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IB Diploma Chemistry SL · Structure 3.2 — functional groups
Mini-Lesson

Classifying organic compounds

4 missions. Guess, learn, then check. Your place is saved.

  1. Mission 1How can C₂H₆O be both a liquid and a gas at room temperature?
  2. Mission 2Petrol and candle wax are both mostly alkanes. Why is one a runny liquid and the other a solid?
  3. Mission 3Could you draw a molecule from its name alone?
  4. Mission 4How many different molecules can you build from C₅H₁₂?
Mission 1

Mission 1: How can C₂H₆O be both a liquid and a gas at room temperature?

Make a guess: How can C₂H₆O be both a liquid and a gas at room temperature?

Mission 1

Five kinds of formula

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formulas of hexaneEmpiricalC3H7MolecularC6H14Full structuralCHHCHHCHHCHHCHHCHHHH5 C–C + 14 C–H = 19 bondsCondensedCH3CH2CH2CH2CH2CH3Skeletal5 lines · 6 pointsStereochemicalCCCHHone CH2 carbon
  • Empirical: simplest whole-number ratio of atoms. Hexane: C₃H₇.
  • Molecular: actual number of each atom. Hexane: C₆H₁₄.
  • Full structural: every atom and bond. Condensed: CH₃CH₂CH₂CH₂CH₂CH₃, or CH₃(CH₂)₄CH₃.
  • Skeletal: a zig-zag of bonds; carbons and their hydrogens are implied.
  • Stereochemical: wedges and dashes show the 3D shape. Draw one only when asked.
  • Build it as a 3D model (real or virtual): each carbon is tetrahedral, so chains zig-zag.
Mission 1

Reading a skeletal formula

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a skeletal formula: pentan-1-olPentan-1-olOHCH3CH2CH2CH2CH2end of line 5 = O, not CH: 3 + 2 + 2 + 2 + 2 + 1 (on O) = 125 C, 12 H, 1 O: C5H12OA group on a short line off a cornerOHattached to this carbon
  • Every line end and corner is a carbon, unless a line ends in a label (OH, Cl): that end is the labelled atom.
  • A group drawn at a corner, or on a short line off it, is attached to that carbon.
  • H on carbon is not drawn: give each carbon enough H for four bonds. Other atoms, and H on them, are always drawn.
  • Lines are bonds: count the points, not the lines.
  • Worked example: five zig-zag lines, the last ending in OH. That is 5 C and 1 O.
  • H: 3 + 2 + 2 + 2 + 2 + 1 (on O) = 12. So C₅H₁₂O, CH₃CH₂CH₂CH₂CH₂OH.
Quick check
?The skeletal formula of a compound is a zig-zag line of five straight segments joined end to end. An –OH group is drawn at the point where the first and second segments meet (the second point from the left-hand end). No other atoms are shown. What is the molecular formula of the compound?
Quick check
?Propan-2-ol has the molecular formula C₃H₈O. Which statement about the formula C₃H₈O is correct?
Quick check
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formula for question 1.5
?A skeletal formula is a zig-zag of four lines, with one short extra line drawn from the middle point. Which condensed structural formula represents the same compound?
Mission 1

Functional groups

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galleryCXhalogenoalkaneCOHalcoholCORHaldehydeCORR′ketoneCOROHcarboxylic acidROR′etherCNH2amineCORNH2amideCOROCR′esterRareneR, R′ = rest of molecule (chain or H)Short lines = other bonds on that carbon
  • A functional group gives a compound its typical reactions and decides its class.
GroupStructureClassExample
halogeno–X (F, Cl, Br, I)halogenoalkaneCH₃CH₂Br
hydroxyl–OHalcoholCH₃CH₂OH
carbonyl–CHO, at the chain endaldehydeCH₃CHO
carbonylC=O inside the chainketoneCH₃COCH₃
carboxyl–COOHcarboxylic acidCH₃CH₂CH₂COOH
alkoxy–O–RetherCH₃OCH₃
amino–NH₂amineCH₃NH₂
amido–CONH₂amideCH₃CONH₂
ester–COO– between two carbonsesterCH₃COOCH₃
phenyl–C₆H₅ (a benzene ring)areneC₆H₅CH₃
Mission 1

Telling look-alikes apart

  • Carboxyl: the C=O carbon also carries –OH. It counts as one group.
  • Ester: the single-bonded O is bonded to a second carbon, not to H.
  • Amido: N bonded to the C=O carbon. Amino: N on a carbon with no C=O.
  • Alkoxy: C–O–C with no C=O.
  • Saturated: only single C–C bonds. Unsaturated: at least one C=C or C≡C.
  • Cyclohexane, C₆H₁₂, is saturated: its ring, not a double bond, lowers the H count.
Quick check
?Which compound contains an ester group?
Quick check
?Which statement gives the defining feature of an unsaturated organic compound?
Quick check
?Which compound contains an amido group?
Mission check

?Two compounds both have the molecular formula C₂H₆O. One is a liquid that boils at 78 °C; the other is a gas that boils at −24 °C. Which explains this?
Mission 2

Mission 2: Petrol and candle wax are both mostly alkanes. Why is one a runny liquid and the other a solid?

Make a guess: Petrol and candle wax are both mostly alkanes. Why is one a runny liquid and the other a solid?

Mission 2

Homologous series

  • A homologous series is a family with the same functional group.
  • Each member differs from the next by CH₂.
  • One general formula fits every member.
  • Members have similar chemical properties; physical properties change gradually.
Mission 2

The series, part 1

SeriesGroupGeneral formulaExample
alkanesC–C onlyCₙH₂ₙ₊₂ethane, CH₃CH₃
alkenesC=CCₙH₂ₙethene, CH₂=CH₂
alkynesC≡CCₙH₂ₙ₋₂ethyne, HC≡CH
halogenoalkanes–XCₙH₂ₙ₊₁Xchloromethane, CH₃Cl
alcohols–OHCₙH₂ₙ₊₁OHmethanol, CH₃OH
ethers–O–CₙH₂ₙ₊₂Omethoxymethane, CH₃OCH₃
Mission 2

The series, part 2

SeriesGroupGeneral formulaExample
aldehydes–CHOCₙH₂ₙOmethanal, HCHO
ketones–CO–CₙH₂ₙOpropanone, CH₃COCH₃
carboxylic acids–COOHCₙH₂ₙO₂methanoic acid, HCOOH
esters–COO–CₙH₂ₙO₂methyl ethanoate, CH₃COOCH₃
amines (primary)–NH₂CₙH₂ₙ₊₃Nmethanamine, CH₃NH₂
amides (primary)–CONH₂CₙH₂ₙ₊₁NOethanamide, CH₃CONH₂
  • Shared general formulae: aldehydes and ketones; acids and esters; alcohols and ethers. The functional group decides the series.
Quick check
?Which pair of compounds are successive members of the same homologous series?
Quick check
?Methanol, ethanol, propan-1-ol and butan-1-ol are successive members of the homologous series of alcohols. Which statement about these four compounds is correct?
Mission 2

Why boiling point rises along a series

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points of the first four alcoholsmethanol65ethanol78propan-1-ol97butan-1-ol11804080120boiling point / °CMore CH2, more contact pointsOHOHOHOHshort chains:2 contactslong chains:4 contactseach molecule has one –OH
  • Boiling separates whole molecules. No covalent bonds break.
  • Each extra CH₂ adds electrons and contact area: stronger London (dispersion) forces.
  • More energy is needed to separate the molecules, so the boiling point rises.
  • In the alcohols, each molecule still has one –OH: its hydrogen bonding stays about the same.
  • Melting points rise too, but less regularly: how molecules pack in the solid also matters.
Quick check
?The boiling points of four successive alcohols are: methanol 65 °C, ethanol 78 °C, propan-1-ol 97 °C and butan-1-ol 118 °C. Which statement explains this trend?
Calculate
1Boiling points of the first four straight-chain aldehydes: methanal −19 °C, ethanal 20 °C, propanal 48 °C, butanal 75 °C. Use the trend to estimate the boiling point of pentanal, CH₃CH₂CH₂CH₂CHO, in °C.
Mission check

?Petrol and candle wax are both mixtures of alkanes. Petrol is a liquid at room temperature; wax is a solid. Which explains this?
Mission 3

Mission 3: Could you draw a molecule from its name alone?

Make a guess: Could you draw a molecule from its name alone?

Mission 3

The parts of a name

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of the name 2-methylpentan-3-ol2-methylpentan-3-ol2-methyl · branch on C2pent · 5 carbons in the chainan · single C–C bonds only3 · locant: the OH is on C3ol · suffix: alcohol (–OH)CH3CHCHCH2CH3CH3OH12345OH: C3 from either end,so the methyl decides:C2 from the left, not C4 from the right
  • Stem = carbons in the parent chain: meth 1, eth 2, prop 3, but 4, pent 5, hex 6.
  • -an- only single C–C bonds; -en- one C=C; -yn- one C≡C.
  • Suffix for the main group: -ol (hydroxyl), -al (aldehyde), -one (ketone), -oic acid (carboxyl). Alkanes end in -e.
  • Prefixes for side groups: methyl, ethyl; fluoro, chloro, bromo, iodo.
  • Locants are carbon numbers: 2-methylpentan-3-ol.
Mission 3

Four steps to a name

  • 1. Find the longest chain that contains the functional-group carbon. It may bend through a branch.
  • 2. Number from the end that gives the suffix group the lowest locant.
  • 3. Then the lowest locant to the C=C or C≡C, then to the prefixes.
  • 4. Prefixes in alphabetical order. Repeats: di-, tri- (not used for alphabetical order). Commas between numbers; hyphens between numbers and letters.
Mission 3

Worked examples: prefixes only

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worked examples2,3-Dimethylpentanefrom the left12345locants {3, 4}from the right54321locants {2, 3}3-Bromo-2-methylpentanefrom the leftBr12345locants {2, 3}from the rightBr54321locants {3, 4}Lower set of locants wins.Prefixes go in alphabetical order:bromo (b) before methyl (m), thoughbromo has the higher locant, 3.
  • CH₃CH₂CH(CH₃)CH(CH₃)CH₃: longest chain 5 → pentane.
  • From the right, methyls on C2 and C3; from the left, C3 and C4. Lower set wins.
  • Name: 2,3-dimethylpentane.
  • CH₃CH(CH₃)CHBrCH₂CH₃: from the left {2, 3}; from the right {3, 4}.
  • Name: 3-bromo-2-methylpentane. Prefixes go in alphabetical order (b before m), not number order.
Quick check
?What is the IUPAC name of CH₃CH₂CH(CH₃)CH₂Cl?
Mission 3

Groups that take a suffix

  • -ol: CH₃CH₂CH₂CH(OH)CH₃ is pentan-2-ol, not pentan-4-ol.
  • -one: CH₃COCH₂CH₂CH₃ is pentan-2-one. Propanone needs no number.
  • -al and -oic acid: that carbon is always C1, so no number: CH₃CH₂CH₂COOH is butanoic acid.
  • With a branch: (CH₃)₂CHCOOH is 2-methylpropanoic acid.
  • -ene, -yne: number the multiple bond by its lower carbon: CH₂=CHCH₂CH₂CH₃ is pent-1-ene; CH₃C≡CCH₃ is but-2-yne.
Mission 3

A C=C plus a suffix group

  • The suffix group gets the lowest locant first; the C=C locant goes before -en-.
  • CH₂=CHCH₂CH(OH)CH₃: from the CH₃ end, OH is on C2 and the C=C starts at C4: pent-4-en-2-ol.
  • Not pent-1-en-4-ol: the suffix group outranks the double bond.
  • Branch plus suffix: CH₃CH(CH₃)CH₂CH₂OH is 3-methylbutan-1-ol.
Quick check
?What is the IUPAC name of CH₃CH₂CH(CH₃)CHO?
Quick check
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formula for question 3.8COOH
?The skeletal formula is a zig-zag of three lines, the right-hand line ending in COOH, with a short extra line from the second point from the left. What is the IUPAC name of the compound?
Quick check
?What is the IUPAC name of CH₃CH₂C(CH₃)₂CH₂OH?
Quick check
?What is the IUPAC name of CH₃CH₂COCH₂CH(CH₃)CH₃?
Quick check
?What is the IUPAC name of CH₂=CHCH(CH₃)CH₃?
Mission check

?Which condensed structural formula is 3-methylpentan-2-one?
Mission 4

Mission 4: How many different molecules can you build from C₅H₁₂?

Make a guess: How many different molecules can you build from C₅H₁₂?

Mission 4

Structural isomers

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of structural isomerChain isomershexane2-methylpentaneboth C6H14Position isomersOHOHpropan-1-olpropan-2-olboth C3H8OFunctional group isomersOOpropanalpropanoneboth C3H6O
  • Structural isomers: same molecular formula, atoms connected differently.
  • Chain (branched-chain) isomers: different skeleton. Hexane and 2-methylpentane, both C₆H₁₄.
  • Position isomers: same group, different place. Propan-1-ol and propan-2-ol.
  • Functional group isomers: different series. Propanal and propanone, both C₃H₆O.
  • Rotating, flipping or bending a drawing does not make a new isomer.
Mission 4

Primary, secondary, tertiary

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secondary and tertiaryAlcohol: count the C bonded to the C–OH carbonpropan-1-olpropan-2-ol2-methyl-propan-2-olOHOHOH1121231° primary1 C on C–OH2° secondary2 C on C–OH3° tertiary3 C on C–OHAmine: count the C bonded to the N atomCH3CH2NH2(CH3)2NH(CH3)3NNH2NHN1121231° primary1 C on N2° secondary2 C on N3° tertiary3 C on N
  • Alcohols and halogenoalkanes: count the carbons bonded to the carbon carrying –OH or –X.
  • One → primary; two → secondary; three → tertiary.
  • Propan-1-ol is primary, propan-2-ol secondary, 2-methylpropan-2-ol tertiary. (CH₃)₃CBr is a tertiary halogenoalkane.
  • Amines: count the carbons bonded to N. CH₃CH₂NH₂ 1°, (CH₃)₂NH 2°, (CH₃)₃N 3°.
  • The class is not the locant: hexan-3-ol is secondary.
Quick check
?Which compound is a tertiary alcohol?
Quick check
?Which statement about the compound (CH₃)₃CNH₂ is correct?
Quick check
?Classify each halogenoalkane. P: (CH₃)₂CHCH₂Cl. Q: CH₃CHICH₃. R: 1-bromo-1-methylcyclohexane (Br and CH₃ on the same ring carbon). Which row is correct for P, Q and R?
Quick check
?Which pair of compounds are position isomers?
Quick check
?Which compound is a secondary amine?
Mission check

?How many structural isomers have the molecular formula C₅H₁₂?
Recap

The big ideas

  • Formulas show more and more: empirical → molecular → structural → skeletal → stereochemical.
  • The functional group sets the class; a homologous series adds CH₂ each time.
  • Boiling points rise along a series: stronger London forces, same functional-group force.
  • IUPAC: longest chain with the group; lowest locant to the suffix; prefixes in alphabetical order.
  • Structural isomers: same formula, different connections. 1°, 2°, 3°: count carbons on that C (on N for amines).
🏆

Mini-lesson complete!

⭐⭐⭐

You've worked through Classifying organic compounds for IB Diploma Chemistry SL. 🎉

  1. Mission 1How can C₂H₆O be both a liquid and a gas at room temperature?
  2. Mission 2Petrol and candle wax are both mostly alkanes. Why is one a runny liquid and the other a solid?
  3. Mission 3Could you draw a molecule from its name alone?
  4. Mission 4How many different molecules can you build from C₅H₁₂?

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