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Edexcel A-level Chemistry (9CH0) · Topic 1: Atomic Structure and the Periodic Table
Mini-Lesson

Atomic Structure & the Periodic Table

This mini-lesson covers the whole of Edexcel Topic 1: isotopes and relative masses, mass spectrometry (including diatomic patterns), ionisation energies and the evidence they give for electronic structure, and orbitals, sub-shells and periodicity.

mass spectra ionisation energies orbitals & periodicity the electronic structure of an atom controls all of its chemistry

Work through each screen, answer the questions as you go (some are wordy, some are calculations) and collect ⭐ stars. Every calculation is worked through for you first. Press Start when you're ready.

Atoms · isotopes

Isotopes and relative masses

Atoms of the same element always have the same number of protons (the atomic number, Z) but can have different numbers of neutrons. Those variants are isotopes. Because chemistry is controlled by electrons, isotopes of an element are chemically identical — they differ only in mass (so in physical properties such as density and rate of diffusion).

  • Relative isotopic mass — the mass of an atom of an isotope relative to 112 the mass of a carbon-12 atom.
  • Relative atomic mass, Ar — the weighted mean mass of the atoms of an element, relative to 112 the mass of a carbon-12 atom.
  • Relative molecular mass, Mr — the same idea applied to a molecule (use relative formula mass for giant/ionic structures such as NaCl).
Ar = Σ(isotopic mass × abundance) ÷ Σ(abundance)if the abundances are percentages that add to 100, just divide by 100

Exam habit: relative masses have no units — they are ratios. Quote Ar to the same precision as the data you were given (usually 1 or 2 decimal places).

Mass spectrometry

How a mass spectrometer measures Ar

A time-of-flight (TOF) mass spectrometer separates particles by their mass/charge ratio (m/z):

  • Ionisation — electron impact (a high-energy electron knocks one electron out) or electrospray (the sample is protonated). Only ions can be accelerated and deflected by electric/magnetic fields.
  • Acceleration — all ions are given the same kinetic energy, so heavier ions travel more slowly.
  • Flight tube / detection — the lighter the ion, the shorter its time of flight; the detector records the abundance of each m/z.

For a singly charged ion (z = 1), the m/z value is the relative mass of that ion.

Worked example — Ar of chlorine

Peaks: m/z 35 (75.0%) and m/z 37 (25.0%).

Ar = (35 × 75.0 + 37 × 25.0) ÷ 100 = (2625 + 925) ÷ 100 = 35.5

Calculate

Your turn — weighted mean mass

1Boron exists as ¹⁰B (19.9%) and ¹¹B (80.1%). Calculate the relative atomic mass of boron to 2 decimal places.
Hint: (10 × 19.9 + 11 × 80.1) ÷ 100 = (199.0 + 881.1) ÷ 100.
Calculate

Your turn — working backwards

2Chlorine has only two isotopes, ³⁵Cl and ³⁷Cl, and Ar(Cl) = 35.5. Calculate the percentage abundance of ³⁵Cl.
%
Hint: let x = fraction of ³⁵Cl. Then 35x + 37(1 − x) = 35.5, so 37 − 2x = 35.5.
Mass spectra

Diatomic molecules give a pattern of peaks

When a diatomic molecule of an element is ionised without fragmenting, you see a peak for every possible combination of isotopes — and the peak heights follow the probabilities.

Chlorine gas (³⁵Cl 75%, ³⁷Cl 25%) gives molecular ions at m/z 70, 72 and 74:

  • m/z 70 = ³⁵Cl–³⁵Cl → 0.75 × 0.75 = 0.5625
  • m/z 72 = ³⁵Cl–³⁷Cl (either way round) → 2 × 0.75 × 0.25 = 0.3750
  • m/z 74 = ³⁷Cl–³⁷Cl → 0.25 × 0.25 = 0.0625
70 : 72 : 74 = 9 : 6 : 1divide 0.5625 : 0.3750 : 0.0625 by 0.0625

Also expect peaks at m/z 35 and 37 from the Cl⁺ fragment, in a 3 : 1 ratio.

Calculate

Your turn — relative peak heights

3In the mass spectrum of Cl₂ above, calculate the ratio of the height of the m/z 70 peak to the height of the m/z 74 peak (give it as a single number, i.e. 70-peak ÷ 74-peak).
Hint: 0.75 × 0.75 = 0.5625 and 0.25 × 0.25 = 0.0625. Divide the first by the second.
Calculate

Your turn — real spectrometer data

4The mass spectrum of magnesium gives peak heights of 73.7 at m/z 24, 10.1 at m/z 25 and 11.2 at m/z 26. Calculate Ar(Mg) to 2 decimal places.
Hint: Σ(m/z × height) = 24×73.7 + 25×10.1 + 26×11.2 = 2312.5. Σ(heights) = 95.0. Now divide.
Ionisation energy

Defining ionisation energies

The first ionisation energy is the energy needed to remove one electron from each atom in one mole of gaseous atoms, forming one mole of gaseous 1+ ions.

X(g) → X⁺(g) + e⁻2nd IE: X⁺(g) → X²⁺(g) + e⁻ — always larger than the 1st

Ionisation energies are always endothermic (positive): you must do work against the attraction of the nucleus. Three factors decide the size:

  • Nuclear charge — more protons pull harder → higher IE.
  • Atomic radius — the further the electron, the weaker the attraction (attraction falls off with distance) → lower IE.
  • Shielding — inner-shell electrons repel the outer electron and screen it from the nucleus → lower IE.

Successive IEs always rise: each electron is pulled from an increasingly positive ion. A big jump means you have broken into a new (inner) shell — that is how IE data tells you the group number.

Quick check

Which equation shows the second ionisation energy of calcium?

5The second ionisation energy of calcium is represented by which equation?
Calculate

Your turn — reading IE data

6The successive ionisation energies of element X (in kJ mol⁻¹) are 738, 1451, 7733, 10 540. Which group of the Periodic Table is X in?
Group
Hint: find the big jump. It comes after 2 electrons have been removed — those 2 were the outer-shell electrons.
Trends

Ionisation energy across a period and down a group

Across Period 3 (Na → Ar) the first ionisation energy generally increases: the nuclear charge rises, the electrons enter the same shell so shielding is roughly constant, and the atomic radius falls. The outer electron is held more tightly.

Down a group (e.g. Li → Cs) the first ionisation energy decreases: each element has an extra full inner shell, so the outer electron is further from the nucleus and better shielded. This outweighs the increase in nuclear charge.

1st IE NaMgAlSi PSClAr 3p starts 3p pairing
The two dips (Mg→Al and P→S) are the experimental evidence for sub-shells and orbitals.
Quick check

Why does aluminium buck the trend?

7The first ionisation energy of aluminium (578 kJ mol⁻¹) is lower than that of magnesium (738 kJ mol⁻¹), even though Al has one more proton. Why?
Quick check

And the sulfur dip?

8The first ionisation energy of sulfur is lower than that of phosphorus. The best explanation is that in sulfur…
Orbitals

Shells, sub-shells and orbitals

An orbital is a region of space in an atom that can hold up to two electrons — and only if they have opposite spins.

  • s orbitals are spherical; there is one per shell → an s sub-shell holds 2 electrons.
  • p orbitals are dumb-bell shaped, in three orientations (px, py, pz) → a p sub-shell holds 6.
  • A d sub-shell has 5 orbitals → 10 electrons; an f sub-shell holds 14.

Quantum shells fill 2, 8, 18, 32 (= 2n²) electrons. Electrons fill the lowest energy sub-shell first, and 4s fills before 3d because 4s is slightly lower in energy.

s orbital — spherical p orbital — dumb-bell
Each orbital — whatever its shape — holds a maximum of two electrons with opposite spins.
Configurations

Writing electronic configurations

Fill in order of increasing energy: 1s 2s 2p 3s 3p 4s 3d 4p. Within a sub-shell, electrons occupy orbitals singly first (Hund's rule) before pairing up.

  • Ti: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d² 4s² — or [Ar] 3d² 4s²
  • Exceptions: Cr = [Ar] 3d⁵ 4s¹ and Cu = [Ar] 3d¹⁰ 4s¹ (a half-full or full d sub-shell is more stable).
  • Ions of d-block metals lose 4s electrons first: Fe = [Ar] 3d⁶ 4s² → Fe²⁺ = [Ar] 3d⁶ → Fe³⁺ = [Ar] 3d⁵.

Blocks: the block is named after the sub-shell the outermost electron occupies — s-block (Groups 1 and 2), p-block (Groups 3–0), d-block (the transition series).

Quick check

d-block ions

9What is the electronic configuration of the Fe³⁺ ion?
Sort it

s-block, p-block or d-block?

Tap an element, then tap the block its electronic configuration puts it in.

🟩 s-block

🟦 p-block

🟪 d-block

Quick check

Why ionise the sample?

10In a mass spectrometer, why must the sample be ionised before analysis?
Periodicity

Periodicity across Period 3

Periodicity = a repeating pattern of properties across the periods, caused by the repeating pattern of electronic configurations.

  • Atomic radius decreases across a period: more protons, same shell, same shielding → electrons pulled in.
  • First ionisation energy increases across a period (with the Al and S dips).
  • Melting temperature across Period 3: rises Na < Mg < Al (metallic bonding gets stronger: more delocalised electrons per atom, smaller ion), peaks sharply at Si (giant covalent — strong covalent bonds must break), then collapses at P₄, S₈, Cl₂ and Ar (simple molecular — only weak London forces between molecules; S₈ > P₄ > Cl₂ because larger molecules have more electrons).

Exam trap: when you explain the drop after silicon, say that intermolecular (London) forces are overcome — not covalent bonds.

Quick check

Melting temperatures in Period 3

11Why does silicon have by far the highest melting temperature in Period 3?
Match it

Match the idea to the evidence

Tap an item on the left, then its partner on the right.

Observation
Explanation
Recap

The big ideas to know

Relative atomic mass: weighted mean mass of the isotopes of an element, relative to 1/12 the mass of a ¹²C atom

Mass spectrometry: ionise → accelerate → separate by m/z → detect; Ar = Σ(m/z × abundance) ÷ Σ(abundance)

1st ionisation energy: X(g) → X⁺(g) + e⁻; depends on nuclear charge, atomic radius and shielding

Trends: IE increases across a period (Z⁺ up, radius down) and falls down a group (radius and shielding up)

Small dips: Al < Mg (3p above 3s) and S < P (paired 3p electrons repel) — evidence for sub-shells

Orbitals: s = spherical, p = dumb-bell; each holds 2 electrons of opposite spin; s(2) p(6) d(10)

Filling: lowest energy first; 4s fills before 3d — and 4s empties first when d-block ions form

You've now covered Topic 1: Atomic Structure and the Periodic Table of the Edexcel A-level Chemistry (9CH0) specification. Press Finish to see your score.

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