This mini-lesson builds the whole of AQA's Biomechanical Movement: Newton's laws applied to sport, force, momentum and impulse, the three lever classes and mechanical advantage, projectile motion, angular motion, and fluid mechanics.
Work through each screen, answer the questions (some are wordy, some are calculations you must recompute) and collect ⭐ stars. Press Start when you're ready.
Forces · Newton's laws
Newton's three laws of motion
Every sporting movement obeys Newton's laws. Learn each law and a sporting example:
1st law — inertia: a body stays at rest, or moving at constant velocity, unless acted on by an external force. A stationary football sits still until a boot applies a force.
2nd law — acceleration: the rate of change of momentum is proportional to the force applied, so F = ma. A larger force on the ball produces a larger acceleration.
3rd law — action–reaction: for every action there is an equal and opposite reaction. A sprinter drives down and back into the blocks; the ground pushes them up and forward (the ground reaction force).
Exam tip: always pair the law with a specific example. State the law, name the force, then describe the effect on the body or implement.
Quick check
Name the law
?A sprinter pushes backwards and downwards into the starting blocks, and is driven forwards out of them. Which of Newton's laws best explains this?
Forces · F = ma
Force and Newton's second law
A force is a push or pull that can change an object's speed, direction or shape. Newton's second law gives us the equation for the size of that force:
F = m × aF = force (newtons, N) · m = mass (kg) · a = acceleration (m/s²)
Because force is proportional to the rate of change of momentum, a bigger force on a fixed mass produces a bigger acceleration. This is why a stronger athlete can accelerate the same shot put faster.
Units: one newton is the force needed to accelerate a 1 kg mass at 1 m/s². Multiply mass in kg by acceleration in m/s² to get force in N.
Calculate
Your turn — resultant force
1A rugby player of mass 75 kg accelerates at 4 m/s² off the mark. Calculate the resultant force driving them forward, in newtons.
N
Working
F = m × a
F = 75 kg × 4 m/s²
F = 300 N
Hint: F = m × a = 75 × 4.
Forces · momentum & impulse
Momentum and impulse
Momentum is the quantity of motion a body has — the product of its mass and velocity:
p = m × vp = momentum (kg·m/s) · m = mass (kg) · v = velocity (m/s)
Impulse is force × time, and it equals the change in momentum. In sport, applying a force for longer (a bigger follow-through) creates a bigger impulse and so a greater change in velocity.
Impulse = F × t = change in momentuma larger force, or the same force over a longer time, changes momentum more
In practice: a sprinter's foot contact shows a positive impulse (drive phase) followed by a smaller negative impulse (braking). A net positive impulse accelerates the runner.
Calculate
Your turn — momentum
2A sprinter of mass 80 kg is running at 10 m/s. Calculate their momentum in kg·m/s.
kg·m/s
Working
p = m × v
p = 80 kg × 10 m/s
p = 800 kg·m/s
Hint: p = m × v = 80 × 10.
Quick check
Why follow through?
?A tennis player is coached to keep the racket in contact with the ball for as long as possible on a serve. In terms of impulse, why does this help?
Levers · three classes
Levers in the body
A lever has three parts: the fulcrum (F, the joint/pivot), the effort (E, the muscle force) and the load / resistance (R, the weight moved). Their order defines the class:
1st class — Fulcrum in the middle (E–F–R). Example: extending the neck by nodding at the atlanto-occipital joint; triceps extending the elbow.
2nd class — Resistance/load in the middle (F–R–E). Example: plantar-flexion when rising onto the toes. High mechanical advantage — moves large loads.
3rd class — Effort in the middle (F–E–R). Example: elbow flexion by the biceps. The most common lever in the body; favours speed and range of movement.
Memory aid: the middle letter of 1-2-3 maps to F-R-E (Fulcrum, Resistance, Effort). Say "1-2-3, F-R-E".
Levers · mechanical advantage
Mechanical advantage
Mechanical advantage (MA) tells you what the lever is good at — moving big loads, or moving fast over a big range:
MA = effort arm ÷ resistance armeffort arm = fulcrum→effort distance · resistance arm = fulcrum→load distance
MA > 1 — the effort arm is longer; a small effort moves a large load. Second-class levers (rising onto the toes) work this way.
MA < 1 — the resistance arm is longer; more effort is needed, but the load moves fast over a large range. Third-class levers (elbow flexion) work this way.
Trade-off: you cannot have both high force and high speed from one lever. Second-class levers favour force; third-class levers favour speed and range.
Sort it
Which lever class?
Tap a statement, then tap the lever class it belongs to.
① 1st class (E–F–R)
② 2nd class (F–R–E)
③ 3rd class (F–E–R)
Calculate
Your turn — mechanical advantage
3In a second-class lever the effort arm is 30 cm and the resistance arm is 12 cm. Calculate the mechanical advantage.
(no units)
Working
MA = effort arm ÷ resistance arm
MA = 30 cm ÷ 12 cm
MA = 2.5 (MA > 1, so a small effort moves a large load)
Hint: MA = 30 ÷ 12.
Quick check
Speed vs force
?Elbow flexion by the biceps is a third-class lever with a mechanical advantage of less than 1. What is the functional benefit of this arrangement?
Projectile motion
Projectile motion
A projectile (a shot, a long-jumper, a football) follows a curved parabolic flight path. We split its release velocity into two independent parts:
Resolve release velocity into horizontal (v·cosθ) and vertical (v·sinθ) components.
Three factors shape the flight path: the speed of release, the angle of release, and the height of release.
Calculate
Your turn — vertical component
4A shot is released at 20 m/s at an angle of 30° above the horizontal. Calculate the vertical component of its release velocity. (Use sin30° = 0.5.)
m/s
Working
vertical = v·sinθ
= 20 × sin30° = 20 × 0.5
= 10 m/s
Hint: vertical = v·sinθ = 20 × 0.5.
Angular motion
Angular motion & the spinning skater
Rotating bodies (a somersaulting gymnast, a spinning skater) obey their own rules:
Moment of inertia — the resistance of a body to changing its state of rotation. It depends on mass and, crucially, how that mass is distributed relative to the axis. Mass spread far out = large moment of inertia.
Angular momentum = moment of inertia × angular velocity. With no external torque, angular momentum is conserved.
So a skater who pulls the arms in reduces their moment of inertia; to keep angular momentum constant their angular velocity rises and they spin faster. Opening out again slows the spin.
Key idea: conservation of angular momentum lets performers control spin speed simply by changing body shape.
Quick check
Faster spin
?A figure skater spinning with arms outstretched pulls their arms in tight to the body. What happens, and why?
Fluid mechanics
Fluid mechanics: drag, lift & spin
Moving through air or water, a body meets fluid forces:
Drag — the resistance opposing motion through a fluid. It is reduced by streamlining, a smooth surface, and a small frontal area (the cyclist's tuck).
Lift & the Bernoulli principle — faster-moving fluid exerts lower pressure. Shaping air flow so it travels faster over one side creates a pressure difference and a lift force (the discus, the aerofoil).
The Magnus effect — a spinning ball drags air around with it, making flow faster on one side. The pressure difference swerves the flight: topspin makes a ball dip, backspin makes it float.
Same physics, opposite goals: a sprint cyclist wants to minimise drag; a swimmer's hand and a spin bowler exploit lift and the Magnus effect.
Match it
Match each term to its meaning
Tap a term on the left, then its matching definition on the right.
Term
Meaning
Recap
The big ideas to know
Newton: 1st = inertia · 2nd = F = ma (rate of change of momentum) · 3rd = action–reaction (ground reaction force)
Momentum: p = m × v · impulse = F × t = change in momentum
Levers: 1-2-3 → F-R-E in the middle · 2nd class = high MA (force) · 3rd class = MA < 1 (speed/range), most common