This mini-lesson covers the whole of OCR Gateway P7 — Energy: how energy is stored and transferred, the conservation of energy in a closed system, the kinetic, gravitational and elastic calculations, plus work, power, dissipation and efficiency.
Work through each screen, answer the questions as you go (some wordy, some calculations) and collect ⭐ stars. Press Start when you're ready.
P7.1 · Stores & transfers
Think in stores, not "types"
OCR wants you to describe a system using energy stores and the transfers between them. We never "use energy up" — we shift it from one store to another.
Stores hold energy; transfers move it between them.
Watch out: "electrical", "heating" and "radiation" name how energy is transferred — they are pathways, not stores.
P7.1 · Pathways
Four ways energy is transferred
Whenever a system changes, the energy moves along one of four pathways:
Mechanically — a force does work (pushing, pulling, stretching, lifting).
Electrically — charge moves through a potential difference (e.g. a current in an appliance).
By heating — energy passes from a hotter to a cooler object.
By radiation — e.g. light or sound carrying energy away.
A toaster: the mains transfers energy electrically to the element, which transfers it by heating (and radiation) to the bread.Quick check
Which store fills?
?A wind-up clockwork toy is wound tightly before it is let go. While it is wound up, which energy store has been filled inside the spring?
Sort it
Filling which store?
For each change, tap the store that is being filled (gaining energy).
P7.1a · Conservation
Energy is conserved
The law of conservation of energy: energy can be transferred, stored or dissipated, but it is never created or destroyed.
In a closed system (no energy in or out) the total energy stays the same — there is no net change. Energy just moves between stores.
The total never changes — only how it is shared between stores.
Misconception: energy is not "used up". Even wasted energy still exists — it has just spread out to the surroundings where it is no longer useful.
P7.1b · GPE ⇄ KE
Falling: gravity store → kinetic store
When an object falls, energy shifts from its gravitational store into its kinetic store. On a swinging pendulum it sloshes back and forth between the two:
At the lowest point the bob moves fastest — its kinetic store is largest there.
If we ignore air resistance, the energy leaving the gravitational store equals the energy gained by the kinetic store, so m g h = ½ m v². The mass cancels, so a heavy and a light object reach the same speed after the same drop.
Quick check
Reading the swing
?Ignoring air resistance, a pendulum bob is released from one side. Which statement is correct?
P7.1e · Equation 1
Kinetic energy of a moving body
Every moving object has energy in its kinetic store. It depends on mass and, far more strongly, on speed:
Ek = ½ m v²kinetic energy (J) = ½ × mass (kg) × (speed)² (m/s)²
Because speed is squared, trebling the speed gives nine times the kinetic energy. This is investigated with light gates and trolleys.
Worked example
A 1200 kg car travels at 15 m/s.
Ek = ½ × 1200 × 15² = ½ × 1200 × 225 = 135 000 J (135 kJ)
Calculate
Your turn — kinetic energy
1A 0.5 kg football is kicked so it moves at 12 m/s. Calculate the energy in its kinetic store.
J
Hint: Ek = ½ × 0.5 × 12². (12² = 144)
P7.1e · Equation 2
Energy of an object raised up
Lift an object and you fill its gravitational store. The work done lifting it equals the energy stored:
Ep = m g hg.p.e. (J) = mass (kg) × gravitational field strength (N/kg) × height (m)
On the OCR data sheet, take g = 9.8 N/kg on Earth.
Worked example
A 0.25 kg apple is lifted 1.6 m onto a shelf (g = 9.8 N/kg).
Ep = 0.25 × 9.8 × 1.6 = 3.92 J
Calculate
Your turn — gravitational store
2A 45 kg gymnast climbs 4 m up a rope. Using g = 9.8 N/kg, how much energy is transferred to her gravitational store?
J
Hint: Ep = 45 × 9.8 × 4.
Calculate
Your turn — falling object
3A ball is dropped from a height of 5 m. Ignoring air resistance, use ½mv² = mgh with g = 9.8 N/kg to find its speed just before it lands.
m/s
Hint: mass cancels, so v² = 2gh = 2 × 9.8 × 5 = 98. Then v = √98.
P7.1e · Equation 3
Energy in a stretched spring
Stretch or compress a spring (up to its limit of proportionality) and you fill its elastic potential store:
Ee = ½ k e²elastic p.e. (J) = ½ × spring constant (N/m) × (extension)² (m)²
e is the extension (how much longer the spring gets), not its total length. Like kinetic energy, the term is squared.
Calculate
Your turn — elastic store
4A spring of spring constant 250 N/m is stretched by an extension of 0.30 m. Calculate the energy in its elastic potential store.
J
Hint: Ee = ½ × 250 × 0.30². (0.30² = 0.09)
P7.1c–d · Work done
Work done by a force
When a force makes an object move, the force does work — and the work done equals the energy transferred mechanically:
W = F swork done (J) = force (N) × distance moved along the line of the force (m)
One joule is the work done when a force of 1 N moves an object 1 m (1 J = 1 N·m). Dragging a heavier crate, or dragging it further, does more work.
Worked example
A cleaner pushes a trolley with a 30 N force for 8 m.
W = F × s = 30 × 8 = 240 J transferred.
Calculate
Your turn — work done
5A horizontal force of 250 N drags a sledge 6 m across the snow. Calculate the work done by the force.
J
Hint: W = F × s = 250 × 6.
P7.2c · Power
Power is the rate of transfer
Power tells you how quickly energy is transferred (or how quickly work is done):
P = E ÷ t = W ÷ tpower (W) = energy transferred (J) ÷ time (s)
One watt is one joule per second (1 W = 1 J/s). The power rating of an appliance tells you how much energy it transfers each second when in use.
Misconception: a higher power does not mean more total energy — it means the same energy can be transferred in less time. A 2 kW kettle boils the same water as a 1 kW one, but in half the time.
Calculate
Your turn — power
6A crane lifts a load, transferring 90 000 J of energy in 30 s. Calculate its power output.
W
Hint: P = E ÷ t = 90 000 ÷ 30.
P7.2a,d · Dissipation & efficiency
Useful vs dissipated energy
In every transfer, some energy is dissipated — stored in less useful ways (usually spread out by heating). A Sankey diagram shows this: the wider the arrow, the more energy.
This motor: 375 J of every 500 J becomes useful kinetic energy.
efficiency = useful output ÷ total input(× 100 for a percentage) — a ratio between 0 and 1, with no units
That motor's efficiency = 375 ÷ 500 = 0.75 = 75%. Efficiency is always less than 1 (under 100%) and has no units.
Calculate
Your turn — efficiency
7A kettle is supplied with 240 000 J of energy and transfers 204 000 J usefully to the thermal store of the water. Calculate its efficiency as a percentage.
%
Hint: (204 000 ÷ 240 000) × 100.
P7.2f–g · Reducing waste
Reducing unwanted transfers
Lubrication — oil between moving parts cuts friction, so less energy is dissipated by heating.
Thermal insulation — keeps energy in the thermal store for longer.
A building cools more slowly when its walls are thicker and made of a material with a lower thermal conductivity (qualitative only).
Quick check
Keeping the heat in
?Two identical houses differ only in their walls. Which house's thermal store will cool down the most slowly?
Higher tier
Increasing efficiency (HT only · P7.2e)
?A geared machine wastes a lot of energy through friction in its bearings. Which change would increase its efficiency the most?
Recap
The P7 equations to know
Kinetic store: Ek = ½ m v²
Gravitational store: Ep = m g h
Elastic store: Ee = ½ k e²
Work done: W = F s (= energy transferred)
Power: P = E ÷ t = W ÷ t
Efficiency: useful output ÷ total input (× 100%, no units)
You've covered both parts of OCR Gateway P7 — P7.1 Work done (stores, transfers, conservation in a closed system, the energy calculations) and P7.2 Power and efficiency (dissipation, efficiency, reducing unwanted transfers). Press Finish to see your score.
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