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IB Diploma Mathematics: Applications & Interpretation HL · Number & Algebra
Mini-Lesson

Number & Algebra (HL)

This HL mini-lesson takes Number & Algebra to full depth: all the SL toolkit (error, standard form, sequences, financial maths, logs) plus the HL extensionscomplex numbers (Cartesian and modulus–argument form, used to model AC circuits), solving systems of equations with matrices, and deeper amortisation.

AI HL flavour: complex numbers appear as phasors/impedance in electrical engineering, and matrices solve linear systems efficiently.

Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Every number on the calculation screens has been re-derived and checked. Press Start when you are ready.

Complex numbers

Cartesian form & the complex plane

A complex number z = a + bi has real part a and imaginary part b, where i² = −1. It is a point (a, b) on the Argand diagram.

modulus |z| = √(a² + b²)argument arg(z) = tan⁻¹(b ⁄ a) (correct quadrant)
Worked example

z = 3 + 4i.

|z| = √(3² + 4²) = √25 = 5

arg(z) = tan⁻¹(4 ⁄ 3) = 53.13°

Calculate

Your turn — modulus

1Find the modulus |z| of the complex number z = 3 + 4i.
Hint: |z| = √(3² + 4²).
Calculate

Your turn — argument

2Find the argument arg(z) of z = 3 + 4i, in degrees to 2 decimal places.
°
Hint: tan⁻¹(4 ⁄ 3).
AC circuits

Complex numbers as impedance

In AC circuit analysis, each component has a complex impedance Z. Impedances in series add like complex numbers, and |Z| is the magnitude of the total opposition to current.

Worked example — series impedance

Z₁ = 3 + 4i (Ω), Z₂ = 5 − 2i (Ω).

Z = Z₁ + Z₂ = (3 + 5) + (4 − 2)i = 8 + 2i

|Z| = √(8² + 2²) = √68 = 8.25 Ω (2 d.p.)

The argument of Z is the phase angle between voltage and current — a genuine engineering use of complex numbers.

Calculate

Your turn — total impedance

3Two series impedances are Z₁ = 3 + 4i and Z₂ = 5 − 2i (ohms). Find the magnitude |Z| of the total impedance Z₁ + Z₂, to 2 decimal places.
Ω
Hint: add to get 8 + 2i, then |Z| = √(8² + 2²).
Systems & matrices

Solving linear systems with matrices

A linear system can be written Ax = b and solved with the inverse matrix (when det A ≠ 0): x = A⁻¹b. Your GDC does this directly.

Worked example

2x + y = 5 and 3x + 4y = 10.

A = [[2, 1], [3, 4]], det A = 2×4 − 1×3 = 5 ≠ 0.

Solution: x = 2, y = 1

If det A = 0 the system has no unique solution (either none or infinitely many).

Calculate

Your turn — solve the system

4Solve the system 2x + y = 5, 3x + 4y = 10 and enter the value of x.
Hint: use matrices or elimination; det = 5, and x works out to a whole number.
Quick check

When is a system uniquely solvable?

?The matrix system Ax = b has a unique solution when:
Financial maths

Amortisation & annuities at HL

HL expects fluent use of the finance solver for loan amortisation and annuities. A loan L at periodic rate i over N periods needs equal repayments:

PMT = L·i ÷ (1 − (1 + i)−N)future value of savings: FV = PMT·((1+i)N − 1)⁄i
Worked example

Loan L = $15 000 at 6%/yr compounded monthly (i = 0.005) over 5 years (N = 60).

PMT = 15000 × 0.005 ÷ (1 − 1.005⁻⁶⁰) = $289.99 per month

Calculate

Your turn — loan repayment

5A $15 000 loan at 6% per year compounded monthly (i = 0.005) is repaid over 5 years (N = 60). Find the monthly repayment PMT = L·i ÷ (1 − (1+i)⁻ᴺ), to the nearest cent.
$
Hint: 15000 × 0.005 ÷ (1 − 1.005^−60).
Sort it

HL Number & Algebra sort

Tap an object, then the concept it belongs to.

🔢 Complex number

🔲 Matrix / system

💷 Financial

Quick check

Modulus meaning

?For a complex impedance Z, the modulus |Z| represents the:
Quick check

Standard form check

?In standard form, 6 × 105 equals:
Match it

Match the HL object to its formula

Tap an item on the left, then its match on the right.

Item
Match
Complex arithmetic

Adding & multiplying complex numbers

Add/subtract by combining real and imaginary parts; multiply using i² = −1.

Worked example

(3 + 4i) + (5 − 2i) = 8 + 2i.

(1 + 2i)(3 + i) = 3 + i + 6i + 2i² = 3 + 7i − 2 = 1 + 7i

Sequences in finance

Sequences behind the finance formulas

Compound interest is a geometric sequence (ratio 1 + i); an amortised loan is a geometric series of discounted payments. The finance solver just automates these.

Understanding the sequence behind each formula helps you check GDC answers for sense.

Quick check

Powers of i

?Using i² = −1, the value of i³ is:
Recap

The big ideas to take away

Complex numbers: z = a + bi; |z| = √(a²+b²), arg = tan⁻¹(b⁄a)

AC circuits: series impedances add as complex numbers

Matrices: Ax = b solved by x = A⁻¹b when det A ≠ 0

Financial: amortisation PMT = Li⁄(1 − (1+i)⁻ᴺ)

SL toolkit: error, standard form, sequences, logs all still assessed

GDC: use the complex, matrix and finance solvers fluently

You have worked through the whole topic. Press Finish to see your score.

🏆

Mini-lesson complete!

⭐⭐⭐

You have covered HL Number & Algebra (with complex numbers and matrices) for AI. 🎉

Your stars: 0 / 0

Next: test yourself in the Evaluate stage, then lock it in with Verify.

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