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Eduqas GCSE Chemistry · Topic 9 — Rate of chemical change and dynamic equilibrium
Mini-Lesson

Rate of chemical change & dynamic equilibrium

This mini-lesson walks you through the whole of Eduqas Topic 9: how we measure the rate of a reaction, the factors that change it, the collision theory behind them, catalysts and enzymes, the required practicals, and reversible reactions that settle into a dynamic equilibrium.

reactants A + B products C + D rate of reaction some reactions are reversible ⇌

Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Items marked Higher are assessed on Higher tier only. Press Start when you're ready.

What is rate?

Measuring the rate of a reaction

The rate of a reaction is how quickly reactants are used up or products are made. To measure it we follow something that changes as the reaction goes — Eduqas wants you to be able to suggest practical methods:

  • Gas collection — measure the volume of gas given off over time (gas syringe), e.g. a metal + acid making hydrogen.
  • Loss of mass — stand the flask on a balance; as gas escapes, the mass falls.
  • Colour change / turbidity (precipitation) — time how long until a cross under the flask disappears as a precipitate clouds the mixture.

Data-logging apparatus (e.g. a pressure or mass sensor) lets you record many readings automatically.

Calculating rate

Mean rate of reaction

The mean (average) rate over a period of time is simply the amount that changed divided by the time it took:

mean rate = quantity changed ÷ timeunits: cm³/s (gas volume), g/s (mass lost), or mol/s

Bigger number = faster reaction. A reaction that makes 48 cm³ of gas in 60 s has a mean rate of 0.8 cm³/s.

Worked example

A flask loses 1.20 g of carbon dioxide in 40 s.

mean rate = 1.20 ÷ 40 = 0.03 g/s

Calculate

Your turn — mean rate

1In a magnesium + acid reaction, a gas syringe collects 30 cm³ of hydrogen in 20 s. Calculate the mean rate of reaction.
cm³/s
Hint: mean rate = volume ÷ time = 30 ÷ 20.
Reading rate graphs

Rate–time graphs & the tangent Higher

Plotting gas volume against time gives a curve. It is steepest at the start (fastest rate, most reactant) and flattens off when a reactant runs out and the reaction stops.

time (s) volume of gas (cm³) tangent at this point Δx (time) Δy (volume) rate = gradient = Δy ÷ Δx flat = reaction finished
To find the rate at one instant, draw a tangent to the curve and work out its gradient (Δy ÷ Δx). Eduqas uses the gradient of a curve as a measure of rate (Higher).

Watch out: a graph that finishes higher up just made more product. It is the steepness (gradient) — not the final height — that tells you how fast the reaction went.

Quick check

Reading the graph

?A reaction makes 40 cm³ of gas in the first 10 s, shown by the steep part of the curve. What is the mean rate over those first 10 seconds?
Factors affecting rate

Five things that change the rate

Eduqas expects you to describe how each of these changes the rate of a reaction:

  • Concentration (and, for gases, pressure Higher) — more crowded particles.
  • Surface area — smaller pieces of a solid expose more surface.
  • Temperature — hotter particles move faster and carry more energy.
  • Catalysts — speed things up without being used up.
one lump slow same mass, powdered fast — more surface area
Powdering a solid increases its surface area to volume ratio, so more collisions happen — the reaction speeds up.
Collision theory

Why the factors work

Particles can only react when they collide with enough energy. That minimum energy is the activation energy (Ea). A faster rate means either more frequent collisions, or collisions with more energy, or both.

progress of reaction → energy reactants products Eₐ without catalyst lower Eₐ with catalyst
A catalyst gives an alternative pathway with a lower activation energy (green), so more collisions succeed — but the reactants and products are unchanged.
  • Concentration / pressure ↑ → particles closer together → collisions are more frequent.
  • Surface area ↑ → more solid surface exposed → more frequent collisions.
  • Temperature ↑ → particles move faster (more frequent collisions) and have more energy (more collisions exceed Ea) Higher.
Quick check

Heating it up

?Why does raising the temperature increase the rate of a reaction? Choose the most complete answer.
Catalysts & enzymes

Catalysts speed things up

A catalyst speeds up a reaction by providing an alternative pathway with a lower activation energy. Crucially, a catalyst is not used up — it is chemically unchanged at the end, so a tiny amount can be used over and over.

  • It does not appear in the overall equation and does not change the amount of product.
  • Different catalysts work for different reactions (you should be able to identify a catalyst in a reaction).
  • Enzymes are biological catalysts — proteins that speed up reactions in living things.

Watch out: a catalyst lowers the activation energy and is not consumed — it does not make the products more energetic, and it does not shift how much product forms.

Quick check

What does a catalyst do?

?Which statement about a catalyst is correct?
Specified practical work

Investigating rate in the lab

Topic 9 has three specified practicals. Each changes one factor while keeping the others constant:

  • SP9A — effect of one factor on rate using a gas collection method (e.g. acid + a metal or carbonate, collecting gas in a syringe).
  • SP9B — the "disappearing cross" reaction of dilute hydrochloric acid + sodium thiosulfate; time how long until a precipitate of sulfur clouds the mixture (turbidity).
  • SP9C — effect of various catalysts on the decomposition of hydrogen peroxide (e.g. manganese(IV) oxide), measuring oxygen given off.

In a non-enclosed system, mass falls as gas escapes — explain this with the particle model: gas particles leave the flask, so the mass on the balance drops.

Sort it

Will this speed it up?

Tap whether each change makes the reaction go faster or slower.

Reversible reactions

Reactions that go both ways

Some reactions are reversible — the products can react to re-form the reactants. We show this with the ⇌ symbol instead of a one-way arrow:

A + B ⇌ C + Dforward → and reverse ← happen at the same time

The energy change is equal but opposite in the two directions. If the forward reaction is exothermic (gives out heat), the reverse is endothermic (takes in the same amount of heat) — for example, hydrated and anhydrous copper(II) sulfate.

Eduqas: some reactions may be reversed by altering the reaction conditions (such as temperature).

Dynamic equilibrium

A balanced, busy state

In a closed system (nothing in or out), a reversible reaction reaches dynamic equilibrium: the rate of the forward reaction equals the rate of the reverse reaction, so the amounts of reactants and products stay constant.

closed system reactants products forward rate reverse rate forward rate = reverse rate
At equilibrium both reactions are still happening — they just happen at the same rate, so nothing appears to change.

Watch out: "dynamic" means the reactions have not stopped — they continue in both directions at equal rates. The amounts are constant, not zero.

Quick check

What is dynamic equilibrium?

?A reversible reaction in a sealed flask has reached dynamic equilibrium. Which statement is true?
Higher tier

Changing the conditions Higher

If you disturb a system at equilibrium, the position of equilibrium shifts to oppose the change (Le Chatelier's idea). You should be able to predict the effect of changing concentration, temperature and pressure:

  • Concentration: add more of a substance → equilibrium shifts to the other side to use it up.
  • Temperature: heat → shifts in the endothermic direction (to absorb the heat); cool → shifts the exothermic way.
  • Pressure (gases): increase pressure → shifts towards the side with fewer gas molecules.

Industrial link: in the Haber process (N₂ + 3H₂ ⇌ 2NH₃, studied in Topic 11), conditions are chosen to push the equilibrium towards ammonia and balance rate against yield. The forward reaction is exothermic, so a lower temperature favours more ammonia — but too low and the rate is too slow.

Watch out: Le Chatelier always opposes the change you make — add a reactant and the system removes some of it; heat an exothermic equilibrium and it shifts back the other way.

Predict Higher

Your turn — shifting equilibrium

2For 2SO₂(g) + O₂(g) ⇌ 2SO₃(g), the left has 3 gas molecules and the right has 2. Increasing the pressure shifts the equilibrium towards the side with fewer gas molecules. How many gas molecules are on the side it shifts to?
molecules
Hint: higher pressure favours the side with fewer gas molecules — count each side.
Match it Higher

Which way does it shift?

Tap a change on the left, then the matching shift on the right. (Reaction is exothermic forward, fewer gas molecules on the product side.)

Recap

The key ideas to know

Mean rate: quantity changed ÷ time (cm³/s, g/s)

Measuring rate: gas volume · loss of mass · colour/turbidity

Rate from a graph: gradient of the curve (tangent) — Higher

Factors: concentration/pressure · surface area · temperature · catalyst

Collision theory: more frequent and/or more energetic collisions; Ea = activation energy

Catalyst: lower Ea, alternative pathway, not used up; enzymes are biological catalysts

Reversible (⇌): energy change equal but opposite both ways

Dynamic equilibrium: forward rate = reverse rate in a closed system

Le Chatelier (Higher): equilibrium shifts to oppose a change

You've covered the whole of Eduqas Topic 9 — rate, the factors and their collision-theory explanations, catalysts and the required practicals, and reversible reactions reaching dynamic equilibrium. Press Finish to see your score.

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