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Eduqas GCSE Physics (C420P) · Topic 4 — Forces and motion
Mini-Lesson

Forces and Motion

This mini-lesson walks you through the whole of Eduqas Topic 4 — Forces and motion: how we describe motion with speed, velocity and acceleration and motion graphs, how Newton's three laws and momentum link forces to motion, and how those ideas keep us safe in vehicles.

Make a guess: what does the slope of a speed–time graph show?

  1. Mission 1How can one line tell the whole journey?
  2. Mission 2Same push: why do the trolleys differ?
  3. Mission 3What pushes the cannon backwards?
  4. Mission 4Why does a distracted driver stop later?

Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Higher-tier-only ideas are clearly flagged. Press Start when you're ready.

4.1 · Scalars and vectors

Distance vs displacement

Distance is how far an object has moved — a scalar (size only). Displacement is the straight-line distance and direction from start to finish — a vector.

start = finish distance travelled = the whole loop one full lap: displacement = 0
Run one full lap of a track and your distance is the whole loop, but your displacement is zero — you finished where you started.

Watch out: velocity is a vector — it always carries a direction. Two cars travelling at 30 m/s in opposite directions have the same speed but different velocities. A sign (+ or −) shows the direction.

Quick check

Speed or velocity?

?A satellite orbits Earth at a steady 7 700 m/s. Its speed is constant, yet physicists say its velocity is constantly changing. Why?
4.1 · Speed and velocity

Speed and typical values

Speed is how fast something travels; velocity is speed in a stated direction. Both use the same relationship to distance (or displacement) and time:

v = x ÷ tspeed/velocity (m/s) = distance or displacement (m) ÷ time (s)

You should know the order of magnitude of everyday speeds, because exam questions expect sensible estimates:

walking ≈ 1.5 running ≈ 3 cycling ≈ 6 wind ≈ 5–20 car 13–30 aeroplane ≈ 250 sound in air ≈ 330 1 10 100 1000 speed (m/s): each mark is ×10
Typical speeds (m/s). Each mark on the scale is ten times the one before. Learn wind (about 5–20 m/s) and sound in air (about 330 m/s) too.
Worked example

A cyclist covers 90 m in 15 s.

v = x ÷ t = 90 ÷ 15 = 6 m/s

4.1 · Acceleration

Acceleration

If velocity changes, the object accelerates (speeds up) or decelerates (slows down). Acceleration is the change in velocity each second:

a = Δv ÷ t = (v − u) ÷ tacceleration (m/s²) = change in velocity (m/s) ÷ time (s)
u = initial velocity, v = final velocity

Free-fall acceleration due to gravity on Earth is about g = 10 m/s² (a skydiver at first speeds up by about 10 m/s every second; as air resistance grows, the acceleration gets smaller).

Worked example

A car speeds up from 8 m/s to 20 m/s in 6 s.

a = (v − u) ÷ t = (20 − 8) ÷ 6 = 12 ÷ 6 = 2 m/s²

If the velocity is positive, a negative acceleration means the object is slowing down (decelerating) — the velocity is still changing, just in the opposite sense.

Calculate

Your turn — acceleration

1A train pulls away from a station, reaching 24 m/s from rest in 8 s. Calculate its acceleration.
m/s²
Hint: a = (v − u) ÷ t = (24 − 0) ÷ 8.
4.1 · Motion graphs

Distance–time graphs

On a distance–time graph, time is on the x-axis and distance on the y-axis, so the gradient = speed:

distance (m) time (s) steep = fast gradient = speed shallow = slow flat = stopped curve = accelerating
Steeper gradient → faster. A horizontal line means the object is stationary. A curve means the speed is changing (getting steeper = accelerating); take a tangent to find the speed at an instant.
4.1 · Motion graphs

Velocity–time graphs

On a velocity–time graph the gradient = acceleration, and the area under the line = distance travelled:

A: gradient = acceleration C: deceleration B: flat = constant velocity velocity (m/s) time (s) Δv Δt A B C area = distance shaded area = total distance travelled
A rising line is acceleration; a flat line is constant velocity; a falling line is deceleration. The shaded area under the whole line gives the total distance travelled.

Watch out: on a distance–time graph the gradient is velocity; on a velocity–time graph the gradient is acceleration and the area is distance. Mixing them up is the classic exam slip.

Quick check

Reading a velocity–time graph

?On a velocity–time graph, a line slopes steadily upward and then becomes horizontal. What does the horizontal part show?
Mission 1 check

How can one line tell the whole journey?

?A graph of speed against time shows a car braking. The line falls in a straight line from 20 m/s to 0 m/s in 4 s. How hard did it brake?
4.1 · Equation of motion

Uniform acceleration equation

When acceleration is uniform (constant), this equation links velocities, acceleration and distance — without needing the time:

v² = u² + 2 a xv = final velocity (m/s), u = initial velocity (m/s),
a = acceleration (m/s²), x = distance (m)
Worked example

A car starts from rest (u = 0) and accelerates at 2 m/s² over 25 m. Find its final velocity.

v² = u² + 2ax = 0 + 2 × 2 × 25 = 100

v = √100 = 10 m/s

With v = 0 and the same braking force, it gives braking distance ∝ speed²: double the speed and the distance needed to stop quadruples — a key safety idea you'll meet in 4.3.

Calculate

Your turn — v² = u² + 2ax

2A motorbike accelerates uniformly from rest at 2 m/s² over a distance of 25 m. Calculate its final velocity.
m/s
Hint: v² = 0 + 2 × 2 × 25 = 100, then v = √100.
Mission 2 of 4

Same push: why do the trolleys differ?

Make a guess: why does the same push move them so differently?

4.2 · Newton's first law

Newton's first law & inertia

A body stays at rest, or keeps moving at constant velocity in a straight line, unless acted on by a resultant force.

So if the forces on an object are balanced (no resultant force), its motion does not change. Inertia is this tendency to resist a change in motion; the greater the mass, the greater the inertia.

thrust drag balanced → constant velocity
When thrust = drag, the resultant force is zero — the car keeps a constant velocity, it does not slow down.

Watch out: balanced forces do not always mean "at rest". They mean no change in motion — a stationary object stays still and a moving one keeps the same velocity.

4.2 · Newton's second law

Newton's second law: F = ma

A resultant force changes an object's velocity — it causes acceleration. The acceleration depends on the force and the mass:

F = m aresultant force (N) = mass (kg) × acceleration (m/s²)

The bigger the resultant force, the greater the acceleration; the bigger the mass, the smaller the acceleration. Mass measured this way — its resistance to acceleration — is the object's inertial mass.

Worked example

A resultant force of 1500 N acts on a 600 kg dragster.

a = F ÷ m = 1500 ÷ 600 = 2.5 m/s²

Calculate

Your turn — F = ma

3A 1200 kg car accelerates at 2.5 m/s². Calculate the resultant force driving it forward.
N
Hint: F = m × a = 1200 × 2.5.
Mission 2 check

Same push: why do the trolleys differ?

?A 1000 kg car and a 3000 kg van are each pulled with the same resultant force of 3000 N. Which statement is correct?
4.2 · Newton's third law

Newton's third law

When two objects interact, they exert equal and opposite forces on each other.

The two forces of a "Newton pair" are the same size, opposite in direction, the same type, and crucially they act on different objects.

boat force on person force on boat equal size, opposite directions
Jump from a boat and you push the boat backwards; the boat pushes you forwards with an equal force. The two forces act on different objects.

Watch out: the two forces in a third-law pair never act on the same object, so they can't "cancel out". If they acted on one object, nothing would ever move.

Quick check

Spotting a Newton pair

?A swimmer pushes backwards on the water and shoots forwards. Which statement about this Newton's-third-law pair is correct?
Mission 3 of 4

What pushes the cannon backwards?

Make a guess: why does the cannon roll backwards?

4.2 · Momentum · Higher tier

Momentum

A moving object has momentum — the harder it is to stop or turn, the more momentum it has. It depends on mass and velocity:

p = m vmomentum (kg m/s) = mass (kg) × velocity (m/s)

Momentum is a vector (it has direction, like velocity). A heavy lorry at low speed can carry as much momentum as a light car at high speed.

Worked example

A 1500 kg car travels at 12 m/s.

p = m × v = 1500 × 12 = 18 000 kg m/s

Calculate · Higher

Your turn — momentum

4A 1500 kg car drives along a road at 12 m/s. Calculate its momentum.
kg m/s
Hint: p = m × v = 1500 × 12.
4.2 · Conservation of momentum · Higher tier

Conservation of momentum

In a closed system (no external forces), the total momentum before an event equals the total momentum after — for collisions and explosions:

total p (before) = total p (after)m₁u₁ + m₂u₂ = (m₁ + m₂)v   (for objects that stick together)
BEFORE 800 kg 6 m/s 400 kg at rest AFTER (joined) 800 kg 400 kg v = ?
800 kg × 6 m/s = 4800 kg m/s before. After they join: 4800 = 1200 × v, so v = 4 m/s.
Calculate · Higher

Your turn — conservation of momentum

5An 800 kg truck moving at 6 m/s collides with a stationary 400 kg truck and they couple together. Calculate their shared velocity afterwards.
m/s
Hint: (800 × 6) = (800 + 400) × v, so 4800 = 1200v.
Mission 3 check

What pushes the cannon backwards?

?A skater stands still on smooth ice, holding a heavy ball. She throws the ball forwards. What happens to her, and why?
4.2 · Higher tier only

Force = rate of change of momentum

Newton's second law can be written in terms of momentum (this equation is not on the Eduqas equation list, but it follows from F = ma with a = Δv ÷ t). The resultant force equals how fast the momentum changes:

F = Δ(mv) ÷ t = Δp ÷ tHIGHERforce (N) = change in momentum (kg m/s) ÷ time (s)

This is the key to vehicle safety: for a given change in momentum, spreading the change over a longer time means a smaller force.

Worked example

A passenger's momentum changes by 12 000 kg m/s during a crash that lasts 0.4 s.

F = Δp ÷ t = 12 000 ÷ 0.4 = 30 000 N

Make the stop last 0.8 s instead and the force halves to 15 000 N.

Calculate · Higher

Your turn — F = Δp ÷ t (Higher)

6In a crash a passenger's momentum changes by 12 000 kg m/s in 0.4 s. Calculate the force on the passenger.
N
Hint: F = Δp ÷ t = 12 000 ÷ 0.4.
Mission 4 of 4

Why does a distracted driver stop later?

Make a guess: why does a distracted driver need further to stop?

4.3 · Safety in public transport

Stopping distance

The total stopping distance of a vehicle is made of two parts:

stopping = thinking + brakingthinking distance (reaction) + braking distance (while brakes act)
thinking distance braking distance total stopping distance
Thinking distance is travelled during the driver's reaction time; braking distance is travelled while the brakes slow the car.
  • Thinking distance grows with speed and a longer reaction time (typically 0.2–0.9 s; measure it with a ruler-drop test) — increased by tiredness, distraction, alcohol or drugs.
  • Braking distance grows with speed (∝ speed² for the same braking force) and with poor conditions: wet/icy roads, worn tyres or brakes, and a heavier loaded vehicle.
Sort it

Thinking or braking distance?

Tap the part of the stopping distance that each factor mainly affects.

Mission 4 check

Why does a distracted driver stop later?

?Two identical cars travel at the same speed on the same dry road. One driver is looking at a phone when a hazard appears. Compared with the other car, what is true for the distracted driver's car?
4.3 · Vehicle safety

Why safety features work

In a crash a large change in momentum happens. Safety features all do the same job: they increase the time (and distance) over which a passenger stops, so by F = Δp ÷ t the force is reduced.

wall passenger crumple zone moving longer stopping time → smaller force F = Δp ÷ t
The crumple zone deforms on impact, lengthening the stopping time and lowering the force on the people inside.
  • Crumple zones — fold and deform, extending the time the car takes to stop.
  • Seatbelts — stretch slightly, increasing the distance and time over which you stop.
  • Air bags — inflate so your head decelerates over a longer time against the bag.

Watch out: these features don't reduce the change in momentum — that's fixed by your mass and speed. They reduce the force by making the stop take longer.

Quick check

Explaining a safety feature

?An air bag inflates in a crash. Using physics, why does this reduce the chance of injury?
Recap

The equations to know

Speed/velocity: v = x ÷ t

Acceleration: a = Δv ÷ t = (v − u) ÷ t

Uniform acceleration (from the equation list): v² = u² + 2 a x

Newton's second law: F = m a

Momentum (Higher): p = m v  (conserved in a closed system)

Force & momentum (Higher, from F = ma): F = Δp ÷ t

You've covered the key ideas across the three parts of Eduqas Topic 4 — speed, velocity, acceleration & motion graphs; forces, accelerations & Newton's laws; and safety in public transport. Press Finish to see your score.

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