This HL mini-lesson develops the calculus core: differentiation (power rule, tangents, optimisation), kinematics, integration as anti-derivative and area, the area between curves, and numerical estimation with the trapezoidal rule. (Differential equations, slope fields and Euler's method are in the dedicated HL lesson.)
AI HL flavour: calculus is used for rates, totals and areas — with numerical methods when an exact integral is hard.
Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Every number on the calculation screens has been re-derived and checked. Press Start when you are ready.
Differentiation
The power rule & gradients
f(x) = a xn ⇒ f′(x) = a n xn−1differentiate term by term
Worked example
f(x) = 3x² − 4x + 1 ⇒ f′(x) = 6x − 4.
f′(2) = 6×2 − 4 = 8
Calculate
Your turn — derivative value
1For f(x) = 3x² − 4x + 1, find f′(2).
Hint: f′(x) = 6x − 4.
Optimisation
Tangents, stationary points & optimisation
Increasing where f′(x) > 0; decreasing where f′(x) < 0.
Stationary points where f′(x) = 0 (max/min).
Tangent at x = a has gradient f′(a).
Optimisation: model the quantity, set f′ = 0, and verify max or min (sign of f′ either side, or the second derivative).
Quick check
Stationary points
?At a smooth maximum or minimum, the derivative f′(x) equals:
Kinematics
Displacement, velocity & acceleration
v = ds ⁄ dt · a = dv ⁄ dtreverse by integrating
Worked example
s(t) = t³ − 3t²: v(t) = 3t² − 6t, a(t) = 6t − 6.
v(4) = 48 − 24 = 24 m/s; a(4) = 24 − 6 = 18 m/s²
Calculate
Your turn — velocity
2For s(t) = t³ − 3t², find v = ds⁄dt at t = 4 (m/s).
m/s
Hint: v(t) = 3t² − 6t at t = 4.
Integration
Anti-derivative & definite integral
∫ a xn dx = a xn+1 ⁄ (n+1) + C∫ab f dx = F(b) − F(a)
Worked example
∫₁³ (2x + 1) dx = [x² + x]₁³ = 12 − 2 = 10
Calculate
Your turn — definite integral
3Evaluate ∫₁³ (2x + 1) dx.
Hint: antiderivative x² + x; (9+3) − (1+1).
Area between curves
Area enclosed by two curves
The area between y = f(x) (upper) and y = g(x) (lower) from a to b is ∫ab [f(x) − g(x)] dx.
Worked example
Between y = x (upper) and y = x² (lower) from 0 to 1: