Eduqas GCSE Physics (C420P) · Topic 2 — Particle model of matter
Mini-Lesson
Particle Model of Matter
This mini-lesson walks you through the whole of Eduqas Topic 2 — Particle model of matter: density and how to measure it, the three states of matter and the changes of state between them, the energy stored inside matter, and how gases create pressure.
Same particles, different arrangements: packed in a solid, close but free to flow in a liquid, far apart in a gas.
Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Some gas-law screens are Higher tier — clearly flagged. Press Start when you're ready.
Density
Density = mass packed into a volume
Eduqas opens this topic by asking you to define density and explain why the three states differ. Density is the mass per unit volume:
ρ = m ÷ Vdensity (kg/m³) = mass (kg) ÷ volume (m³) · ρ is the Greek letter "rho"
Because a gas has its particles spread far apart, the same mass fills a far bigger volume — so gases have a much lower density than solids or liquids of the same substance.
Units tip: Eduqas expects you to work in both kg/m³ and g/cm³ (water ≈ 1000 kg/m³ = 1 g/cm³), but you won't be asked to convert between them.
Quick check
Why are gases least dense?
?Steam, water and ice are all the same substance. Why does the steam have by far the lowest density?
Specified practical · SP2A
Measuring density
To find a density you need a mass (from a balance) and a volume. How you get the volume depends on the shape:
Regular solid (e.g. a cube): measure the sides with a ruler and calculate volume = length × width × height.
Irregular solid (e.g. a stone): lower it into a measuring cylinder of water and read the rise in volume — the water it displaces equals the object's volume.
Liquid: mass an empty measuring cylinder, add a known volume, re-mass, and subtract to find the liquid's mass.
The stone pushes the water level up from 20 cm³ to 26 cm³, so its volume is 6 cm³. Then ρ = m ÷ V.
Worked example
That stone has a mass of 48.0 g and displaced 6 cm³ of water.
ρ = m ÷ V = 48.0 ÷ 6 = 8.0 g/cm³
Calculate
Your turn — find a density
1A regular metal block measures 2 cm × 3 cm × 5 cm and has a mass of 240 g. Calculate its density in g/cm³.
When a substance melts, freezes, evaporates, condenses or sublimates, it changes state. These are physical changes, not chemical ones:
No new substance is made — the particles are simply rearranged.
Mass is conserved: 1 kg of ice melts into exactly 1 kg of water.
They are reversible — cool the steam and you get the same water back (ice → water → steam → water → ice).
Heating drives a substance to the right; cooling drives it back. Sublimation jumps straight from solid to gas.
Watch out: a chemical change (like burning) makes a new substance and isn't easily reversed — a change of state always lets you recover the original substance.
Quick check
Does the mass change?
?A sealed flask containing 18 g of ice is left out until all the ice has melted to water. What is the mass of water now?
Internal energy
The energy stored inside matter
Heating a substance raises its internal energy — the total energy stored by its particles. It comes in two parts:
the kinetic energy of the particles (how fast they vibrate or move) — this sets the temperature;
the potential energy from the bonds and spacing between particles — this changes during a change of state.
Spec note: on the Eduqas course the terms and equations for internal energy, specific heat capacity and specific latent heat are formally introduced in Topic 1 (Energy). They sit naturally alongside changes of state, so we revisit them here — and the next three screens are flagged as the Topic 1 link.
Topic 1 link · heating without changing state
Specific heat capacity
While a substance stays in one state, adding energy raises its temperature. How much energy depends on the mass and the material's specific heat capacity, c:
ΔE = m c Δθenergy (J) = mass (kg) × specific heat capacity (J/kg°C) × temperature change (°C)
The specific heat capacity is the energy needed to raise the temperature of 1 kg of a substance by 1 °C. Water's is high (4200 J/kg°C), so it is slow to heat and slow to cool.
Worked example
Heating 0.30 kg of copper (c = 385 J/kg°C) by 40 °C:
ΔE = 0.30 × 385 × 40 = 4620 J
Calculate
Your turn — specific heat capacity
2How much energy is needed to raise the temperature of 0.5 kg of aluminium (c = 900 J/kg°C) by 30 °C?
J
Hint: ΔE = 0.5 × 900 × 30.
Topic 1 link · changing state
Specific latent heat & the heating curve
During melting or boiling the temperature stops rising, even though energy is still flowing in. That energy is breaking bonds and pulling particles apart — it is the specific latent heat:
E = m Lenergy (J) = mass (kg) × specific latent heat (J/kg) — fusion for melting, vaporisation for boiling
The two flat plateaus are the give-away: during melting and boiling, energy goes into changing state, so the temperature holds steady.
Don't mix them up: use ΔE = mcΔθ on the slopes (temperature changing, one state) and E = mL on the plateaus (state changing, temperature constant).
Calculate
Your turn — specific latent heat
3The specific latent heat of fusion of ice is 334 000 J/kg. How much energy is needed to melt 0.2 kg of ice that is already at 0 °C?
J
Hint: E = m L = 0.2 × 334 000. (No temperature change, so no mcΔθ here.)
Sort it
Which equation, and why?
Tap a situation on the left, then its correct match on the right.
Gases · temperature & pressure
Pressure comes from particle collisions
In a gas the particles fly around at high speed in random directions. Each time one hits a wall it pushes on it. Billions of these tiny pushes per second add up to gas pressure:
Each collision exerts a tiny force on the wall. Pressure is the total force per unit area from all these collisions.
Raising the temperature gives the particles more kinetic energy, so they move faster. They hit the walls harder and more often, so at constant volume the pressure rises: p ∝ T.
Quick check
Heating a sealed can
?A sealed, rigid can of gas is heated on a sunny day. Its volume cannot change. Why does the pressure inside rise?
Pressure, force & area
Pressure acts at right angles to a surface
Gases can be compressed or expanded when the pressure changes. The pressure produces a net force at right angles to any surface it touches:
p = F ÷ A ⇔ F = p Apressure (Pa) = force (N) ÷ area (m²) · 1 Pa = 1 N/m²
Key idea: the same pressure pushes outwards on every wall of a container, always perpendicular to the surface — never along it.
Calculate
Your turn — force from pressure
4A gas at a pressure of 50 000 Pa pushes on a piston of area 0.004 m². Calculate the force on the piston.
N
Hint: F = p × A = 50 000 × 0.004.
Higher tier · gas laws
Squeeze a gas and the pressure rises Higher
Keep the temperature constant and change the volume of a fixed mass of gas. Squeeze it into a smaller space and the same particles hit the walls more often, so the pressure goes up. Pressure is inversely proportional to volume:
p ∝ 1 ÷ V ⇒ p V = constantat constant temperature, for a fixed mass of gas · so p₁V₁ = p₂V₂
Halve the volume at constant temperature and the pressure doubles — the particles collide twice as often with the walls.Calculate · Higher
Your turn — pV = constant Higher
5A fixed mass of gas has a volume of 0.06 m³ at a pressure of 100 000 Pa. At constant temperature it is compressed to 0.04 m³. Calculate the new pressure.
Pa
Hint: p₁V₁ = p₂V₂ → p₂ = (100 000 × 0.06) ÷ 0.04.
Doing work on a gas
Pump it and it warms up
Pumping up a bicycle tyre, the bottom of the pump gets noticeably warm. Pushing the piston in does work on the gas: that energy is transferred to the internal energy of the gas particles, so their temperature rises.
Work done on the gas is transferred to the kinetic energy of its particles — raising the temperature.Quick check
Why is the pump warm?
?After inflating a tyre, the barrel of the bike pump feels hot. What best explains this?
Recap
The equations to know
Density: ρ = m ÷ V
Heating (one state): ΔE = m c Δθ · Topic 1 link
Changing state: E = m L · Topic 1 link
Pressure: p = F ÷ A (F = p A)
Gases (Higher): p V = constant → p₁V₁ = p₂V₂
Qualitative: p ∝ T at constant volume; mass conserved in changes of state.
You've covered all of Eduqas Topic 2 — density and its practical, states & changes of state, gas pressure and the gas laws — plus the internal-energy ideas it shares with Topic 1. Press Finish to see your score.
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