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Eduqas GCSE Physics (C420P) · Topic 2 — Particle model of matter
Mini-Lesson

Particle Model of Matter

This mini-lesson walks you through the whole of Eduqas Topic 2 — Particle model of matter: density and how to measure it, the three states of matter and the changes of state between them, the energy stored inside matter, and how gases create pressure.

solid liquid gas
Same particles, different arrangements: packed in a solid, close but free to flow in a liquid, far apart in a gas.

Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Some gas-law screens are Higher tier — clearly flagged. Press Start when you're ready.

Density

Density = mass packed into a volume

Eduqas opens this topic by asking you to define density and explain why the three states differ. Density is the mass per unit volume:

ρ = m ÷ Vdensity (kg/m³) = mass (kg) ÷ volume (m³)  ·  ρ is the Greek letter "rho"

Because a gas has its particles spread far apart, the same mass fills a far bigger volume — so gases have a much lower density than solids or liquids of the same substance.

Units tip: Eduqas expects you to work in both kg/m³ and g/cm³ (water ≈ 1000 kg/m³ = 1 g/cm³), but you won't be asked to convert between them.

Quick check

Why are gases least dense?

?Steam, water and ice are all the same substance. Why does the steam have by far the lowest density?
Specified practical · SP2A

Measuring density

To find a density you need a mass (from a balance) and a volume. How you get the volume depends on the shape:

  • Regular solid (e.g. a cube): measure the sides with a ruler and calculate volume = length × width × height.
  • Irregular solid (e.g. a stone): lower it into a measuring cylinder of water and read the rise in volume — the water it displaces equals the object's volume.
  • Liquid: mass an empty measuring cylinder, add a known volume, re-mass, and subtract to find the liquid's mass.
48.0 g balance → mass 20 cm³ 26 cm³ rise = 6 cm³ = the volume
The stone pushes the water level up from 20 cm³ to 26 cm³, so its volume is 6 cm³. Then ρ = m ÷ V.
Worked example

That stone has a mass of 48.0 g and displaced 6 cm³ of water.

ρ = m ÷ V = 48.0 ÷ 6 = 8.0 g/cm³

Calculate

Your turn — find a density

1A regular metal block measures 2 cm × 3 cm × 5 cm and has a mass of 240 g. Calculate its density in g/cm³.
g/cm³
Hint: volume = 2 × 3 × 5 = 30 cm³, then ρ = 240 ÷ 30.
Changes of state

Melting, boiling — and mass is conserved

When a substance melts, freezes, evaporates, condenses or sublimates, it changes state. These are physical changes, not chemical ones:

  • No new substance is made — the particles are simply rearranged.
  • Mass is conserved: 1 kg of ice melts into exactly 1 kg of water.
  • They are reversible — cool the steam and you get the same water back (ice → water → steam → water → ice).
solid liquid gas melting → ← freezing evaporating → ← condensing
Heating drives a substance to the right; cooling drives it back. Sublimation jumps straight from solid to gas.

Watch out: a chemical change (like burning) makes a new substance and isn't easily reversed — a change of state always lets you recover the original substance.

Quick check

Does the mass change?

?A sealed flask containing 18 g of ice is left out until all the ice has melted to water. What is the mass of water now?
Internal energy

The energy stored inside matter

Heating a substance raises its internal energy — the total energy stored by its particles. It comes in two parts:

  • the kinetic energy of the particles (how fast they vibrate or move) — this sets the temperature;
  • the potential energy from the bonds and spacing between particles — this changes during a change of state.

Spec note: on the Eduqas course the terms and equations for internal energy, specific heat capacity and specific latent heat are formally introduced in Topic 1 (Energy). They sit naturally alongside changes of state, so we revisit them here — and the next three screens are flagged as the Topic 1 link.

Topic 1 link · heating without changing state

Specific heat capacity

While a substance stays in one state, adding energy raises its temperature. How much energy depends on the mass and the material's specific heat capacity, c:

ΔE = m c Δθenergy (J) = mass (kg) × specific heat capacity (J/kg°C) × temperature change (°C)

The specific heat capacity is the energy needed to raise the temperature of 1 kg of a substance by 1 °C. Water's is high (4200 J/kg°C), so it is slow to heat and slow to cool.

Worked example

Heating 0.30 kg of copper (c = 385 J/kg°C) by 40 °C:

ΔE = 0.30 × 385 × 40 = 4620 J

Calculate

Your turn — specific heat capacity

2How much energy is needed to raise the temperature of 0.5 kg of aluminium (c = 900 J/kg°C) by 30 °C?
J
Hint: ΔE = 0.5 × 900 × 30.
Topic 1 link · changing state

Specific latent heat & the heating curve

During melting or boiling the temperature stops rising, even though energy is still flowing in. That energy is breaking bonds and pulling particles apart — it is the specific latent heat:

E = m Lenergy (J) = mass (kg) × specific latent heat (J/kg) — fusion for melting, vaporisation for boiling
temperature energy supplied → 0°C 100°C melting (plateau) boiling (plateau) solid liquid gas
The two flat plateaus are the give-away: during melting and boiling, energy goes into changing state, so the temperature holds steady.

Don't mix them up: use ΔE = mcΔθ on the slopes (temperature changing, one state) and E = mL on the plateaus (state changing, temperature constant).

Calculate

Your turn — specific latent heat

3The specific latent heat of fusion of ice is 334 000 J/kg. How much energy is needed to melt 0.2 kg of ice that is already at 0 °C?
J
Hint: E = m L = 0.2 × 334 000. (No temperature change, so no mcΔθ here.)
Sort it

Which equation, and why?

Tap a situation on the left, then its correct match on the right.

Gases · temperature & pressure

Pressure comes from particle collisions

In a gas the particles fly around at high speed in random directions. Each time one hits a wall it pushes on it. Billions of these tiny pushes per second add up to gas pressure:

force on wall
Each collision exerts a tiny force on the wall. Pressure is the total force per unit area from all these collisions.

Raising the temperature gives the particles more kinetic energy, so they move faster. They hit the walls harder and more often, so at constant volume the pressure rises: p ∝ T.

Quick check

Heating a sealed can

?A sealed, rigid can of gas is heated on a sunny day. Its volume cannot change. Why does the pressure inside rise?
Pressure, force & area

Pressure acts at right angles to a surface

Gases can be compressed or expanded when the pressure changes. The pressure produces a net force at right angles to any surface it touches:

p = F ÷ A  ⇔  F = p Apressure (Pa) = force (N) ÷ area (m²)  ·  1 Pa = 1 N/m²

Key idea: the same pressure pushes outwards on every wall of a container, always perpendicular to the surface — never along it.

Calculate

Your turn — force from pressure

4A gas at a pressure of 50 000 Pa pushes on a piston of area 0.004 m². Calculate the force on the piston.
N
Hint: F = p × A = 50 000 × 0.004.
Higher tier · gas laws

Squeeze a gas and the pressure rises Higher

Keep the temperature constant and change the volume of a fixed mass of gas. Squeeze it into a smaller space and the same particles hit the walls more often, so the pressure goes up. Pressure is inversely proportional to volume:

p ∝ 1 ÷ V  ⇒  p V = constantat constant temperature, for a fixed mass of gas  ·  so p₁V₁ = p₂V₂
big V, low p compress small V, high p p₁V₁ = p₂V₂
Halve the volume at constant temperature and the pressure doubles — the particles collide twice as often with the walls.
Calculate · Higher

Your turn — pV = constant Higher

5A fixed mass of gas has a volume of 0.06 m³ at a pressure of 100 000 Pa. At constant temperature it is compressed to 0.04 m³. Calculate the new pressure.
Pa
Hint: p₁V₁ = p₂V₂ → p₂ = (100 000 × 0.06) ÷ 0.04.
Doing work on a gas

Pump it and it warms up

Pumping up a bicycle tyre, the bottom of the pump gets noticeably warm. Pushing the piston in does work on the gas: that energy is transferred to the internal energy of the gas particles, so their temperature rises.

push (work done) gas warms up → internal energy rises
Work done on the gas is transferred to the kinetic energy of its particles — raising the temperature.
Quick check

Why is the pump warm?

?After inflating a tyre, the barrel of the bike pump feels hot. What best explains this?
Recap

The equations to know

Density: ρ = m ÷ V

Heating (one state): ΔE = m c Δθ · Topic 1 link

Changing state: E = m L · Topic 1 link

Pressure: p = F ÷ A  (F = p A)

Gases (Higher): p V = constant → p₁V₁ = p₂V₂

Qualitative: p ∝ T at constant volume; mass conserved in changes of state.

You've covered all of Eduqas Topic 2 — density and its practical, states & changes of state, gas pressure and the gas laws — plus the internal-energy ideas it shares with Topic 1. Press Finish to see your score.

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