Edexcel A-level Chemistry (9CH0) · Topic 9: Kinetics I
Mini-Lesson
Kinetics I
This mini-lesson covers the whole of Edexcel Topic 9: how we measure rate, collision theory and activation energy, the Maxwell–Boltzmann distribution and what happens to it when you heat a gas, and how concentration, pressure, surface area, temperature and catalysts change the rate.
Work through each screen, answer the questions as you go (several are calculations) and collect ⭐ stars. Every calculation is worked through for you first. Press Start when you're ready.
Rate
What "rate of reaction" actually means
The rate of reaction is the change in the concentration (or amount) of a reactant or product per unit time.
rate = change in amount ÷ time takenunits: mol dm⁻³ s⁻¹ (concentration), cm³ s⁻¹ (gas volume) or g s⁻¹ (mass loss)
Anything that changes measurably as the reaction proceeds can be used to follow it:
Gas volume collected in a gas syringe (e.g. H₂ from Mg + HCl).
Mass loss on a balance as a gas escapes (e.g. CO₂ from CaCO₃ + HCl).
Colour change followed with a colorimeter (e.g. the fading purple of MnO₄⁻).
Titrating samples quenched at known times, or measuring pH / conductivity.
Mean rate vs initial rate. A mean rate divides the total change by the total time. The initial rate is the gradient of the tangent at t = 0 — it is the fastest rate, because the concentrations are highest then and nothing has been used up.
Rate
Reading a rate off a graph
The gradient of the tangent at any point gives the rate at that instant. The steepest point is always the start.
Worked example — mean rate
A reaction produces 45.0 cm³ of gas in 90.0 s.
mean rate = 45.0 ÷ 90.0 = 0.500 cm³ s⁻¹
Calculate
Your turn — mean rate from gas volume
1In a reaction between magnesium and hydrochloric acid, 24.0 cm³ of hydrogen is collected in 30.0 s. Calculate the mean rate in cm³ s⁻¹.
cm³ s⁻¹
Hint: rate = volume ÷ time = 24.0 ÷ 30.0.
Calculate
Your turn — mean rate from mass loss
2Calcium carbonate reacts with hydrochloric acid on a balance. The flask loses 0.960 g of CO₂ in 120 s. Calculate the mean rate of mass loss in g s⁻¹.
g s⁻¹
Hint: rate = 0.960 ÷ 120. Expect a small number — write it as a decimal, e.g. 0.00xx.
Calculate
Your turn — rate in mol dm⁻³ s⁻¹
3The concentration of a reactant falls from 0.500 mol dm⁻³ to 0.380 mol dm⁻³ in 60.0 s. Calculate the mean rate of reaction in mol dm⁻³ s⁻¹.
mol dm⁻³ s⁻¹
Hint: change = 0.500 − 0.380 = 0.120 mol dm⁻³. Rate = 0.120 ÷ 60.0. (Rate is quoted as a positive number.)
Calculate
Your turn — initial rate from a tangent
4A tangent drawn at t = 0 on a volume-against-time graph passes through the origin (0 s, 0 cm³) and the point (40.0 s, 36.0 cm³). Calculate the initial rate in cm³ s⁻¹.
cm³ s⁻¹
Hint: the initial rate is the gradient of the tangent: (36.0 − 0) ÷ (40.0 − 0).
Stoichiometry
Turning moles into a rate
Exam questions often make you do the mole arithmetic before you can find the rate. Remember: at room temperature and pressure, 1 mol of any gas occupies 24 000 cm³ (24.0 dm³).
Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)1 mol of Mg gives exactly 1 mol of H₂
Worked example
0.0600 g of magnesium (Ar = 24.0) reacts completely with excess acid in 25.0 s.
50.100 g of magnesium (Ar = 24.0) reacts completely with excess hydrochloric acid. Calculate the volume of H₂ produced, in cm³, at room temperature and pressure (molar volume = 24 000 cm³ mol⁻¹).
cm³
Hint: n(Mg) = 0.100 ÷ 24.0 = 0.004167 mol. n(H₂) is the same (1 : 1). V = 0.004167 × 24 000.
Calculate
Your turn — and the rate
6That 100 cm³ of hydrogen is all collected in 50.0 s. Calculate the mean rate of hydrogen production in cm³ s⁻¹.
cm³ s⁻¹
Hint: rate = 100 ÷ 50.0.
Collision theory
Collision theory and activation energy
For particles to react they must collide — but the overwhelming majority of collisions achieve nothing. A collision is successful only if:
the colliding particles have a combined energy greater than or equal to the activation energy, Ea; and
they collide in the correct orientation (the reacting parts of the molecules must meet).
Ea = the minimum energy that colliding particles must have for a reaction to occurit is the energy needed to start breaking bonds and reach the transition state
So the rate depends on the frequency of successful collisions — and every single factor below works by changing either how often particles collide, or what fraction of those collisions has E ≥ Ea.
A high Ea means a slow reaction at a given temperature, because only a tiny fraction of molecules have enough energy. This is why a mixture of petrol vapour and air sits happily in a fuel tank until a spark supplies the activation energy.
Quick check
Defining activation energy
7Which is the correct definition of activation energy?
Maxwell–Boltzmann
The Maxwell–Boltzmann distribution
At any temperature the molecules in a gas do not all have the same energy. The Maxwell–Boltzmann distribution shows how molecular energies are spread out.
The curve starts at the origin (no molecule has zero energy) and never touches the x-axis again (there is no upper limit on energy).
The peak is the most probable energy — not the mean. The mean energy is slightly to the right of the peak because the curve is not symmetrical.
The total area under the curve = the total number of molecules.
The area beyond Ea = the number of molecules with enough energy to react. It is a tiny fraction of the total.
Temperature
What temperature does to the distribution
Raise the temperature and the whole distribution changes shape:
At the higher temperature the peak is lower and further right, and the curve is flatter and broader — but the area stays the same, because the number of molecules has not changed.
The molecules have more kinetic energy, so they move faster and collide more frequently.
Far more importantly, a much greater proportion of molecules now has E ≥ Ea — the area beyond Ea grows dramatically.
Exam gold: a 10 K rise typically doubles the rate, yet it raises the mean speed by only about 2%. That is far too small to explain a doubling by "more frequent collisions" alone — the increase comes overwhelmingly from the fraction of molecules exceeding Ea. Say this and you get the mark.
Quick check
Why heating works
8Raising the temperature by 10 K roughly doubles the rate of many reactions. What is the main reason?
Quick check
Reading the curve
9Which statement about the Maxwell–Boltzmann distribution is correct?
Factors
Concentration, pressure and surface area
Concentration ↑ — more particles in the same volume, so the particles are closer together and collide more frequently. The proportion of successful collisions is unchanged; there are simply more collisions per second.
Pressure ↑ (gases, at constant temperature) — squeezing the same number of molecules into a smaller volume raises the concentration of the gases. Same explanation: more frequent collisions.
Surface area ↑ (a solid reactant) — grinding a lump into a powder exposes more particles at the surface where the other reactant can reach them, so collisions are more frequent. The mass is the same; the accessible surface is not.
Two traps. (1) Adding an inert gas at constant volume raises the total pressure but does not change the concentration of the reactants — so the rate is unchanged. (2) Pressure has essentially no effect on reactions between liquids or solutions, which are almost incompressible.
Quick check
An inert gas
10Argon is pumped into a sealed, rigid vessel in which two gases are reacting. The total pressure rises. What happens to the rate?
Catalysts
Catalysts and activation energy
A catalyst increases the rate of a reaction by providing an alternative reaction pathway with a lower activation energy. It is not used up — it is regenerated at the end, so a tiny amount catalyses a huge quantity of reaction.
The catalyst lowers the barrier, not the destination. Both routes start and finish at the same enthalpies, so ΔH is unchanged.
A lower Ea means a much larger proportion of molecules has enough energy to react — draw a second dashed line further left on your Maxwell–Boltzmann curve and the shaded area leaps up.
Heterogeneous catalyst — in a different phase from the reactants (e.g. solid Fe in the Haber process); reaction happens on the surface.
Homogeneous catalyst — in the same phase (e.g. Cl• radicals catalysing ozone breakdown in the gas phase).
What a catalyst does NOT do: it does not change ΔH, it does not shift the position of an equilibrium, and it does not "lower the energy of the reactants". It offers a different route.
Quick check
What a catalyst does
11Which statement about a catalyst is correct?
Quick check
Why powders react faster
125.0 g of powdered CaCO₃ reacts with acid much faster than a single 5.0 g lump. Why?
Sort it
Faster, slower — or no change?
A reaction between two gases is running in a sealed, rigid vessel, alongside a solid + acid reaction on the bench. Tap a change, then tap what it does to the rate.
⬆️ Increases the rate
⬇️ Decreases the rate
➡️ No change to the rate
Match it
Match the factor to the explanation
Tap an item on the left, then its partner on the right.
Factor
Why the rate changes
Recap
The big ideas to know
Rate: change in amount ÷ time; follow it by gas volume, mass loss, colour or titration
Initial rate: gradient of the tangent at t = 0 — the fastest point of the reaction
Collision theory: particles must collide with E ≥ Eaand in the correct orientation
Ea: the minimum energy colliding particles need for a reaction to occur
Maxwell–Boltzmann: starts at the origin, never touches the axis again; area = total molecules; area beyond Ea = molecules that can react
Higher T: peak lower and further right, same area — a far greater fraction has E ≥ Ea (the dominant effect), plus slightly more frequent collisions
Higher conc / pressure / surface area: collisions are more frequent (the proportion that succeeds is unchanged)
Catalyst: alternative route with lower Ea; not used up; ΔH unchanged; equilibrium position unchanged
You've now covered Topic 9: Kinetics I of the Edexcel A-level Chemistry (9CH0) specification. Press Finish to see your score.
🏆
Mini-lesson complete!
⭐⭐⭐
You've worked through Kinetics I for Edexcel A-level Chemistry. 🎉
Your stars: 0 / 0
Next: test yourself in the Evaluate stage Confidence Quiz, then lock it in with Verify.
📣 Smashed it? Share your score
Challenge a mate to beat your stars, or show a parent how you got on.