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Edexcel GCSE Physics (1PH0) · Topic 14 — Particle model
Mini-Lesson

Particle model

This mini-lesson walks you through the whole of Edexcel Topic 14 — Particle model: density, the three states of matter, changes of state, specific heat capacity, specific latent heat, and how moving particles create gas pressure.

solid liquid gas
The same particles in all three states — only their arrangement and energy differ.

Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Press Start when you're ready.

Kinetic theory · 14.1

Three states of matter

The kinetic theory model pictures all matter as tiny particles in constant motion. Edexcel wants you to describe each state by the arrangement, movement and energy of its particles:

  • Solid — particles packed in a regular, fixed pattern, touching, vibrating about fixed positions. Lowest energy. Fixed shape and volume.
  • Liquid — particles still touching but randomly arranged, able to slide past each other. More energy. Fixed volume, takes the shape of its container.
  • Gas — particles far apart, random, moving quickly in all directions. Most energy. Fills any container; easily compressed.
SOLID regular · vibrate in place LIQUID touching · slide past GAS far apart · fast & random
Solid → liquid → gas: spacing increases, and particle energy increases.
Quick check

Which state?

?In which state are the particles arranged in a regular pattern, only able to vibrate about fixed positions?
Equation · 14.2 / 14.4

Density

Density tells you how much mass is packed into a given volume. It depends on the mass of the particles and how closely packed they are:

ρ = m ÷ Vdensity (kg/m³) = mass (kg) ÷ volume (m³)

Because particles are packed tightly in a solid and a liquid but spread far apart in a gas, the same substance is usually densest as a solid and least dense as a gas.

Watch your units. The SI unit is kg/m³, but lab data often comes in g/cm³. Use the same units throughout, and remember 1 g/cm³ = 1000 kg/m³ (water is 1.0 g/cm³ = 1000 kg/m³).

Worked example

A metal block has mass 600 g and volume 75 cm³.

ρ = m ÷ V = 600 ÷ 75 = 8 g/cm³ (= 8000 kg/m³)

Calculate

Your turn — density

1A block of wood has a mass of 240 g and a volume of 300 cm³. Calculate its density in g/cm³.
g/cm³
Hint: ρ = m ÷ V = 240 ÷ 300. The answer is less than 1, so the wood floats on water.
Core Practical · 14.3

Measuring density

Edexcel's Core Practical is to investigate the densities of solid and liquids. You always need a mass (balance) and a volume.

  • Liquid: place a measuring cylinder on a balance, zero it, pour the liquid in. Read the mass and the volume straight off.
  • Regular solid: weigh it, then measure its sides and calculate the volume.
  • Irregular solid: weigh it, then find its volume by displacement — lower it into water and measure the volume of water pushed out (e.g. with a eureka/displacement can).
collected = volume of object irregular solid Then: ρ = mass ÷ volume mass from a balance, volume from displaced water
Water displacement: the volume of water pushed out equals the volume of the object.
Changes of state · 14.5

Changes of state are physical

Melting, freezing, boiling, evaporating, condensing and subliming are all changes of state. They are physical changes, not chemical:

  • Mass is conserved — no particles are created or destroyed, so the mass stays exactly the same.
  • They are reversible — the material recovers its original properties if the change is reversed (unlike many chemical changes, which make new substances).
solid liquid gas melting freezing boiling / evaporating condensing sublimation (solid ⇄ gas)
Every arrow is reversible, and the mass never changes.

Misconception: ice melting to water is not a chemical reaction. It's still H₂O — cool it down and the water freezes straight back to ice with its original properties. Mass in = mass out.

Quick check

Physical, not chemical

?A 20 g ice cube melts completely into water in a sealed dish. What is the mass of the water?
Internal energy · 14.6

Heating changes stored energy

The internal energy of a substance is the total energy stored in its particles (their movement and their positions). When you heat a system, that stored energy increases, and one of two things happens:

  • the particles speed up, so the temperature rises; or
  • at a melting or boiling point, the energy goes into breaking bonds between particles — a change of state — and the temperature stays constant while it does.
temperature time / energy supplied → melting m.p.  boiling b.p.  solid liquid gas
On the flat plateaus, energy goes into changing state, so the temperature does not rise.

Misconception: the temperature does not keep climbing while something melts or boils. During a change of state the temperature pauses even though you keep supplying energy.

Equation · 14.7 / 14.8

Specific heat capacity

The specific heat capacity, c, is the energy needed to raise the temperature of 1 kg of a substance by 1 °C. To warm a mass m by a temperature change Δθ:

ΔQ = m c Δθchange in thermal energy (J) = mass (kg) × specific heat capacity (J/kg°C) × temperature change (°C)

Water has a high specific heat capacity (4200 J/kg°C), so it takes a lot of energy to warm up and is slow to cool — which is why it makes a good coolant and hot-water bottle.

Worked example

Heating 0.5 kg of water (c = 4200 J/kg°C) by 30 °C:

ΔQ = m c Δθ = 0.5 × 4200 × 30 = 63 000 J (63 kJ)

Calculate

Your turn — heat capacity

2How much thermal energy is needed to raise the temperature of 2 kg of copper (c = 385 J/kg°C) by 50 °C?
J
Hint: ΔQ = m c Δθ = 2 × 385 × 50.
Core Practical · 14.11

Investigating water

The second Core Practical is to investigate the properties of water: determine the specific heat capacity of water and obtain a temperature–time graph for melting ice.

  • Heat a known mass of water with an electric immersion heater, using a joulemeter (or power × time) for the energy ΔQ supplied and a thermometer for the temperature change Δθ.
  • Rearrange ΔQ = m c Δθ to get c = ΔQ ÷ (m Δθ).
  • For melting ice, plot temperature against time: the line is flat at 0 °C while the ice melts, then rises again once it is all liquid.

Why your value comes out a bit high: some energy escapes to the surroundings instead of going into the water, so the measured c is usually a little larger than the true 4200 J/kg°C. Insulating the beaker reduces this.

Equation · 14.7 / 14.9

Specific latent heat

To change the state of a substance you must supply energy without changing its temperature. The specific latent heat, L, is the energy needed to change the state of 1 kg of a substance:

Q = m Lthermal energy for a change of state (J) = mass (kg) × specific latent heat (J/kg)

This energy goes into separating the particles (breaking bonds), not into making them move faster — so the thermometer stays still during melting or boiling.

Analogy: latent heat is like paying to unlock the particles from one another. While you are paying the "unlock fee", the temperature pauses; only once they're free does heating start to raise the temperature again.

Worked example

Melting 0.2 kg of ice (specific latent heat of fusion L = 334 000 J/kg):

Q = m L = 0.2 × 334 000 = 66 800 J

Calculate

Your turn — latent heat

3How much energy is needed to boil away 0.5 kg of water already at 100 °C? (specific latent heat of vaporisation L = 2 260 000 J/kg)
J
Hint: it's already at 100 °C, so use Q = m L = 0.5 × 2 260 000.
Gas pressure · 14.12

Where gas pressure comes from

Gas particles fly about randomly and constantly collide with the walls of their container. Each collision pushes on the wall; the combined effect of billions of collisions per second is the gas pressure.

force on walls random motion
Each bounce off a wall is a tiny push; together they make the pressure.

Analogy: imagine hundreds of bouncy balls drumming on the inside of a box. You don't feel the individual hits — you feel a steady outward push. That steady push is gas pressure.

Temperature · 14.13

Heat a gas, raise its pressure

The temperature of a gas is a measure of the average kinetic energy of its molecules. Heat a fixed mass of gas in a sealed, rigid container (constant volume) and:

  • the particles gain kinetic energy and move faster;
  • they hit the walls harder and more often;
  • so the pressure rises.

This is a qualitative link for Edexcel: higher temperature → faster particles → more frequent, harder collisions → higher pressure (volume kept constant).

Quick check

Reading the collisions

?A sealed rigid can of gas is heated. The volume cannot change. Why does the pressure inside rise?
Absolute zero · 14.14 / 14.15

Absolute zero & the kelvin scale

Absolute zero is −273 °C — the lowest possible temperature, where particles have the least possible movement (their kinetic energy is as low as it can be).

The kelvin temperature scale starts there: 0 K = −273 °C. To convert between the scales:

K = °C + 273e.g. 27 °C → 300 K, and 0 °C → 273 K
−273 °C 0 K absolute zero 0 °C 273 K ice melts 27 °C 300 K warm room
Calculate

Your turn — converting temperatures

4A gas is at a temperature of 47 °C. Convert this to the kelvin scale.
K
Hint: K = °C + 273 = 47 + 273.
Physics only · 14.16–14.19

Squeezing a gas (separate Physics)

A gas can be compressed or expanded by changing the pressure, and its pressure produces a net force at right angles to any surface. For a fixed mass of gas at constant temperature:

  • Squeeze the gas into a smaller volume → particles hit the walls more often (less distance to travel) → higher pressure.
  • Let it expand → collisions become less frequent → lower pressure.
P₁ × V₁ = P₂ × V₂at constant temperature for a fixed mass of gas
Worked example

Gas at 100 kPa fills 0.40 m³. It is squeezed to 0.10 m³ at constant temperature.

P₂ = (P₁V₁) ÷ V₂ = (100 × 0.40) ÷ 0.10 = 400 kPa

Calculate

Your turn — pressure & volume

5A fixed mass of gas at 200 kPa occupies 0.60 m³. At constant temperature it is compressed to 0.20 m³. Calculate the new pressure.
kPa
Hint: P₂ = (P₁V₁) ÷ V₂ = (200 × 0.60) ÷ 0.20.
Higher Tier · 14.20

Doing work on a gas warms it

Pushing in a piston (or pumping up a tyre) does work on the gas. That work is transferred to the particles, increasing their kinetic energy — so the gas gets hotter, even with no flame in sight.

This is why a bicycle pump feels warm after you've used it: as you compress the air, you do work on it and its temperature rises.

push (work done) gas warms up faster particles
Work in → more kinetic energy → higher temperature (no heating needed).
Sort it

Spot the state

Tap the state of matter that each description fits best.

Sort it

Which equation?

Tap a situation, then tap the equation you'd use.

🌡️ ΔQ = m c Δθ
(temperature change)

🔓 Q = m L
(change of state)

Quick check

Squeezing at constant temperature

?A fixed mass of gas is squeezed into half the volume at constant temperature. What happens to its pressure?
Recap

The equations to know

Density: ρ = m ÷ V

Heating (temperature change): ΔQ = m c Δθ

Change of state (latent heat): Q = m L

Kelvin conversion: K = °C + 273

Gas (constant temperature, Physics only): P₁V₁ = P₂V₂

You've covered the whole of Edexcel Topic 14 — density and states of matter, changes of state, internal energy, specific heat capacity and latent heat, and gas pressure including the Higher Tier work-on-a-gas idea. Press Finish to see your score.

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Mini-lesson complete!

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