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AQA A-level Chemistry (7405) · Alcohols, Aldehydes, Ketones & Carboxylic Acids
Mini-Lesson

Alcohols, Aldehydes, Ketones & Carboxylic Acids

This mini-lesson covers AQA 3.3.5 Alcohols, 3.3.8 Aldehydes and ketones and 3.3.9 Carboxylic acids and derivatives: oxidation of primary and secondary alcohols (and why the apparatus decides the product), nucleophilic addition, the Tollens and Fehling tests, esterification, and the reactions of acyl chlorides and anhydrides.

alcohols & oxidation carbonyls & nucleophiles acids & derivatives the C=O carbon is δ+ — so carbonyls are attacked by nucleophiles

Work through each screen, answer the questions as you go (some are wordy, most are calculations) and collect ⭐ stars. Everything here is A-level standard — the maths is done properly, not skipped. Press Start when you're ready.

Alcohols · oxidation

Classifying and oxidising alcohols

Classify by the number of carbon atoms attached to the carbon carrying the OH: primary (0 or 1), secondary (2), tertiary (3).

The oxidising agent is acidified potassium dichromate(VI), K₂Cr₂O₇/H₂SO₄ — orange Cr₂O₇²⁻ is reduced to green Cr³⁺. We write the oxidising agent as [O].

  • Primary alcohol → aldehyde → carboxylic acid. The apparatus decides which you get:
    • Distil the product off as it forms → you isolate the aldehyde (it has a lower boiling point than the alcohol, because it cannot hydrogen bond to itself).
    • Heat under reflux with excess oxidising agent → the aldehyde stays in the flask and is oxidised again → the carboxylic acid.
  • Secondary alcohol → ketone (and no further — there is no H on the carbonyl carbon to remove).
  • Tertiary alcohol → no reaction. There is no hydrogen atom on the C–OH carbon to be removed, so it cannot be oxidised without breaking a C–C bond.
CH₃CH₂OH + [O] → CH₃CHO + H₂Oethanol → ethanal (distil) · then CH₃CHO + [O] → CH₃COOH (reflux)

Reflux means "boil without losing anything": the vertical condenser returns the vapour to the flask, so volatile products cannot escape and the mixture can be heated for a long time. Distillation does the opposite — it deliberately removes the product the moment it forms.

Sort it

Classify each alcohol

Tap an alcohol, then tap whether it is primary, secondary or tertiary.

🟩 Primary alcohol

🟪 Secondary alcohol

🟦 Tertiary alcohol

Quick check

Quick check

?A student wants to make ethanal (not ethanoic acid) from ethanol. Which apparatus should they use?
Calculate

Your turn

10.100 mol of ethanol is oxidised to ethanal (Mr = 44.0). The theoretical mass is 4.40 g but only 3.30 g is collected. Calculate the percentage yield.
%
Hint: Theoretical mass = 0.100 × 44.0 = 4.40 g. % yield = (3.30 ÷ 4.40) × 100.
Carbonyls · nucleophilic addition

Aldehydes, ketones and nucleophilic addition

The C=O bond is strongly polar: oxygen is far more electronegative, so the carbon is δ+. That makes carbonyls a target for nucleophiles — the opposite of alkenes, which attract electrophiles.

Reduction with NaBH₄ (in aqueous methanol) — the nucleophile is the hydride ion, H⁻:

  • Aldehyde + 2[H] → primary alcohol (e.g. CH₃CHO + 2[H] → CH₃CH₂OH)
  • Ketone + 2[H] → secondary alcohol

Addition of HCN (using KCN followed by dilute acid) — the nucleophile is the cyanide ion, CN⁻. This produces a hydroxynitrile and, crucially, adds a carbon atom to the chain:

CH₃CHO + HCN → CH₃CH(OH)CN2-hydroxypropanenitrile — the chain has grown from 2 carbons to 3

The mechanism: CN⁻ attacks the δ+ carbon (curly arrow from the lone pair on carbon); the C=O π electrons move onto the oxygen, giving an intermediate with a negatively charged oxygen; that oxygen then takes a proton from H⁺ or water.

Why HCN addition gives a racemic mixture. The carbonyl group is planar, so the cyanide ion can attack from either face with equal probability. If the product has a chiral centre, both enantiomers form in equal amounts — an optically inactive racemate.

Hazard: KCN and HCN are extremely toxic, so this reaction is done in a fume cupboard.

Quick check

Quick check

?How would you distinguish between propanal and propanone?
Carboxylic acids · esters

Carboxylic acids and esterification

Carboxylic acids are weak acids (only partially dissociated), but they are strong enough for one decisive test:

2CH₃COOH + Na₂CO₃ → 2CH₃COONa + H₂O + CO₂effervescence — a carboxylic acid releases CO₂ from a carbonate. Check: Na 2, C 5, H 8, O 7 both sides ✓

Esterification — a carboxylic acid plus an alcohol, with a concentrated sulfuric acid catalyst. It is reversible, so the yield is limited:

CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂Oethanoic acid + ethanol ⇌ ethyl ethanoate + water

Esters are named alcohol part first, then the acid part: ethyl ethanoate. They have sweet, fruity smells and are used as solvents, plasticisers, perfumes and flavourings.

Ester hydrolysis:

  • Acid hydrolysis (dilute acid, reflux) is reversible and gives the carboxylic acid + alcohol.
  • Base hydrolysis (dilute NaOH, reflux) goes to completion and gives the carboxylate salt + alcohol. Applied to a fat, this is saponification — it makes soap plus glycerol (propane-1,2,3-triol).

Biodiesel is a mixture of methyl esters of long-chain carboxylic acids, made by reacting vegetable oil with methanol using a KOH catalyst.

Calculate

Your turn

2Calculate the relative molecular mass of ethyl ethanoate, CH₃COOC₂H₅ (C₄H₈O₂). (C = 12.0, H = 1.0, O = 16.0)
Hint: M_r = 4(12.0) + 8(1.0) + 2(16.0).
Calculate

Your turn

30.200 mol of ethanoic acid reacts with excess ethanol. Calculate the theoretical mass of ethyl ethanoate (Mr = 88.0) that could form.
g
Hint: The ratio is 1 : 1, so n(ester) = 0.200 mol. m = n × M_r.
Calculate

Your turn

4Calculate the atom economy for CH₃COOH + C₂H₅OH → CH₃COOC₂H₅ + H₂O. (Mr: acid = 60.0, ethanol = 46.0, ester = 88.0, water = 18.0)
%
Hint: Atom economy = 88.0 ÷ (88.0 + 18.0) × 100 — or equivalently 88.0 ÷ (60.0 + 46.0) × 100.
Derivatives · acyl chlorides

Acyl chlorides and acid anhydrides

Acyl chlorides (RCOCl) are the most reactive carboxylic acid derivatives. Every reaction follows the same pattern — a nucleophile replaces the Cl, and HCl gas is given off (steamy white fumes):

  • + water → carboxylic acid: CH₃COCl + H₂O → CH₃COOH + HCl (violent, at room temperature)
  • + alcohol → ester: CH₃COCl + CH₃OH → CH₃COOCH₃ + HCl (fast, irreversible, and gives a much better yield than esterification)
  • + ammonia → amide: CH₃COCl + 2NH₃ → CH₃CONH₂ + NH₄Cl
  • + primary amine → N-substituted amide: CH₃COCl + 2CH₃NH₂ → CH₃CONHCH₃ + CH₃NH₃Cl

Acid anhydrides ((RCO)₂O) do exactly the same chemistry but more gently, releasing the carboxylic acid instead of corrosive HCl gas:

(CH₃CO)₂O + H₂O → 2CH₃COOHcheck: C 4 = 4 · H 6 + 2 = 8 = 8 · O 3 + 1 = 4 = 4 ✓ (do not forget the water)

Why aspirin is made with ethanoic anhydride, not ethanoyl chloride. The anhydride is cheaper, less corrosive, less vulnerable to hydrolysis by moisture and does not produce dangerous HCl fumes — a genuine industrial-safety judgement, and a favourite exam question.

Match it

Match the reagent to its result

Tap a reagent on the left, then its result on the right.

Reagent
Result
Quick check

Quick check

?Why can a tertiary alcohol not be oxidised by acidified potassium dichromate(VI)?
Quick check

Quick check

?Aspirin is manufactured using ethanoic anhydride rather than ethanoyl chloride. Give the best reason.
Carbonyls · exam traps

Apparatus, tests and the reactions that go nowhere

  • The apparatus decides the product. Distil → aldehyde. Reflux → carboxylic acid. If the question shows a diagram, read it before you answer.
  • Tollens’ and Fehling’s are positive for ALDEHYDES only. They are gentle oxidising agents, and a ketone has no H on the carbonyl carbon to remove.
  • A tertiary alcohol cannot be oxidised — no hydrogen on the C–OH carbon.
  • Only a carboxylic acid gives CO₂ with a carbonate. Alcohols and phenols do not — this is the definitive test.

Nucleophilic addition, in one sentence: "The C=O carbon is δ+ because oxygen is more electronegative, so it is attacked by a nucleophile; the π electrons shift onto the oxygen, giving a negatively charged intermediate, which is then protonated." That sentence, plus correct arrows, is full marks.

Quick check

Quick check

?NaBH₄ is added to propanal. What is the product?
Calculate

Your turn

5Calculate the relative molecular mass of propanone, CH₃COCH₃ (C₃H₆O). (C = 12.0, H = 1.0, O = 16.0)
Hint: M_r = 3(12.0) + 6(1.0) + 16.0.
Recap

The big ideas to know

Classifying alcohols: primary, secondary or tertiary — by the number of carbons attached to the C–OH carbon

Oxidation: 1° → distil to get the aldehyde; reflux to get the carboxylic acid. 2° → ketone. 3° → no oxidation

Elimination: alcohol + conc. H₂SO₄ (or Al₂O₃), heat → an alkene (dehydration)

Nucleophilic addition: KCN/H⁺ gives a hydroxynitrile (adds a carbon); NaBH₄ reduces the carbonyl to an alcohol

Distinguishing tests: Tollens’ (silver mirror) and Fehling’s (brick-red ppt) are positive for aldehydes only

Carboxylic acids: weak acids, but strong enough to release CO₂ from a carbonate — which phenols cannot do

Derivatives: acyl chlorides react vigorously with water, alcohols, ammonia and amines, releasing HCl each time

That is AQA 3.3.5, 3.3.8 and 3.3.9. Press Finish.

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