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CCEA GCE Mathematics (2210) · Impulse and momentum
Mini-Lesson

Impulse and momentum

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  1. Mission 1A 1 kg trolley at 4 m s⁻¹ hits a still 3 kg one. They stick. How fast?
Mission 1

A 1 kg trolley at 4 m s⁻¹ hits a still 3 kg one. They stick. How fast?

Make a guess: A 1 kg trolley at 4 m s⁻¹ hits a still 3 kg one. They stick. How fast?

Mechanics · impulse and momentum (A2 only)

Momentum and impulse

  • Momentum =mv. It is a vector: in one dimension, choose a positive direction and give velocities signs. Units: N s (or kg m s⁻¹).
  • Impulse of a constant force F acting for time t is Ft, in N s.
  • Impulse = change in momentum:
I=mv−mu
  • The impulse has the same direction as the change in velocity.
Worked example Mechanics · impulse and momentum (A2 only)

A ball rebounding from a wall

Question
A ball of mass 0.2 kg hits a vertical wall at 15 m s⁻¹ and rebounds along the same line at 10 m s⁻¹. Find the impulse on the ball, and the average force if contact lasts 0.04 s.
  1. 1
    Take towards the wall as positive: u=15, v=−10
  2. 2
    Use I=mv−mu: I=0.2(−10)−0.2(15)=−5
  3. 3
    Interpret the sign: 5 N s away from the wall
  4. 4
    Average force: F=I/t=5/0.04=125
Answer
impulse 5 N s away from the wall; average force 125 N
⚠️ Watch out
0.2(15−10)=1 N s ignores the reversal; the velocity changes by 25 m s⁻¹, not 5.
Calculate
?A ball of mass 0.4 kg moving at 6 m s⁻¹ is hit by a bat and moves back along the same line at 14 m s⁻¹. Find the magnitude of the impulse on the ball.
N s
Mechanics · impulse and momentum (A2 only)

Conservation of linear momentum

  • When two bodies collide, they exert equal and opposite impulses on each other (Newton's third law).
  • So, with no external impulse, total momentum before = total momentum after:
m₁u₁+m₂u₂=m₁v₁+m₂v₂
  • Coalesce: the bodies stick and share one velocity, (m₁+m₂)v.
  • Explosion from rest: total momentum is zero before, so the parts move in opposite directions.
Worked example Mechanics · impulse and momentum (A2 only)

A head-on collision

Before and after a collision5 m s−14 m s−11 m s−1+BeforeAfterA3 kgB2 kgA3 kgB2 kgvB = ?
Question
Particle A (3 kg) moving at 5 m s⁻¹ collides directly with particle B (2 kg) moving at 4 m s⁻¹ towards A. After the collision A moves at 1 m s⁻¹ in its original direction. Find the velocity of B after the collision.
  1. 1
    Take A's original direction as positive, so B's velocity is −4
  2. 2
    Momentum before: 3(5)+2(−4)=7
  3. 3
    Momentum after: 3(1)+2v_B=7, so v_B=2
  4. 4
    Check impulses: on A, 3(1−5)=−12; on B, 2(2−(−4))=12
Answer
B moves at 2 m s⁻¹ in A's original direction (it reverses)
⚠️ Watch out
writing B's initial velocity as +4 gives v_B=10, which is wrong.
Quick check
?A shell of mass 5 kg is at rest. It explodes into two parts of mass 2 kg and 3 kg. The 2 kg part moves off at 12 m s⁻¹. Find the speed of the 3 kg part.
Calculate
?Particle A (4 kg) moving at 6 m s⁻¹ collides directly with particle B (m kg) moving at 3 m s⁻¹ towards A. They coalesce and move at 1.5 m s⁻¹ in A's original direction. Find m.
kg
Calculate
?Hence find the magnitude of the impulse exerted on A in this collision.
N s
Mission check

?A 1 kg trolley at 4 m s⁻¹ hits a stationary 3 kg trolley and they stick together. How fast do they move?
Recap

Big ideas

  • Momentum =mv (a vector); impulse =Ft=mv−mu, in N s.
  • With no external impulse, total momentum is conserved in collisions, coalescence and explosions.
  • Choose a positive direction first and give every velocity its sign.
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  1. Mission 1A 1 kg trolley at 4 m s⁻¹ hits a still 3 kg one. They stick. How fast?

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Specification points and sources for this lesson are listed at the bottom of the page.

Sources (1)

The specification points and sources behind this lesson.

  1. 1 CCEA GCE Mathematics (2018) specification, Unit A2 2 Applied Mathematics, Section A Mechanics, Impulse and momentum