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AQA GCSE Physics (8463) · Topic 4.3 — Particle Model of Matter
Mini-Lesson

Particle Model of Matter

This mini-lesson walks you through the whole of AQA Topic 4.3 — Particle Model of Matter: density, the three states and how particles are arranged, changes of state, internal energy, specific heat capacity and latent heat, and how gas particles create pressure.

solid · vibrate in place liquid · slide past gas · fast & random
Same particles, different arrangements: solid (regular, packed, vibrating), liquid (close, irregular, sliding), gas (far apart, fast, random). The arrangement explains density, melting, boiling and pressure.

Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Press Start when you're ready.

Density

Density packs mass into volume

Density tells you how much mass is squeezed into a given volume. A dense material has a lot of mass in a small space.

ρ = m ÷ Vdensity (kg/m³) = mass (kg) ÷ volume (m³)

The symbol ρ is the Greek letter "rho". Density can also be quoted in g/cm³ — just keep your units consistent.

Worked example

A metal block has a mass of 240 g and a volume of 30 cm³.

ρ = 240 ÷ 30 = 8 g/cm³

Density · particle arrangement

Why solids are densest

The particle model explains why the same substance is usually densest as a solid and least dense as a gas:

  • Solid — particles in a regular pattern, touching, only vibrating in fixed positions. Most particles per volume → highest density.
  • Liquid — particles close together but random, able to move/flow past each other. Slightly less dense than the solid.
  • Gas — particles far apart, random and moving fast. Very few particles per volume → lowest density.

Required practical: find density with a balance and ρ = m ÷ V. For a regular solid, measure sides and calculate the volume. For an irregular solid or a liquid, use a eureka (displacement) can — the volume of water pushed out equals the object's volume.

eureka can measuring cylinder volume of water out = volume of object
Displacement gives the volume of an awkward shape; the balance gives its mass.
Quick check

Spot the gas

?In which state are the particles far apart, arranged randomly and moving quickly in all directions?
Calculate

Your turn — density

1A wooden block has a mass of 750 g and a volume of 250 cm³. Calculate its density in g/cm³.
g/cm³
Hint: ρ = m ÷ V = 750 ÷ 250.
Sort it

Name the state

Tap the state that matches each particle description.

Changes of state

Melting, boiling and back again

Adding or removing energy moves a substance between states. Each change has a name:

SOLID LIQUID GAS melting → boiling → ← freezing ← condensing sublimation (solid → gas)
Red = energy in (heating). Blue = energy out (cooling).

Key idea: changes of state are physical, not chemical. No new substance is made, the mass is conserved, and you can always get the original substance back by reversing the change (e.g. freeze the water and you have ice again).

Watch out — particles don't change size. When something melts, boils or expands, the particles themselves stay exactly the same size and number. What changes is only their spacing and how they move — they spread out and move more freely, they do not grow or shrink.

Internal energy

Internal energy of a substance

The internal energy of a substance is the total energy of all its particles. It is made of two parts:

  • Kinetic energy — because the particles are moving/vibrating (linked to temperature).
  • Potential energy — stored in the forces and spacing between the particles (linked to the state).
internal energy = total KE + total PEof all the particles in the substance

Heating a substance raises its internal energy. That extra energy does one of two jobs:

  • raise the temperature (more particle kinetic energy), or
  • change the state (more particle potential energy, at constant temperature).

Don't confuse internal energy with temperature. Internal energy = total kinetic + total potential energy of all the particles. Temperature only tracks the kinetic part. So on a plateau the temperature is fixed, yet the internal energy is still rising (the potential part is going up).

Heating curve

Why the graph goes flat

Heat ice steadily and plot temperature against time (or energy supplied). The two flat sections are the changes of state — the temperature stays constant while particles gain potential energy and the forces between them are overcome.

temperature → energy supplied / time → m.p. b.p. melting (flat) boiling (flat & longer) solid liquid gas
Sloped parts = temperature rising (kinetic energy up). Flat parts = changing state (potential energy up). Boiling's plateau is longer because vaporising takes far more energy than melting.

Analogy — the "unlocking" energy: on a flat plateau the energy isn't speeding the particles up, it's spent unlocking them from one another (pulling them apart against their attractions). That's why the thermometer pauses — kinetic energy isn't changing, only potential energy is.

Quick check

Reading the flat part

?While a pure substance is melting, energy is still being supplied. What happens to its temperature during this time?
Sort it

Temperature or state?

Tap an event, then tap whether the supplied energy raises the temperature or changes the state.

🌡️ Raises temperature

🔄 Changes state

Quick check

Physical or chemical?

?Water is boiled to steam, then the steam is cooled back to water. Which statement is correct?
Specific heat capacity (recap)

Raising the temperature

When energy raises the temperature (the sloped parts of the graph), use the specific heat capacity equation:

ΔE = m c Δθenergy (J) = mass (kg) × specific heat capacity (J/kg°C) × temperature change (°C)

The specific heat capacity c is the energy to raise 1 kg of a substance by 1 °C. Water's is high (4200 J/kg°C).

Analogy — water is a "thermal sponge". A high specific heat capacity means a substance soaks up a lot of energy for only a small temperature rise (and gives it back slowly when cooling). That is why water is slow to heat and slow to cool — handy for car radiators and central-heating systems, and why coastal climates are milder.

Worked example

Heating 0.5 kg of water (c = 4200) by 30 °C:

ΔE = 0.5 × 4200 × 30 = 63 000 J (63 kJ)

Calculate

Your turn — heating

2How much energy is needed to raise the temperature of 0.2 kg of water (c = 4200 J/kg°C) by 25 °C?
J
Hint: ΔE = 0.2 × 4200 × 25.
Specific latent heat

Changing state takes energy too

To change state at constant temperature (the flat parts of the graph) you need the specific latent heat L — the energy to change the state of 1 kg of a substance with no temperature change:

E = m Lenergy (J) = mass (kg) × specific latent heat (J/kg)
  • Latent heat of fusion — melting or freezing (solid ⇄ liquid).
  • Latent heat of vaporisation — boiling or condensing (liquid ⇄ gas).
Worked example

Melting 2 kg of ice (specific latent heat of fusion L = 334 000 J/kg):

E = 2 × 334 000 = 668 000 J (668 kJ)

Calculate

Your turn — latent heat

3How much energy is needed to melt 0.5 kg of ice at 0 °C? (specific latent heat of fusion L = 334 000 J/kg)
J
Hint: E = m L = 0.5 × 334 000.
Particle model & pressure · Physics only

How a gas pushes on its walls

Physics only: this gas-pressure section is on the Physics paper, not the Combined Science Trilogy paper.

Gas particles move quickly and randomly. Each time one collides with a wall it bounces off and gives the wall a tiny push. Billions of collisions every second add up to a steady pressure on the container.

each rebound pushes outward → pressure on every wall
Pressure is the total push of all the particle–wall collisions, spread over the wall area. Blue = a particle's path bouncing off the wall; green = the net outward push.

Analogy — drumming on the walls: picture thousands of tiny rubber balls thrown nonstop at the inside of a box. No single ball does much, but the constant drumming of all of them keeps a steady outward push — that push, per unit area, is the gas pressure.

Raise the temperature at constant volume and the particles move faster, so they hit the walls harder and more often — the pressure rises.

Quick check

Heating a sealed gas

?A fixed amount of gas is sealed in a rigid (constant-volume) container and then heated. What happens to the pressure?
Pressure & volume · Physics only

Squeeze it, and pressure rises

For a fixed mass of gas at constant temperature, pressure and volume are linked:

p V = constant  →  p₁V₁ = p₂V₂pressure × volume stays the same at constant temperature

Squeeze the gas into a smaller volume and the same particles hit the walls more often, so the pressure rises. Also, doing work on a gas (e.g. quickly pushing a bike pump) transfers energy to it and can raise its temperature.

Analogy — same balls, half the room. The number of particles never changes. Halve the volume and you crowd exactly the same particles into half the space, so each one reaches a wall in half the time and hits it twice as often — double the volume, halve the pressure; halve the volume, double the pressure. That's why p × V stays constant.

Worked example

Gas at p₁ = 100 kPa fills V₁ = 6 m³. It is squeezed to V₂ = 2 m³ at constant temperature. Find p₂.

p₂ = p₁V₁ ÷ V₂ = (100 × 6) ÷ 2 = 300 kPa

Calculate

Your turn — p₁V₁ = p₂V₂

4A fixed mass of gas at constant temperature has p₁ = 200 kPa and V₁ = 3 m³. It is compressed to V₂ = 1.5 m³. Calculate the new pressure p₂ in kPa.
kPa
Hint: p₂ = (p₁ × V₁) ÷ V₂ = (200 × 3) ÷ 1.5.
Recap

The equations to know

Density: ρ = m ÷ V

Heating (temperature change): ΔE = m c Δθ

Changing state (latent heat): E = m L

Gas (constant temperature): p₁V₁ = p₂V₂  (Physics only)

You've covered all of AQA 4.3 — density & the states of matter, changes of state & internal energy, specific heat capacity, latent heat, and gas pressure. Press Finish to see your score.

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