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IB Diploma Physics HL · Themes D.1–D.3 Fields
Mini-Lesson

Fields

This mini-lesson covers Themes D.1–D.3 — Fields: gravitational fields and Newton's law, electric fields and Coulomb's law, magnetic fields, and the motion of charges in electric and magnetic fields.

gravitational g electric E magnetic forces

Work through each screen, answer the questions as you go (some are reasoning, some are calculations) and collect ⭐ stars. Watch for the HL flag on higher-level extensions. Press Start when you're ready.

D.1 · gravity

Gravitational fields

A field is a region where a mass or charge feels a force. Gravitational field strength g is the force per unit mass. Newton's law of gravitation and the field of a point/spherical mass are inverse-square:

F = GMm ÷ r² · g = F ÷ m = GM ÷ r²G = 6.67 × 10⁻¹¹ N m² kg⁻²

Gravity is always attractive and acts on mass. Because g ∝ 1/r², doubling the distance from a planet's centre quarters the field strength.

Quick check

Quick check

?At the surface of a planet the gravitational field strength is g. What is it at a distance of two planet-radii from the centre?
Calculate

Calculate

#Find the gravitational field strength at Earth's surface. Use M = 5.97 × 10²⁴ kg, r = 6.37 × 10⁶ m, G = 6.67 × 10⁻¹¹.
N kg⁻¹
Hint: g = GM ÷ r² = 6.67e-11 × 5.97e24 ÷ (6.37e6)².
D.2 · electric

Electric fields & Coulomb's law

Electric field strength E is the force per unit positive charge. Coulomb's law gives the force between point charges, and a point charge produces a radial field:

F = kQ₁Q₂ ÷ r² · E = F ÷ q = kQ ÷ r²k = 8.99 × 10⁹ N m² C⁻²

Unlike gravity, electric forces can attract or repel: like charges repel, unlike attract. Field lines point away from positive charge and towards negative.

Calculate

Calculate

#Two charges, 3.0 µC and 2.0 µC, are 0.10 m apart. Find the electrostatic force between them. (k = 8.99 × 10⁹.)
N
Hint: F = kQ₁Q₂ ÷ r² = 8.99e9 × 3.0e-6 × 2.0e-6 ÷ 0.10².
Calculate

Calculate

#A charge of 2.0 µC feels a force of 6.0 mN (6.0 × 10⁻³ N) in an electric field. Find the field strength.
N C⁻¹
Hint: E = F ÷ q = 6.0e-3 ÷ 2.0e-6.
D.2–D.3 · magnetic

Magnetic fields & forces

A magnetic field exerts a force on a moving charge or a current. The force is perpendicular to both the field and the velocity/current (Fleming's left-hand rule):

F = BIL · F = qvBwire of length L carrying current I · charge q moving at speed v

Because the magnetic force on a moving charge is always perpendicular to its velocity, it does no work — it changes direction, not speed, making charges move in circles.

Calculate

Calculate

#A 0.20 m wire carries 5.0 A at right angles to a 0.40 T magnetic field. Find the force on it.
N
Hint: F = BIL = 0.40 × 5.0 × 0.20.
Quick check

Quick check

?A magnetic field does no work on a charged particle moving through it. Why?
Sort it

Which field does this describe?

Tap an item, then tap the group it belongs to.

🌍 Gravitational

⚡ Electric

🧲 Magnetic

Match it

Match the law to its equation

Tap a statement on the left, then its match on the right.

Statement
Answer
D.1 · HL depth

Potential, energy & orbits

At HL fields are described by potential — the potential energy per unit mass or charge. For a point mass and point charge:

V_g = −GM ÷ r · V_e = kQ ÷ rfield strength is the negative gradient of potential

Gravitational potential energy E_P = −GMm/r. The escape speed (KE just enough to reach r → ∞) and a circular orbital speed are:

v_escape = √(2GM ÷ r) · v_orbit = √(GM ÷ r)a bound orbit has total energy E = −GMm ÷ 2r

Gravitational potential is always negative and rises to zero at infinity; you must do positive work to lift a mass away.

Calculate

Calculate

#HL: find the escape speed from Earth's surface, in km s⁻¹. Use M = 5.97 × 10²⁴ kg, r = 6.37 × 10⁶ m.
km s⁻¹
Hint: v = √(2GM ÷ r) = √(2 × 6.67e-11 × 5.97e24 ÷ 6.37e6), then ÷1000.
Calculate

Calculate

#HL: find the orbital speed of a satellite at radius 7.0 × 10⁶ m from Earth's centre, in km s⁻¹.
km s⁻¹
Hint: v = √(GM ÷ r) = √(6.67e-11 × 5.97e24 ÷ 7.0e6), then ÷1000.
Recap

The big ideas to know

Gravitational: g = GM/r²; F = GMm/r²; attractive, acts on mass

Electric: E = kQ/r²; F = kQ₁Q₂/r²; attracts or repels

Magnetic: F = BIL and F = qvB; force ⟂ velocity, so does no work

Inverse square: doubling r quarters both gravitational and electric field

HL: potential V = −GM/r (grav) or kQ/r; v_escape = √(2GM/r)

That completes Fields for IB Diploma Physics HL. Press Finish to see your score.

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