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CCEA GCE Mathematics (2210) · Vectors
Mini-Lesson

Vectors

1 mission. Guess, learn, then check. Your place is saved.

  1. Mission 1A plane heads north at 200 km/h in a 50 km/h east wind. Where to?
Mission 1

A plane heads north at 200 km/h in a 50 km/h east wind. Where to?

Make a guess: A plane heads north at 200 km/h in a 50 km/h east wind. Where to?

Vectors · two dimensions

What a vector is

Vector as a displacement1234512345OxyAB32OA(1,1)B(4,3)
  • A vector has size (magnitude) and direction; a scalar has size only. Velocity is a vector; speed is a scalar.
  • Write a vector as a column vector ( 3 ; 2 ) or with unit vectors 3i + 2j, where i is one unit in the x-direction and j one unit in the y-direction.
  • Print uses bold a; by hand, underline it: a.
  • The movement from A to B is AB→. In the diagram, AB→ = 3i + 2j.
Vectors · two dimensions

Magnitude and direction

  • The magnitude of a = xi + yj is its length, by Pythagoras:
|a| = √(x² + y²)
  • Its direction comes from tan θ = y/x. Sketch the vector first so you put the angle in the right quadrant.
  • Give the direction as an angle with i (or a bearing in context), saying which way it is measured.
  • Example: 3i + 4j has magnitude 5 and makes 53.1° with i.
Worked example Vectors · two dimensions

Magnitude and direction of a vector

Components of a vector−2246−14−12−10−8−6−4−22Oxya512θ
Question
Find the magnitude and direction of a = 5i − 12j.
  1. 1
    Magnitude by Pythagoras: |a| = √(5² + (−12)²) = √169 = 13
  2. 2
    Sketch: 5 right and 12 down, so a points below the positive x-axis
  3. 3
    Angle below the axis: tan⁻¹12/5 = 67.4°
  4. 4
    Measured anticlockwise from the positive x-axis: 360° − 67.4° = 292.6°
Answer
|a| = 13; direction 67.4° below i (that is, 292.6° anticlockwise from the positive x-axis)
⚠️ Watch out
a calculator gives tan⁻¹(−12/5) = −67.4° for any vector with this ratio, including −5i + 12j. Only the sketch tells you the quadrant.
Calculate
?A force of 20 N acts at 30° above the direction of i. Write it as ai + bj and give a to 3 significant figures.
Vectors · two dimensions

Adding vectors and position vectors

  • Add or subtract component by component; a scalar multiplies every component. Geometrically, vectors add tip to tail (triangle law).
  • a and b are parallel if b = ka for some scalar k.
  • The position vector of A is OA→ = a, from the origin O.
AB→ = b − a
  • The distance AB is the magnitude |b − a|.
Worked example Vectors · two dimensions

Distance and the fourth corner of a parallelogram

Question
A, B and C have position vectors 2i − j, 7i + 11j and 10i + 4j. Find the distance AB, and the position vector of D such that ABCD is a parallelogram.
  1. 1
    AB→ = b − a = 5i + 12j, so AB = √(5² + 12²) = 13
  2. 2
    In parallelogram ABCD, AD→ = BC→
  3. 3
    BC→ = c − b = 3i − 7j
  4. 4
    d = a + BC→ = (2i − j) + (3i − 7j)
Answer
AB = 13 and d = 5i − 8j
⚠️ Watch out
the letters go round in order. AD→ equals BC→, not CB→.
Quick check
?Points A and B have position vectors a = 3i − 2j and b = −i + 4j. Find AB→.
Vectors · two dimensions

Unit vectors and vectors in mechanics

  • Forces, velocities and displacements are vectors. The resultant of several forces is their vector sum.
  • Two velocities combine the same way: a plane's velocity through the air plus the wind's velocity gives its velocity over the ground.
  • In a bearing problem, take i as east and j as north.
Calculate
?Two forces F₁ = (2i + 3j) N and F₂ = (pi − 5j) N act on a particle. Their resultant is parallel to 3i − j. Find the value of p.
Mission check

?A plane heads north at 200 km/h in a 50 km/h wind blowing towards the east. How does it actually move?
Recap

Big ideas

  • A 2-D vector is xi + yj or ( x ; y ); its magnitude is √(x² + y²) and its direction comes from tan θ = y/x with a sketch.
  • Add vectors component by component (tip to tail); AB→ = b − a and the distance AB = |b − a|.
  • Forces and velocities are vectors: their resultant is the vector sum.
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  1. Mission 1A plane heads north at 200 km/h in a 50 km/h east wind. Where to?

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Specification points and sources for this lesson are listed at the bottom of the page.

Sources (1)

The specification points and sources behind this lesson.

  1. 1 CCEA GCE Mathematics (2018) specification, Unit AS 1 Pure Mathematics, Vectors