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Edexcel GCSE Maths (1MA1) · Algebra
Mini-Lesson

Algebra

This mini-lesson works through the core Algebra strand of Edexcel GCSE Maths (1MA1): expanding & factorising (including quadratics), solving linear equations, solving quadratics, simultaneous equations, rearranging formulae, sequences (nth term), straight-line graphs (y = mx + c) and inequalities.

3x + 7 22 =
An equation is a balance: whatever you do to one side, do to the other.

Work through each screen, answer the questions as you go (most are calculations) and collect ⭐ stars. Press Start when you're ready.

Manipulation

Expanding brackets

To expand, multiply every term inside the bracket by the term outside. For a double bracket, multiply each term in the first by each term in the second (FOIL), then collect like terms.

(x + a)(x + b) = x² + (a + b)x + abFirst · Outer · Inner · Last — then simplify
Worked example — single bracket

Expand 3(2x − 5).

3 × 2x = 6x  and  3 × (−5) = −15

= 6x − 15

Worked example — double bracket

Expand (x + 4)(x + 2).

x·x = x²,   x·2 = 2x,   4·x = 4x,   4·2 = 8

= x² + 2x + 4x + 8 = x² + 6x + 8

Common slip: when expanding (x + 5)², don't write x² + 25. It means (x + 5)(x + 5), giving the middle term: x² + 10x + 25.

Quick check

Your turn — expand a square

?Expand and simplify (x + 5)².
Manipulation

Factorising quadratics

Factorising is expanding in reverse. For x² + bx + c, find two numbers that multiply to c and add to b:

x² + bx + c = (x + p)(x + q)where p × q = c  and  p + q = b
Worked example

Factorise x² + 7x + 12.

Need two numbers with product 12 and sum 7 → 3 and 4 (3 × 4 = 12, 3 + 4 = 7).

= (x + 3)(x + 4)  (check by expanding: x² + 4x + 3x + 12 = x² + 7x + 12 ✓)

Signs matter: for x² − 5x + 6 the two numbers multiply to +6 but add to −5, so both are negative: (x − 2)(x − 3).

Quick check

Your turn — factorise

?Factorise x² + 7x + 12.
Equations

Solving linear equations

An equation is a balance. Do the same operation to both sides to isolate the letter. Aim to gather the letters on one side and the numbers on the other.

3x + 7 = 22subtract 7 → 3x = 15  ·  divide by 3 → x = 5
Worked example — unknown on both sides

Solve 5x − 3 = 2x + 18.

Subtract 2x from both sides: 3x − 3 = 18

Add 3 to both sides: 3x = 21

Divide by 3: x = 7  (check: 5×7 − 3 = 32 and 2×7 + 18 = 32 ✓)

Golden rule: whatever you do to one side, you must do to the other — otherwise the balance breaks and the answer is wrong.

Calculate

Your turn — solve a linear equation

1Solve 3x + 7 = 22. Type the value of x.
Hint: subtract 7 (→ 3x = 15), then divide by 3.
Calculate

Your turn — letters on both sides

2Solve 5x − 3 = 2x + 18. Type the value of x.
Hint: subtract 2x (→ 3x − 3 = 18), add 3 (→ 3x = 21), divide by 3.
Equations

Solving quadratics by factorising

To solve a quadratic = 0, factorise it, then use the fact that if two things multiply to zero, at least one of them must be zero.

(x + p)(x + q) = 0 → x = −p  or  x = −qset each bracket equal to zero
Worked example

Solve x² + 5x + 6 = 0.

Two numbers multiplying to 6, adding to 5 → 2 and 3.

(x + 2)(x + 3) = 0

x + 2 = 0 → x = −2  or  x + 3 = 0 → x = −3

So x = −2 or x = −3.

Sign flip: the bracket (x + 2) gives the root x = −2, not +2. Always change the sign of the number in the bracket.

Calculate

Your turn — solve a quadratic

3Solve x² + 5x + 6 = 0. Type the larger root.
Hint: (x + 2)(x + 3) = 0 → x = −2 or x = −3. The larger of −2 and −3 is −2.
Match game

Equation ⇄ solution

Tap an equation on the left, then its solution on the right.

Equations

Simultaneous equations

Two equations, two unknowns. Eliminate one letter by adding or subtracting the equations (after matching coefficients), solve for the other, then substitute back.

Worked example

Solve  2x + y = 11  and  x + y = 7.

Subtract the second from the first: (2x − x) + (y − y) = 11 − 7 → x = 4.

Substitute x = 4 into x + y = 7: 4 + y = 7 → y = 3.

x = 4, y = 3  (check: 2×4 + 3 = 11 ✓)

Tip: if the letters have the same sign, subtract to eliminate; if they have opposite signs, add.

Formulae

Rearranging formulae

To make a different letter the subject, use the same balancing moves as solving an equation — get the wanted letter on its own.

v = u + at → a = (v − u) ÷ tsubtract u, then divide by t
Worked example

Make x the subject of y = 4x − 3.

Add 3 to both sides: y + 3 = 4x

Divide by 4: x = (y + 3) ÷ 4

Order matters: undo operations in reverse. In 4x − 3 you multiplied then subtracted, so to reverse it you add first, then divide.

Sequences

nth term of a linear sequence

A linear (arithmetic) sequence goes up by the same amount each time — the common difference. The nth term is:

nth term = dn + (a − d)d = common difference · a = first term
Worked example

Find the nth term of 5, 8, 11, 14, …

Common difference d = 3, so it starts "3n". First term is 5, and 3×1 = 3, so add 2.

nth term = 3n + 2. Check n = 2: 3×2 + 2 = 8 ✓

10th term: 3 × 10 + 2 = 32.

Careful: "3n + 2" is a rule, not a term. To get an actual term you must substitute a value of n.

Calculate

Your turn — a term in a sequence

4The sequence 5, 8, 11, 14, … has nth term 3n + 2. Work out the 10th term.
Hint: substitute n = 10 into 3n + 2.
Quick check

Reading the nth term

?The nth term of a sequence is 2n + 3. What is the first term (n = 1)?
Graphs

Straight-line graphs: y = mx + c

Every straight line has the form y = mx + c, where m is the gradient (steepness) and c is the y-intercept (where it crosses the y-axis).

gradient m = rise ÷ runchange in y ÷ change in x
x y (0, 1) intercept y = 2x + 1 gradient 2, up 2 for every 1 across 1
y = 2x + 1: crosses the y-axis at 1 and rises 2 for every 1 across, so the gradient is 2.

Read it straight off: in y = 4x − 3 the gradient is 4 and the line crosses the y-axis at −3. The number in front of x is always the gradient.

Calculate

Your turn — read the gradient

5A line has equation y = 4x − 3. Write down its gradient.
Hint: in y = mx + c, the gradient m is the number in front of x.
Inequalities

Solving inequalities

Solve an inequality just like an equation — but there's one special rule: if you multiply or divide by a negative number, you must flip the inequality sign.

3x + 4 < 19 → 3x < 15 → x < 5subtract 4, then divide by (positive) 3 — sign stays the same
Worked example — flipping

Solve −2x > 6.

Divide both sides by −2 → x < −3 (the > flips to <).

The one trap: forgetting to flip. Dividing by a negative reverses the direction of the inequality every time.

Sort it

Linear or quadratic?

A linear equation has no x² term; a quadratic contains an x² term. Tap an equation, then tap the box it belongs in.

➗ Linear

x² Quadratic

Recap

The Algebra strand

Expanding: multiply out brackets; (x + a)(x + b) = x² + (a+b)x + ab; watch the middle term in (x + 5)².

Factorising: reverse of expanding — two numbers that multiply to c and add to b.

Linear equations: balance both sides; gather letters one side, numbers the other.

Quadratics: factorise = 0, then each bracket = 0 (flip the sign for the root).

Simultaneous: eliminate one letter, solve, substitute back.

Rearranging: undo operations in reverse to change the subject.

Sequences: nth term = dn + (a − d); substitute n for a term.

Graphs: y = mx + c — m is the gradient, c the y-intercept.

Inequalities: solve like equations, but flip the sign when × or ÷ by a negative.

You've covered the core Algebra topics in Edexcel 1MA1. Press Finish to see your score.

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Mini-lesson complete!

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You've worked through the Algebra strand for Edexcel GCSE Maths (1MA1). 🎉

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