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IB Diploma Mathematics: Analysis & Approaches SL · Calculus
Mini-Lesson

Calculus

This mini-lesson covers SL Calculus: the derivative as a gradient, the power rule, tangents & normals, stationary points and optimisation, integration as the reverse of differentiation, definite integrals and area, and kinematics.

Answer as you go and collect ⭐ stars. Press Start when ready.

The derivative

Limits & the derivative

The derivative f′(x) is the gradient of the tangent to y = f(x) — the instantaneous rate of change. It is defined as a limit of gradients of chords.

f′(x) = limh→0 [f(x+h) − f(x)] / h
Quick check

Power rule

?Using the power rule, the derivative of x⁴ is:
Differentiation

The power rule

For each power, bring the index down and reduce it by one; differentiate term by term.

d/dx (xⁿ) = n xⁿ⁻¹e.g. f(x) = x³ ⇒ f′(x) = 3x², so f′(2) = 12

SL standards: also d/dx(sin x) = cos x, d/dx(eˣ) = eˣ, d/dx(ln x) = 1/x.

Calculate

Derivative value

Given f(x) = x³, find f′(2).
Hint: f′(x) = 3x², so 3(2)² = 3 × 4.
Tangents

Tangents & normals

The gradient of the tangent at x = a is f′(a); the normal is perpendicular, with gradient −1/f′(a).

Worked example

y = x² at x = 3: f′(x) = 2x so the tangent gradient is 2(3) = 6. Tangent line: y − 9 = 6(x − 3).

Quick check

Stationary point

?At a stationary point of a curve, what is always true?
Calculate

Tangent gradient

Find the gradient of the tangent to y = x² at the point where x = 3.
Hint: dy/dx = 2x, then substitute x = 3.
Stationary points

Increasing, decreasing & stationary

f is increasing where f′(x) > 0 and decreasing where f′(x) < 0. A stationary point has f′(x) = 0.

Classify: use the second derivative — f″ > 0 gives a local minimum, f″ < 0 a local maximum. For y = x² − 6x + 5, f′ = 2x − 6 = 0 at x = 3.

Sort it

Differentiate or integrate?

Tap a task, then the tool that produces it.

d/dx Differentiate

∫ Integrate

➖ Neither

Optimisation

Optimisation

To optimise, write the quantity as a function of one variable, differentiate, set the derivative to zero, and test the nature of the stationary point.

Always check the endpoints and the context (a length or area cannot be negative).

Calculate

Stationary point

Find the x-coordinate of the stationary point of y = x² − 6x + 5.
Hint: set dy/dx = 2x − 6 = 0.
Quick check

Antiderivative

?Which is an antiderivative of 2x?
Integration

Integration as antidifferentiation

Integration reverses differentiation. Raise the index by one and divide:

∫ xⁿ dx = xⁿ⁺¹/(n+1) + C  (n ≠ −1)the constant C matters for indefinite integrals
Calculate

Definite integral

Evaluate ∫₀² 3x² dx.
Hint: antiderivative is x³, so [x³]₀² = 2³ − 0.
Match it

Match each function to its derivative

Tap a statement on the left, then its matching partner on the right.

Function
Derivative
Definite integrals

Definite integrals, area & kinematics

A definite integral gives the (signed) area between the curve and the x-axis:

ab f(x) dx = F(b) − F(a)e.g. ∫₀² 3x² dx = [x³]₀² = 8

Kinematics: velocity v = ds/dt and acceleration a = dv/dt; going back, s = ∫v dt.

Calculate

Kinematics

A particle has displacement s(t) = 2t³. Find its velocity at t = 3.
Hint: v = ds/dt = 6t², then t = 3.
Quick check

Kinematics

?If s(t) is displacement, then velocity v(t) is:
Strategy

Reading a calculus question

"Gradient / rate of change / tangent" → differentiate. "Area / total / displacement from velocity" → integrate. "Maximum / minimum" → set f′(x) = 0.

Exam habit: never forget +C for indefinite integrals, and substitute limits in the order F(b) − F(a).

Recap

The big ideas to know

Derivative: f′(x) = gradient; power rule d/dx xⁿ = nxⁿ⁻¹

Tangents: tangent gradient f′(a); normal gradient −1/f′(a)

Stationary: f′(x) = 0; classify with f″

Integration: ∫xⁿ dx = xⁿ⁺¹/(n+1) + C

Definite/kinematics: ∫ₐᵇ = F(b)−F(a); v = ds/dt, a = dv/dt

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