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IB Diploma Mathematics: Analysis & Approaches HL · Complex Numbers
Mini-Lesson

Complex Numbers

This HL mini-lesson covers Complex Numbers: Cartesian arithmetic and the conjugate, modulus & argument on the Argand diagram, polar and Euler form, de Moivre's theorem, and roots of complex numbers and polynomials.

Answer as you go and collect ⭐ stars. Press Start when ready.

Cartesian form

The imaginary unit & Cartesian form

With i² = −1, a complex number is z = a + bi (a = Re z, b = Im z). Real numbers are the special case b = 0.

i² = −1powers cycle: i, i²=−1, i³=−i, i⁴=1, then repeat
Quick check

Conjugate

?The complex conjugate of 3 + 4i is:
Arithmetic

Arithmetic & the conjugate

Add/subtract componentwise; multiply with i² = −1. The conjugate of a + bi is a − bi.

z z* = (a + bi)(a − bi) = a² + b²always real and equal to |z|²

Division: multiply top and bottom by the conjugate of the denominator to make it real.

Calculate

Modulus

Find the modulus |3 + 4i|.
Hint: √(3² + 4²) = √25.
Modulus & argument

Modulus, argument & the Argand diagram

Plot z = a + bi as the point (a, b). Its distance from the origin is the modulus, and the angle from the positive real axis is the argument.

|z| = √(a² + b²) · arg z = arctan(b/a)|3 + 4i| = √25 = 5; arg(1 + i) = 45°
Quick check

Modulus

?The modulus of a + bi is:
Calculate

Argument

Find the argument of 1 + i in degrees.
°
Hint: arg = arctan(1/1) = 45°.
Polar form

Modulus-argument (polar) form

Any complex number can be written using its modulus r and argument θ:

z = r(cos θ + i sin θ) = r cis θmultiply moduli and add arguments when multiplying
Sort it

Real, imaginary or neither?

Tap an expression, then what kind of number it is.

🟦 Real

🟪 Purely imaginary

🟨 Neither

Euler form

Euler form

Euler's relation links exponentials and trigonometry:

e^{iθ} = cos θ + i sin θ, so z = r e^{iθ}and the famous e^{iπ} + 1 = 0
Calculate

de Moivre modulus

If |z| = 2, find |z³| using de Moivre.
Hint: |z³| = |z|³ = 2³.
Quick check

de Moivre

?By de Moivre, (r cis θ)ⁿ equals:
de Moivre

de Moivre’s theorem

Raising a polar number to a power multiplies the modulus and the argument:

(r cis θ)ⁿ = rⁿ cis(nθ)so |zⁿ| = |z|ⁿ; e.g. |z³| = 2³ = 8 when |z| = 2
Calculate

Product modulus

If |z₁| = 2 and |z₂| = 3, find |z₁z₂|.
Hint: |z₁z₂| = |z₁||z₂| = 2 × 3.
Match it

Match each expression to its value

Tap a statement on the left, then its matching partner on the right.

Expression
Value
Roots

Roots of complex numbers & polynomials

The n nth roots of a complex number are equally spaced on a circle of radius |z|^{1/n}, separated by 2π/n.

Conjugate root theorem: a polynomial with real coefficients has non-real roots in conjugate pairs (if a + bi is a root, so is a − bi).

Calculate

Power modulus

Find |(1 + i)⁴|. (|1 + i| = √2.)
Hint: |(1+i)⁴| = (√2)⁴.
Quick check

Real polynomials

?A polynomial with real coefficients has 2 + 3i as a root. Another root must be:
Strategy

Choosing a form

Use Cartesian form for adding, polar/Euler form for multiplying, dividing and taking powers or roots (via de Moivre). Convert between forms with |z| and arg z.

Exam habit: give arguments in the correct range and remember the modulus of a product is the product of the moduli.

Recap

The big ideas to know

Cartesian: z = a + bi, i² = −1; conjugate a − bi

Modulus/argument: |z| = √(a²+b²), arg z = arctan(b/a)

Polar/Euler: z = r cis θ = r e^{iθ}

de Moivre: (r cis θ)ⁿ = rⁿ cis(nθ)

Roots: n nth-roots on a circle; real polys have conjugate-pair roots

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