Eduqas OA2 is the oxygen family: alcohols and their oxidation, the surprising acidity of phenols, aldehydes and ketones and their nucleophilic addition, and finally carboxylic acids and their derivatives — acyl chlorides, esters and their hydrolysis.
Work through each screen, answer every question as you go — the multiple-choice checks, the calculations and the sorting games — and collect ⭐ stars. Press Start when you are ready.
OA2 · alcohols
Alcohols — classification and oxidation
Alcohols are primary, secondary or tertiary, according to how many carbons are attached to the carbon bearing the –OH.
Oxidation with acidified potassium dichromate(VI): the solution goes orange → green as Cr₂O₇²⁻ is reduced to Cr³⁺. The oxidising agent is written [O].
Primary + distil: the aldehyde is removed as it forms (it has the lowest boiling point — no hydrogen bonding).
Primary + reflux with excess oxidant: straight through to the carboxylic acid.
Secondary + reflux: the ketone, which resists further oxidation.
Tertiary:no reaction — there is no hydrogen on the C–OH carbon to remove.
Also: dehydration with hot concentrated H₂SO₄ or Al₂O₃ gives an alkene; and alcohols with a CH₃CH(OH)– group give the iodoform (triiodomethane) reaction — a yellow crystalline precipitate with I₂ and NaOH.
Quick check
Oxidise the secondary alcohol
?Butan-2-ol is refluxed with excess acidified potassium dichromate(VI). What is the product?
OA2 · phenols
Phenols — why they are acidic
In phenol, C₆H₅OH, a lone pair on the oxygen is delocalised into the ring. That has two big consequences.
Phenol is a weak acid, but far more acidic than an alcohol. Losing H⁺ gives the phenoxide ion, in which the negative charge is spread around the ring — so the anion is stabilised and the equilibrium lies further right. Phenol reacts with NaOH to give sodium phenoxide, but is too weak to react with Na₂CO₃ — it will not fizz. Carboxylic acids will.
The ring is activated. The extra electron density makes phenol much more reactive than benzene towards electrophiles. With bromine water (no halogen carrier, no heat) it gives an immediate white precipitate of 2,4,6-tribromophenol — and the bromine water is decolourised.
Two tests worth memorising: phenol gives a violet/purple colour with neutral iron(III) chloride solution; and a carboxylic acid fizzes with sodium carbonate while a phenol does not. Together they separate the two.
Quick check
Phenol and bromine water
?Phenol is added to bromine water at room temperature, with no catalyst. What is observed?
OA2 · carbonyls
Aldehydes and ketones — nucleophilic addition
The C=O bond is strongly polar (Cδ+=Oδ−) and planar. The δ+ carbon attracts nucleophiles, and the π bond can open — so carbonyls undergo nucleophilic addition.
With HCN (in the presence of KCN):
CH₃CHO + HCN → CH₃CH(OH)CN2-hydroxypropanenitrile — the carbon chain has grown by one
Mechanism: the CN⁻ nucleophile attacks the δ+ carbon; the π electrons shift onto the oxygen, giving an alkoxide intermediate; that oxygen then takes an H⁺ (from HCN or water). Since the C=O is planar, attack occurs equally from both faces — giving a racemate.
Reduction with NaBH₄ (a source of the hydride nucleophile, H⁻) reverses the oxidation: an aldehyde → a primary alcohol; a ketone → a secondary alcohol.
Quick check
Aldehyde or ketone?
?Which reagent distinguishes an aldehyde from a ketone?
Quick check
Name the nucleophile
?In the reaction of HCN with propanone, which species attacks the carbonyl carbon?
Calculate
Your turn — reduction yield
15.80 g of propanal (Mr = 58.0) is reduced with NaBH₄. The propan-1-ol formed (Mr = 60.0) weighs 4.80 g. Calculate the percentage yield.
%
Hint: n(propanal) = 5.80 ÷ 58.0 = 0.100 mol → theoretical mass of propan-1-ol = 0.100 × 60.0 = 6.00 g. Then (4.80 ÷ 6.00) × 100.
Sort it
Which family?
Tap a compound, then the family it belongs to.
🍺 Alcohol or phenol
🔶 Aldehyde or ketone
🧪 Acid or acid derivative
OA2 · carboxylic acids
Carboxylic acids
–COOH is a carbonyl and a hydroxyl on the same carbon. Carboxylic acids are weak acids — they only partially dissociate — but they are strong enough to displace CO₂ from carbonates:
2CH₃COOH + Na₂CO₃ → 2CH₃COONa + H₂O + CO₂C: 4 = 4 · Na: 2 = 2 · effervescence — a phenol will NOT do this
Why are they acidic at all? The carboxylate ion RCOO⁻ is stabilised by delocalisation of the negative charge over both oxygens — both C–O bonds become equal in length. An alkoxide ion (from an alcohol) has no such stabilisation, which is why alcohols are essentially neutral.
They also form hydrogen-bonded dimers, giving unexpectedly high boiling points, and the short-chain ones are very soluble in water.
Quick check
Tell them apart
?You have two colourless liquids: ethanoic acid and phenol. Which test separates them?
OA2 · derivatives
Acyl chlorides and esters
Acyl chlorides (RCOCl) are the most reactive derivative — the C is bonded to two electronegative atoms, so it is very strongly δ+. They react violently and irreversibly with any nucleophile, giving steamy HCl fumes:
CH₃COCl + H₂O → CH₃COOH + HClwith an alcohol → an ester · with ammonia → an amide · with an amine → a substituted amide
Esters are made by esterification — a carboxylic acid plus an alcohol, with a concentrated H₂SO₄ catalyst. This route is reversible and slow, so the yield is limited:
CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂Oethyl ethanoate · named alcohol-part FIRST, acid-part second
Hydrolysis of an ester:
Acid hydrolysis (dilute H₂SO₄, reflux) is reversible and gives back the carboxylic acid and the alcohol.
Alkaline hydrolysis (NaOH(aq), reflux) — saponification — goes to completion, because the product is the carboxylate salt, which cannot re-esterify. This is how soap is made from fats.
Esters have fruity smells and are used as flavourings, perfumes, solvents and plasticisers. Vegetable oils are esters of glycerol (propane-1,2,3-triol).
Calculate
Your turn — Mr of an ester
2Calculate the Mr of ethyl ethanoate, CH₃COOC₂H₅ (which is C₄H₈O₂). (Ar: C = 12.0, H = 1.0, O = 16.0)
30.200 mol of ethanoic acid is refluxed with an excess of ethanol. 12.3 g of ethyl ethanoate (Mr = 88.0) is obtained. Calculate the percentage yield.
%
Hint: theoretical mass = 0.200 × 88.0 = 17.6 g. Then (12.3 ÷ 17.6) × 100.
Calculate
Your turn — hydrolysing an acyl chloride
47.85 g of ethanoyl chloride, CH₃COCl (Mr = 78.5), is added to an excess of water. Calculate the mass of ethanoic acid (Mr = 60.0) formed, assuming a 100% yield.
g
Hint: n = 7.85 ÷ 78.5 = 0.100 mol. The ratio is 1 : 1, so mass = 0.100 × 60.0.
Quick check
Alkaline hydrolysis
?Ethyl ethanoate is refluxed with aqueous sodium hydroxide. What are the products?
Match it
Reagents and conditions
Tap a reagent and condition on the left, then its product on the right.