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AQA GCSE Chemistry (8462) · 4.4 Chemical changes
Mini-Lesson

Chemical changes

This mini-lesson walks you through AQA Topic 4.4 — Chemical changes: the reactivity series, oxidation & reduction, extracting metals, the reactions of acids and salts, the pH scale, and electrolysis.

Make a guess: why does carbon free iron but not aluminium?

  1. Mission 1Why does carbon work for iron but not aluminium?
  2. Mission 2Why do only some acid reactions fizz?
  3. Mission 3Why does water change the product?

Work through each screen, answer the questions as you go (some are wordy, some are calculations or equations) and collect ⭐ stars. HT-only ideas are flagged in purple. Press Start when you're ready.

Oxidation & reduction · oxygen

Gaining and losing oxygen

Metals react with oxygen to make metal oxides. Because the metal gains oxygen, this is an oxidation reaction:

2Mg + O₂ → 2MgOmagnesium + oxygen → magnesium oxide (oxidation: Mg gains oxygen)

The opposite is reduction — the loss of oxygen. When copper oxide is heated with carbon, the copper oxide is reduced:

2CuO + C → 2Cu + CO₂copper(II) oxide loses oxygen (reduced); carbon gains oxygen (oxidised)

In terms of oxygen: OXidation = gain of OXygen; reduction = loss of oxygen. These two always happen together.

Quick check

Oxidised or reduced?

?In the reaction 2CuO + C → 2Cu + CO₂, what has happened to the copper oxide?
The reactivity series

Ordering metals by reactivity

The reactivity of a metal depends on its tendency to form positive ions. We arrange metals in a reactivity series, deduced from their reactions with water and dilute acids. The non-metals carbon and hydrogen are included for comparison:

most reactive more reactive Potassium K Sodium Na Lithium Li Calcium Ca Magnesium Mg Carbon C (non-metal) Zinc Zn Iron Fe Hydrogen H (non-metal) Copper Cu least reactive
AQA's reactivity series: K, Na, Li, Ca, Mg, then (carbon), then Zn, Fe, then (hydrogen), then Cu.

Why it matters: a more reactive metal displaces a less reactive metal from its compound — and a metal's position relative to carbon and hydrogen decides how it is extracted and how it reacts with acid.

Predict it

Will it displace?

A more reactive metal displaces a less reactive one. Tap the correct outcome each time.

Extraction of metals

Reduction with carbon vs electrolysis

Most metals are found in the Earth as compounds (ores) and must be extracted. How we do it depends on the metal's position in the reactivity series, compared with carbon:

  • Less reactive than carbon (e.g. zinc, iron, copper) → can be extracted by reduction with carbon. The metal oxide loses oxygen to the carbon.
  • More reactive than carbon (e.g. potassium, sodium, calcium, magnesium, aluminium) → carbon can't do it, so we use electrolysis.
2Fe₂O₃ + 3C → 4Fe + 3CO₂iron(III) oxide is reduced by carbon — it loses oxygen, carbon gains it

Gold and other very unreactive metals are found as the metal itself (native), so they need no chemical extraction at all.

Quick check

How would you extract it?

?Aluminium sits above carbon in the reactivity series. How must aluminium be extracted from its oxide?
Mission 1 check

Why does carbon work for iron but not aluminium?

?Zinc is below carbon in the reactivity series. Magnesium is above it. Heating zinc oxide with carbon gives zinc. Heating magnesium oxide with carbon gives no magnesium. Why?
Higher tier only

Redox in terms of electrons

At Higher tier, oxidation and reduction are defined by electrons, not just oxygen. Remember OIL RIG:

OIL RIGOxidation Is Loss of electrons · Reduction Is Gain of electrons

In a displacement reaction the more reactive metal loses electrons (oxidised); the less reactive metal ion gains electrons (reduced). The half equations show this:

Mg → Mg²⁺ + 2e⁻magnesium is oxidised — it loses 2 electrons
Cu²⁺ + 2e⁻ → Cucopper ions are reduced — they gain 2 electrons

Watch out (OIL RIG): it feels backwards, but losing electrons is oxidation and gaining electrons is reduction. The electrons lost must equal the electrons gained, so they cancel out of the full ionic equation.

Higher · Quick check

Loss or gain of electrons?

?In the half equation Zn → Zn²⁺ + 2e⁻, the zinc is…
Mission 2 of 3

Why do only some acid reactions fizz?

Make a guess: why do only some acid reactions fizz?

Reactions of acids · metals

Acid + metal → salt + hydrogen

Acids react with some metals (e.g. magnesium, zinc, iron) to make a salt and hydrogen gas:

acid + metal → salt + hydrogene.g. Mg + 2HCl → MgCl₂ + H₂

The salt's name comes from the acid: hydrochloric acid → chloride, sulfuric acid → sulfate, nitric acid → nitrate.

(HT) This is a redox reaction: the metal atoms lose electrons (oxidised) and the hydrogen ions gain electrons (reduced) to form H₂.

Name the salt

What salt forms?

?Zinc reacts with sulfuric acid. Name the salt produced.
Neutralisation & salts

Acid + base → salt + water

Acids are neutralised by bases. The base can be a metal oxide, a metal hydroxide (an alkali if soluble) or a metal carbonate:

acid + metal oxide → salt + water eg 2HCl + CuO → CuCl₂ + H₂O acid + metal hydroxide → salt + water eg H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O acid + carbonate → salt + water + CO₂ eg 2HCl + CaCO₃ → CaCl₂ + H₂O + CO₂
Acid + base → salt + water. With a carbonate you also get carbon dioxide.

Watch out (naming): the salt's second word comes from the acid (chloride / sulfate / nitrate); the first word comes from the metal in the base.

Balance it

Balance the neutralisation

1Balance: __ HCl + Ca(OH)₂ → CaCl₂ + 2H₂O. What number goes in front of HCl?
× HCl
Hint: there are 2 Cl on the right (CaCl₂) and 2 OH in Ca(OH)₂ to neutralise.
Required practical 1

Making a pure, dry soluble salt

A soluble salt can be made by reacting an acid with an insoluble solid (a metal, metal oxide, hydroxide or carbonate). The classic example is copper sulfate from sulfuric acid + copper oxide:

  • Warm the dilute acid (Bunsen burner), then add the insoluble solid a little at a time.
  • Keep adding until no more reacts (excess solid sits unreacted) — this ensures all the acid is used up.
  • Filter off the excess solid to leave a salt solution.
  • Crystallise: evaporate some water (water bath/electric heater), then leave to cool so crystals form. Pat dry.
H₂SO₄ + CuO → CuSO₄ + H₂Osulfuric acid + copper(II) oxide → copper(II) sulfate + water

Why excess solid? Using more base than the acid can dissolve guarantees the acid is fully neutralised — and the leftover solid is easy to filter out.

Quick check

Getting a pure salt

?When making copper sulfate, why is excess copper oxide added to the warm acid?
The pH scale & neutralisation

Acids, alkalis and pH

Acids produce hydrogen ions, H⁺ in water; alkalis contain hydroxide ions, OH⁻. The pH scale (0–14) measures acidity, read with universal indicator or a pH probe:

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 7 = neutral ← acidic (pH < 7) alkaline (pH > 7) → lower pH = more acidic · higher pH = more alkaline
Universal indicator: red strong acid → green neutral → purple strong alkali.

In neutralisation between an acid and an alkali, H⁺ and OH⁻ combine to make water:

H⁺ + OH⁻ → H₂Othe ionic equation for neutralisation

Watch out (pH): pH 7 is neutral. A lower pH means more acidic (not less!). pH above 7 is alkaline.

Quick check

Reading the pH scale

?Solution A has pH 2 and solution B has pH 5. Which statement is correct?
Mission 2 check

Why do only some acid reactions fizz?

?Dilute sulfuric acid is added to three tubes. One holds zinc, one copper(II) oxide and one copper(II) carbonate. Which statement explains which tubes fizz?
Required practical 2 · Chemistry only

Titration: finding reacting volumes

A titration measures exactly what volume of acid reacts with a known volume of alkali. An indicator shows the end-point. Use strong acids (hydrochloric, sulfuric, nitric) and strong alkalis.

  • Use a pipette to put 25.0 cm³ of alkali into a conical flask. Add a few drops of indicator.
  • Fill a burette with acid and read the start volume.
  • Add the acid while swirling, then drop by drop near the end, until the indicator just changes colour. Read the final volume.
  • Titre = final reading − start reading. Repeat until titres agree within 0.10 cm³ (concordant), then take their mean.

Higher tier: from the reacting volumes and one known concentration you can work out the other concentration in mol/dm³ and g/dm³ (see Quantitative chemistry).

Higher tier only

Strong vs weak acids

This is about how much an acid ionises in water — not the same as concentration:

  • A strong acid is completely ionised in solution (e.g. hydrochloric, nitric, sulfuric).
  • A weak acid is only partially ionised (e.g. ethanoic, citric, carbonic).
stronger acid → lower pHat the same concentration, more H⁺ ions means a lower pH

As the pH falls by 1 unit, the H⁺ concentration rises by a factor of 10. So pH 2 has ten times the H⁺ of pH 3.

Don't confuse two pairs: dilute/concentrated = amount of acid in a volume; weak/strong = degree of ionisation. A weak acid can still be concentrated.

Higher · Quick check

Strong, weak, dilute?

?Two solutions have the same concentration. One is hydrochloric acid (pH 1), one is ethanoic acid (pH 3). Why is the hydrochloric acid's pH lower?
Mission 3 of 3

Why does water change the product?

Make a guess: why does water stop sodium forming at the cathode?

Electrolysis · the process

Splitting compounds with electricity

When an ionic compound is melted or dissolved, its ions are free to move — it becomes an electrolyte. Passing a current makes the ions move to the electrodes, where they are discharged as elements:

− + cathode (−) anode (+) positive ions + negative ions − electrolyte (molten or aqueous) metal or hydrogen gain e⁻: reduced non-metal or oxygen lose e⁻: oxidised
Positive ions → cathode (–); negative ions → anode (+). Molten lead bromide gives lead at the cathode and bromine at the anode.

Watch out (cathode): at the cathode, positive ions gain electrons (reduction). "Cat-ions go to the cat-hode." At the anode, negative ions lose electrons (oxidation).

Aqueous solutions & aluminium

Rules for the products

With aqueous solutions, water also provides H⁺ and OH⁻ ions, so there is competition. The rules (inert electrodes):

  • Cathode (–): hydrogen is produced unless the metal is less reactive than hydrogen (e.g. copper) — then the metal is deposited.
  • Anode (+): oxygen is produced unless a halide (Cl⁻, Br⁻, I⁻) is present — then the halogen forms.

Reactive metals like aluminium are extracted by electrolysis of the molten oxide:

aluminium oxide dissolved in molten cryolitecryolite lowers the melting point, saving energy

The carbon anode burns away: oxygen made at the positive electrode reacts with the hot carbon to form CO₂, so the anode must be replaced regularly.

Sort it

Cathode or anode?

Electrolysis of aqueous copper chloride and sodium sulfate. Tap a product, then the electrode where it forms.

➖ Cathode

➕ Anode

Mission 3 check

Why does water change the product?

?Molten sodium bromide is electrolysed and sodium forms at the cathode. When a solution of sodium bromide in water is electrolysed, hydrogen forms there instead. Why?
Higher tier only

Half equations at the electrodes

At Higher tier you write half equations for each electrode. At the cathode ions gain electrons (reduction); at the anode ions lose electrons (oxidation):

Cathode: 2H⁺ + 2e⁻ → H₂hydrogen ions gain electrons — reduction
Anode: 4OH⁻ → O₂ + 2H₂O + 4e⁻hydroxide ions lose electrons — oxidation

For molten lead bromide the half equations are:

Pb²⁺ + 2e⁻ → Pb  ·  2Br⁻ → Br₂ + 2e⁻lead is reduced at the cathode; bromide is oxidised at the anode

Check the balance: atoms and charge must balance. In 2H⁺ + 2e⁻ → H₂ the 2 positive charges are cancelled by 2 electrons, giving neutral H₂.

Higher · Balance it

Complete the half equation

2Complete the cathode half equation: Al³⁺ + __ e⁻ → Al. How many electrons are gained?
electrons
Hint: the charge on Al³⁺ is 3+, so it needs 3 electrons to become a neutral Al atom.
Required practical 3 · aqueous electrolysis

Electrolysis of copper sulfate

In required practical 3 you electrolyse aqueous solutions with inert (carbon) electrodes, eg aqueous copper(II) sulfate, and observe what forms:

  • Cathode (–): a coating of copper appears — copper is less reactive than hydrogen, so the metal is deposited.
  • Anode (+): bubbles of oxygen are released (no halide is present).
Cathode: Cu²⁺ + 2e⁻ → Cucopper ions are reduced and deposited on the electrode

Investigation idea: changing the current or concentration changes the mass of copper deposited or the volume of gas collected — a good hypothesis to test.

Quick check

Products at the electrodes

?Aqueous copper sulfate is electrolysed with inert electrodes. What forms at the cathode?
Recap

The key ideas to know

Reactivity series: K Na Li Ca Mg (C) Zn Fe (H) Cu — more reactive displaces less reactive

Redox (oxygen): oxidation = gain O · reduction = loss O

Redox (electrons, HT): OIL RIG — Oxidation Is Loss, Reduction Is Gain

Extraction: below carbon → reduce with carbon · above carbon → electrolysis

Acids: + metal → salt + hydrogen · + base → salt + water · + carbonate → salt + water + CO₂

pH: 7 = neutral · <7 acid · >7 alkali · H⁺ + OH⁻ → H₂O

Titration (Chemistry only): pipette alkali · burette acid · indicator → end-point · repeat for concordant titres

Electrolysis: cathode (–) gains e⁻ (reduction) · anode (+) loses e⁻ (oxidation)

You've covered AQA 4.4 — reactivity of metals, reactions of acids (including titrations, Chemistry only), and electrolysis. Press Finish to see your score.

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