This mini-lesson walks you through the whole of CCEA Unit 1.1 — Motion: speed, distance and time, the difference between scalars and vectors, displacement, velocity and acceleration, and how to read motion graphs.
How far (distance) and how fast (speed) — measured over a span of time.
Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Press Start when you're ready.
Quantities & SI units · 1.1.1
The quantities of motion
Every motion measurement is a physical quantity with a number and a unit. CCEA uses these SI units:
Distance (and displacement) — measured in metres (m).
Speed (and velocity) — measured in metres per second (m/s).
Rate of change of speed (acceleration) — measured in metres per second squared (m/s²).
Time — measured in seconds (s).
Everyday speeds: a person walks at roughly 1.5 m/s, a sprinter runs at around 10 m/s, and a car on a town road travels near 13 m/s (about 30 mph). Knowing these helps you sense-check an answer.
Quick check
Match the unit
?In CCEA's SI units, which is the correct unit for the rate of change of speed (acceleration)?
Speed & average speed · 1.1.1
Speed = distance ÷ time
Speed tells you how quickly an object covers distance. CCEA wants you to recall and use the average speed equation:
average speed = distance moved ÷ time takenaverage speed (m/s) = distance moved (m) ÷ time taken (s)
There is a second form CCEA lists for steady changes of speed — the average of the start and end speeds:
average speed = (initial speed + final speed) ÷ 2useful when speed changes at a steady rate
Worked example
A cyclist travels 300 m in 25 s.
average speed = 300 ÷ 25 = 12 m/s
Calculate
Your turn — average speed
1A train covers a distance of 1500 m in 60 s. Calculate its average speed.
m/s
Hint: average speed = distance ÷ time = 1500 ÷ 60.
Scalars & vectors · 1.1.3 · Higher tier
Scalars vs vectors
A scalar has size only. A vector has size and direction. CCEA pairs them up:
Distance is a scalar; displacement is a vector — both in metres (m).
Speed is a scalar; velocity is a vector — both in m/s.
Rate of change of speed is a scalar; acceleration is a vector — both in m/s².
Walk a curving path and your distance is the whole route; your displacement is the straight arrow from start to end.
Watch out: distance and displacement are only equal when the motion is in a perfectly straight line. Walk a full lap of a track and your distance is 400 m, but your displacement is zero — you finished where you started.
Sort it
Scalar or vector?
Tap a quantity, then tap the box it belongs in.
📏 Scalar (size only)
🧭 Vector (size + direction)
Velocity · 1.1.4 · Higher tier
Velocity is rate of change of displacement
Where speed only says "how fast", velocity says "how fast and in which direction". CCEA defines it through displacement:
average velocity = displacement ÷ timeaverage velocity (m/s) = displacement (m) ÷ time (s)
For a steady change of velocity in one direction, you can also use the average of the start and end velocities:
average velocity = (initial velocity + final velocity) ÷ 2CCEA only sets problems on motion in one direction
Watch out: two cars can have the same speed (30 m/s) but different velocities if they travel in different directions. Velocity is a vector — change the direction and you change the velocity, even if the speed stays the same.
Calculate
Your turn — average velocity
2A runner has a displacement of 180 m due north in a time of 24 s. Calculate her average velocity.
m/s
Hint: average velocity = displacement ÷ time = 180 ÷ 24.
Acceleration · 1.1.4–1.1.5 · Higher tier
Acceleration = change in velocity ÷ time
Acceleration is how quickly velocity changes. For motion in one direction:
a = (v − u) ÷ tacceleration (m/s²) = (final velocity − initial velocity) ÷ time taken
Watch out: acceleration is the change in velocity, not the velocity itself. An object can be moving fast yet have zero acceleration (steady velocity). A negative acceleration — slowing down — is called retardation in CCEA.
Worked example
A car speeds up from u = 8 m/s to v = 20 m/s in t = 4 s.
a = (20 − 8) ÷ 4 = 12 ÷ 4 = 3 m/s²
Calculate
Your turn — acceleration
3A motorbike accelerates from rest (u = 0) to a final velocity v = 18 m/s in a time of 6 s. Calculate its acceleration.
m/s²
Hint: a = (v − u) ÷ t = (18 − 0) ÷ 6.
Distance–time graphs · 1.1.6
Distance–time graphs: slope = speed
On a distance–time graph the gradient (slope) is the speed. The steeper the line, the faster the object. A flat line means it is stationary.
Gradient of the sloped part = 40 m ÷ 10 s = 4 m/s. The flat section means the object has stopped.Read the graph
Reading a distance–time graph
?On a distance–time graph, an object's line is perfectly horizontal (flat) for 8 seconds. What is happening during that time?
Velocity–time graphs · 1.1.6–1.1.7 · Higher tier
Velocity–time graphs: slope & area
A velocity–time graph packs in two pieces of information CCEA expects you to extract:
the slope (gradient) is the acceleration;
the area under the line is the distance moved (displacement).
Gradient = 12 ÷ 6 = 2 m/s² (acceleration). Shaded area = distance: triangle (½×6×12 = 36 m) + rectangle (4×12 = 48 m) = 84 m.
Watch out: don't confuse the two graphs. On a distance–time graph the slope is the speed; on a velocity–time graph the slope is the acceleration and the area underneath is the distance.
Read the graph
Your turn — gradient of a v–t graph
4On a velocity–time graph, a straight line rises from 4 m/s to 28 m/s over a time of 8 s. Calculate the acceleration (the gradient).
5A car moves at a steady velocity of 15 m/s for 12 s. On its velocity–time graph this is a flat line. Find the distance moved (the area under the line).
m
Hint: the area is a rectangle = velocity × time = 15 × 12.
Calculate
Your turn — rearranging speed
6A jogger runs at an average speed of 4 m/s for 90 s. Calculate the distance moved.
m
Hint: rearrange speed = distance ÷ time → distance = speed × time = 4 × 90.
Match it
Which graph tells you what?
Tap a feature on the left, then its meaning on the right.
Recap
The relationships to know
Average speed: distance moved ÷ time taken
Average speed (steady change): (initial speed + final speed) ÷ 2
Average velocity: displacement ÷ time (Higher)
Acceleration: a = (v − u) ÷ t (Higher)
Distance–time graph: slope = speed
Speed–time / velocity–time graph: slope = acceleration; area = distance moved
Scalars vs vectors: distance/speed = scalar; displacement/velocity/acceleration = vector (Higher)
You've covered the whole of CCEA Unit 1.1 — Motion: quantities and units, speed and average speed, scalars and vectors, displacement, velocity and acceleration, and motion graphs. Press Finish to see your score.
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