is the volume of the larger multiplied?
Recap

The rules & formulas to know

Angles: line 180° · point 360° · polygon exterior sum 360° · interior sum (n−2)×180°

Pythagoras: a² + b² = c² (c = hypotenuse)

SOHCAHTOA: sin=O/H · cos=A/H · tan=O/A

Sine rule (H): a/sinA = b/sinB = c/sinC

Cosine rule (H): a² = b² + c² − 2bc cosA

Area of triangle (H): ½ab sinC

Circle: C = 2πr · A = πr² · sector = (θ/360)

Volume: cylinder πr²h · cone ⅓πr²h · sphere 4⁄3πr³

Similarity: length k · area k² · volume k³ (H)

You've covered all of Edexcel 4MA1 Section 4 — angles, polygons, symmetry, bearings, constructions & loci, circle theorems, Pythagoras, trigonometry, mensuration, 3D solids and similarity. Press Finish to see your score.

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