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OCR A-level Biology A (H420) · Genetics, Evolution & Ecosystems
Mini-Lesson

Genetics, evolution & ecosystems

This mini-lesson covers OCR Module 6 — Genetics, evolution and ecosystems: cellular control (mutations, the lac operon, apoptosis and homeobox genes); patterns of inheritance (dihybrid crosses, epistasis, chi-squared and the Hardy-Weinberg principle); manipulating genomes (PCR, electrophoresis, sequencing, genetic engineering); cloning and biotechnology; and ecosystems — energy transfer, succession, and populations and sustainability.

Work through each screen, answer the questions as you go (some are extended-recall, some are calculations) and collect ⭐ stars. This is A-level content — expect quantitative work and mechanism-level detail. Press Start when you are ready.

Cellular control

Mutations and the lac operon

A substitution may be silent (the code is degenerate), missense (a different amino acid) or nonsense (a premature stop codon). An insertion or deletion causes a frameshift, changing every triplet downstream — almost always catastrophic.

The lac operon — the classic example of transcriptional control in a prokaryote. E. coli normally respires glucose. It only makes the enzymes for lactose metabolism when lactose is actually present, because making them otherwise would waste energy.

  • The operon consists of a promoter, an operator, and the structural genes lacZ (β-galactosidase, which hydrolyses lactose) and lacY (lactose permease, which transports lactose in).
  • A separate regulatory gene continuously produces a repressor protein.
  • No lactose: the repressor binds to the operator, physically blocking RNA polymerase from binding to the promoter. The genes are not transcribed.
  • Lactose present: lactose binds to the repressor, changing its shape so that it can no longer bind the operator. It detaches, RNA polymerase binds the promoter, and the structural genes are transcribed — the enzymes are made.

Do not say the lactose "switches the gene on". It inactivates the repressor. The gene was always able to be transcribed; it was being blocked. Precision here is worth marks.

Cellular control

Apoptosis and homeobox genes

Apoptosis is programmed cell death: an orderly, controlled sequence in which enzymes break down the cytoskeleton, the cell shrinks, the membrane blebs, chromatin condenses, DNA is fragmented, and the fragments are engulfed by phagocytes without inflammation. Contrast necrosis, which is uncontrolled death after injury, releasing hydrolytic enzymes and causing inflammation.

Apoptosis is essential in development — it is what removes the webbing between the fingers of a developing embryo — and in removing damaged or infected cells. Too little apoptosis allows damaged cells to persist and contributes to cancer; too much contributes to neurodegenerative disease.

Homeobox genes control the body plan: they specify what develops where along the head-to-tail axis. They contain a highly conserved 180-base-pair homeobox sequence, which codes for a 60-amino-acid homeodomain that binds DNA — so their products are transcription factors that switch whole batteries of other genes on or off.

Why the conservation matters: homeobox sequences are strikingly similar in animals, plants and fungi. Such deep conservation across kingdoms is powerful evidence of a common ancestor, and it means that the equivalent gene in a fruit fly can inform us about human development.

Quick check

The repressor

?A mutation makes the lac repressor protein unable to bind lactose (but it can still bind the operator). What is the effect on the bacterium?
Inheritance

Dihybrid crosses, linkage and epistasis

Monohybrid: Aa × Aa → 3:1. Dihybrid (two unlinked genes): AaBb × AaBb → 9:3:3:1. A test cross against the homozygous recessive reveals an unknown genotype.

  • Codominance — both alleles are expressed in the heterozygote (blood group AB). Multiple alleles — more than two alleles exist in the population (IA, IB, IO), though any individual has only two.
  • Sex linkage — a gene on the X chromosome. Males (XY) have a single copy, so a recessive allele is always expressed. Haemophilia and red-green colour blindness are far commoner in males, and a male cannot be a carrier.
  • Autosomal linkage — genes on the same chromosome are inherited together unless separated by crossing over. The result is an excess of parental phenotypes and far fewer recombinants than 9:3:3:1 would predict.
  • Epistasis — one gene masks or modifies the expression of another at a different locus. If the gene producing a pigment precursor is homozygous recessive, no pigment can be made at all, whatever the second gene says. Look for ratios such as 9:3:4, 9:7 or 12:3:1.

Continuous variation (height, mass) is polygenic: many genes each of small effect, plus a strong environmental contribution, giving a normal distribution. Discontinuous variation is controlled by one or few genes and gives discrete categories.

Calculate

Your turn — chi-squared

1A monohybrid cross predicts a 3:1 ratio. Of 120 offspring, 82 show the dominant phenotype and 38 the recessive. Calculate χ² = Σ(O − E)² ÷ E. Give your answer to 2 decimal places.
χ²
Hint: Expected = 90 and 30. χ² = (82 − 90)²/90 + (38 − 30)²/30 = 64/90 + 64/30.
Quick check

What does χ² = 2.84 mean?

?For the cross above there is 1 degree of freedom, and the critical value at p = 0.05 is 3.84. What do you conclude?
Population genetics

The Hardy-Weinberg principle

Hardy-Weinberg lets you calculate allele frequencies in a population from the phenotypes you can count.

p + q = 1p = frequency of the dominant allele · q = frequency of the recessive allele
p² + 2pq + q² = 1p² = homozygous dominant · 2pq = heterozygous carriers · q² = homozygous recessive

Always start with the recessive phenotype, because it is the only genotype you can identify with certainty. Its frequency is ; take the square root to get q; then p = 1 − q; then calculate 2pq.

The five assumptions: a large population; random mating; no selection; no mutation; and no migration. If measured frequencies deviate from those predicted, one of these has been violated — which is itself evidence that the population is evolving. In small populations, genetic drift alone can change allele frequencies purely by chance.

Calculate

Your turn — Hardy-Weinberg

2A recessive genetic disorder affects 1 in 10 000 people. Assuming Hardy-Weinberg equilibrium, calculate the percentage of the population who are heterozygous carriers. Give your answer to 2 decimal places.
%
Hint: q² = 0.0001, so q = 0.01 and p = 0.99. Carriers = 2pq = 2 × 0.99 × 0.01.
Manipulating genomes

PCR, electrophoresis and genetic engineering

PCR amplifies DNA in vitro, doubling it every cycle: denaturation at 95 °C (hydrogen bonds break), annealing at 55–65 °C (primers bind), extension at 72 °C (Taq polymerase, from a thermophile, so it survives the 95 °C step, builds the new strands).

molecules after n cycles = starting number × 2ⁿ

Gel electrophoresis: DNA is negatively charged because of its phosphate groups, so it migrates towards the anode (+). Smaller fragments travel further through the gel. Fragments are therefore separated by length, and compared with a ladder of known sizes.

Genetic engineering: isolate the gene (reverse transcriptase on mRNA gives cDNA, which has no introns — essential, because bacteria cannot splice); cut the gene and a plasmid with the same restriction endonuclease to give complementary sticky ends; join with DNA ligase to form recombinant DNA; transform the bacteria (Ca²⁺ and heat shock); identify the transformed cells with a marker gene (e.g. fluorescence, or antibiotic resistance).

Applications and their issues: gene therapy — somatic (affects only the patient; must be repeated) vs germ line (heritable, and prohibited in humans). DNA profiling uses the highly variable short tandem repeats in non-coding DNA — forensics, paternity, and analysis of relatedness. Sequencing has moved from Sanger chain-termination to high-throughput methods, making whole-genome sequencing routine.

Calculate

Your turn — mark-release-recapture

340 beetles are captured, marked and released. A later sample of 50 beetles contains 8 marked individuals. Estimate the total population size.
individuals
Hint: (40 × 50) ÷ 8.
Cloning & biotechnology

Clones, cultures and immobilised enzymes

Natural cloning in plants uses vegetative propagation (runners, bulbs, tubers). Artificial plant cloning uses micropropagation and tissue culture: an explant is taken, sterilised, and grown on a nutrient medium with auxins and cytokinins to form a callus, which is then induced to develop into whole plantlets — thousands of genetically identical plants from one parent, quickly and free of disease.

Animal cloning: artificial twinning (splitting an early embryo) or somatic cell nuclear transfer (the nucleus of a body cell is placed into an enucleated egg, which is stimulated to divide — the Dolly method). Uses: producing genetically identical research animals, and pharming.

Microorganisms in biotechnology — fast reproduction, cheap media (often waste products), no ethical objections, and they can be grown anywhere. Batch culture: a fixed volume, growth follows lag → log → stationary → death phases; used for secondary metabolites such as penicillin. Continuous culture: nutrients added and product removed continuously, so the culture is held in the log phase; used for insulin. Asepsis is essential throughout, or the contaminant will out-compete the culture and may produce toxins.

Immobilised enzymes — trapped in alginate beads, adsorbed onto a surface, or covalently bonded. Advantages: the enzyme is easily recovered and re-used, the product is not contaminated with enzyme, and the enzyme is more stable to changes in temperature and pH. Disadvantage: the rate of reaction is somewhat lower, because the substrate must diffuse to the immobilised active site.

Ecosystems

Energy transfer, succession and sustainability

Producers convert only about 1–3% of incident light into biomass. Thereafter, roughly 10% of the energy is transferred between trophic levels; the rest is lost in respiration (as heat), and in the parts not eaten or not digested (egested or excreted).

NPP = GPP − Rnet primary production = gross primary production − respiratory loss
% efficiency = (energy at this trophic level ÷ energy at the previous level) × 100

Succession: pioneer species colonise bare rock; they weather it and, on death and decomposition, add humus to form soil. This makes the habitat less hostile, so new species colonise and out-compete the pioneers. Biomass, soil depth and biodiversity all increase until a stable climax community is reached. Human activity (grazing, mowing, burning) can arrest this, producing a plagioclimax — which is why conservation of a heathland or a chalk grassland means active management, not simply leaving it alone.

Populations: growth is limited by density-dependent factors (competition, predation, disease — these intensify as the population grows) and density-independent factors (fire, flood, extreme temperature). The population settles at the carrying capacity. Conservation is the active management of biodiversity — it can be reconciled with sustainable exploitation (rotational coppicing, selective felling, fishing quotas and mesh-size limits).

Calculate

Your turn — net primary production

4A grassland has a gross primary production of 45 000 kJ m⁻² yr⁻¹, and its producers lose 18 000 kJ m⁻² yr⁻¹ in respiration. Calculate the net primary production.
kJ m⁻² yr⁻¹
Hint: NPP = GPP − R = 45 000 − 18 000.
Quick check

Why short food chains?

?Food chains rarely have more than four or five trophic levels. What is the fundamental reason?
Sort it

Which technique or field?

Tap a statement, then tap where it belongs.

🔁 PCR / electrophoresis

🧪 Genetic engineering

🌍 Ecosystems

Match it

Match the technique

Tap an item on the left, then its partner on the right.

Term
Meaning
Recap

The big ideas to take away

Mutations: substitution (may be silent), insertion/deletion (frameshift). Mutations in regulatory genes and in genes controlling the cell cycle are the most dangerous

lac operon: in the absence of lactose the repressor binds the operator and blocks RNA polymerase. Lactose binds the repressor, changing its shape so it detaches — the structural genes are transcribed

Development: apoptosis (programmed cell death) sculpts tissues; homeobox genes contain a conserved 180-base homeobox and control the body plan

Inheritance: monohybrid 3:1, dihybrid 9:3:3:1; codominance, sex linkage, autosomal linkage and epistasis all distort the expected ratio

Chi-squared: χ² = Σ(O − E)² ÷ E. If χ² < the critical value at p = 0.05, accept the null hypothesis

Hardy-Weinberg: p + q = 1 and p² + 2pq + q² = 1. Assumes a large population, random mating, no selection, mutation or migration

Genomes: PCR doubles the DNA each cycle; electrophoresis separates fragments by size (DNA is negative, so it moves to the anode); restriction enzymes, ligase, plasmid vectors, marker genes

Ecosystems: NPP = GPP − R; roughly 10% is transferred between trophic levels. Succession runs from pioneer to climax; mark-release-recapture estimates population size

That is the whole of OCR Module 6 — Genetics, evolution and ecosystems. Press Finish to see your score.

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