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AQA A-level Biology (7402) · Biological Molecules
Mini-Lesson

Biological molecules

This mini-lesson covers the whole of AQA 3.1 — Biological molecules: monomers, polymers, condensation and hydrolysis; carbohydrates and lipids; the four levels of protein structure; enzymes as catalysts (induced fit, activation energy) and their competitive and non-competitive inhibitors; nucleic acids and semi-conservative replication; ATP; and the properties of water and inorganic ions.

Work through each screen, answer the questions as you go (some are extended-recall, some are calculations) and collect ⭐ stars. This is A-level content — expect quantitative work and mechanism-level detail. Press Start when you are ready.

Monomers & polymers

Condensation and hydrolysis

Life is built from a small set of monomers joined into polymers. Every polymer in this topic is made the same way and broken the same way:

condensation: monomer + monomer → dimer + H₂Ohydrolysis is the reverse: a water molecule is used to break the bond
  • Monosaccharides (glucose, fructose, galactose) → glycosidic bonds → disaccharides and polysaccharides.
  • Amino acidspeptide bonds → polypeptides.
  • Nucleotidesphosphodiester bonds → DNA and RNA.
  • Glycerol + fatty acidsester bonds → triglycerides (lipids are not polymers — they are macromolecules).

Counting trick you will be examined on: forming a polymer of n monomers requires n − 1 condensation reactions, so n − 1 water molecules are released. A triglyceride, however, always releases exactly 3.

Carbohydrates

α-glucose, β-glucose and the polysaccharides

Glucose is a hexose monosaccharide, C₆H₁₂O₆, with two isomers that differ only in the orientation of the –OH group on carbon 1. That single difference dictates everything downstream.

  • Starch (α-glucose): amylose is unbranched 1,4-glycosidic and coils into a helix; amylopectin adds 1,6 branches. Compact, insoluble (no osmotic effect), many free ends for rapid hydrolysis. Plant storage.
  • Glycogen (α-glucose): like amylopectin but more highly branched → even faster mobilisation. Animal storage in liver and muscle.
  • Cellulose (β-glucose): every alternate molecule is inverted 180° so 1,4 bonds can form. Chains are straight, held side-by-side by hydrogen bonds into microfibrils — huge tensile strength in the cell wall.
Glycogen (α-glucose) 1,6 branches = many free ends → fast hydrolysis to glucose Cellulose (β-glucose) dashed = hydrogen bonds between chains → microfibrils with high tensile strength
Same monomer formula, opposite jobs: storage (compact, branched) vs structure (straight, cross-linked).

Tests: Benedict's (blue → brick-red) for reducing sugars; boil with acid, neutralise, re-test for non-reducing sugars (e.g. sucrose); iodine in potassium iodide (orange → blue-black) for starch.

Lipids

Triglycerides and phospholipids

A triglyceride is one glycerol condensed with three fatty acids, forming three ester bonds and releasing three water molecules. Fatty acids are saturated (no C=C) or unsaturated (one or more C=C, which kink the tail and lower the melting point).

  • Energy store: the long hydrocarbon tails are highly reduced, so oxidation releases roughly twice the energy per gram of carbohydrate. Storage is also anhydrous — no water of hydration to carry.
  • Phospholipid: one fatty acid is replaced by a phosphate group. The phosphate head is hydrophilic, the tails hydrophobic → in water the molecules self-assemble into a bilayer, the basis of every membrane.
  • Test: emulsion test — dissolve in ethanol, then add water; a white/milky emulsion indicates lipid.

Exam precision: "triglycerides are insoluble in water" — because the molecule is essentially non-polar, so it cannot form hydrogen bonds with water. That is also why fat stores do not affect the cell's water potential.

Quick check

Why cellulose is not a food store

?Explain the structural reason a cellulose chain is straight, whereas amylose coils into a helix.
Proteins

Four levels of protein structure

Every amino acid shares a central carbon bonded to an amine group (–NH₂), a carboxyl group (–COOH), a hydrogen and a variable R group. The 20 R groups are the whole of the difference.

  • Primary — the sequence of amino acids joined by peptide bonds. It is encoded by the gene, and it determines everything else.
  • Secondaryhydrogen bonds between the C=O of one peptide bond and the N–H of another produce the α-helix or β-pleated sheet.
  • Tertiary — the chain folds into a precise 3-D shape held by ionic bonds (between charged R groups), disulfide bridges (covalent, between cysteines), further hydrogen bonds, and hydrophobic interactions that bury non-polar R groups in the core.
  • Quaternary — two or more polypeptides, sometimes with a prosthetic group. Haemoglobin = 4 polypeptides (2α, 2β) each with an iron-containing haem group; collagen = 3 chains wound into a triple helix.

Denaturation: heat or extreme pH disrupt hydrogen and ionic bonds (not peptide bonds), so the tertiary structure — and the active site — is lost. Biuret test: blue → purple/lilac for peptide bonds.

Calculate

Your turn — condensation counting

1A polypeptide is synthesised from 87 amino acids. How many molecules of water are released during its formation?
water molecules
Hint: n monomers need n − 1 condensation reactions.
Enzymes

Induced fit and activation energy

Enzymes are globular proteins that act as biological catalysts. The substrate binds the active site to form an enzyme–substrate complex, which lowers the activation energy of the reaction so it proceeds rapidly at body temperature.

E + S ⇌ ES → EP → E + Pthe enzyme is unchanged and can be re-used

The modern model is induced fit, not a rigid lock and key: the active site is not perfectly complementary at first. Substrate binding distorts the active site, moulding it around the substrate. That distortion also strains bonds in the substrate, which is precisely how activation energy is reduced.

Rate factors: temperature (rate rises with kinetic energy until denaturation), pH (charged R groups altered → ionic/H bonds broken → active site changes shape), enzyme concentration (rate ∝ [E] provided substrate is in excess), substrate concentration (rate rises until all active sites are saturated — then Vmax).

Always measure the initial rate. As soon as the reaction runs, substrate is used up, so the gradient falls. Only the tangent at t = 0 compares conditions fairly.

Enzymes · inhibition

Competitive vs non-competitive inhibition

Two mechanisms, and the examiner will test whether you can tell them apart from a graph.

substrate concentration → rate → no inhibitor competitive — same V(max), reached later non-competitive — lower V(max)
The graph is the giveaway: competitive inhibition can be outcompeted; non-competitive inhibition cannot.
  • Competitive: the inhibitor is similar in shape to the substrate and binds the active site, blocking ES complexes. The effect is reduced by increasing substrate concentration, and Vmax is eventually still reached.
  • Non-competitive: the inhibitor binds elsewhere (an allosteric site), changing the tertiary structure of the active site so the substrate no longer fits. Increasing substrate does not reverse it, and Vmax is permanently lowered.

Real examples: statins competitively inhibit HMG-CoA reductase; cyanide non-competitively inhibits cytochrome c oxidase, shutting down oxidative phosphorylation.

Quick check

Reading an inhibition graph

?Adding an inhibitor lowers the rate, but at very high substrate concentration the reaction reaches the same Vmax as the uninhibited reaction. What does this show?
Calculate

Your turn — initial rate

2Catalase decomposes hydrogen peroxide. In the first 150 s, 24 cm³ of oxygen is collected. Calculate the mean rate of reaction in cm³ min⁻¹.
cm³ min⁻¹
Hint: 24 ÷ 150 = 0.16 cm³ s⁻¹, then × 60.
Nucleic acids

DNA, RNA and semi-conservative replication

A nucleotide = pentose sugar + phosphate + nitrogenous base. In DNA the sugar is deoxyribose and the bases are A, T, C, G; in RNA it is ribose with U in place of T.

  • Nucleotides join by phosphodiester bonds (condensation) between the phosphate on carbon 5 of one sugar and the –OH on carbon 3 of the next → a sugar-phosphate backbone.
  • The two strands are antiparallel (5′→3′ against 3′→5′) and held by hydrogen bonds: A–T (2 bonds) and C–G (3 bonds). Because pairing is complementary, %A = %T and %C = %G (Chargaff's rules).
  • DNA is stable, very long (huge information capacity), and the double helix protects the bases inside — ideal as the genetic material.

Semi-conservative replication: DNA helicase breaks the hydrogen bonds and unwinds the helix; each strand acts as a template; free activated DNA nucleotides pair with exposed bases; DNA polymerase catalyses phosphodiester bond formation, moving only along the 3′→5′ template (so the new strand grows 5′→3′). Each daughter molecule contains one original and one new strand.

Meselson & Stahl (1958): bacteria grown on heavy ¹⁵N then switched to ¹⁴N. After one round of replication all the DNA was of intermediate density — impossible under conservative replication. After two rounds: half intermediate, half light — impossible under dispersive replication. Semi-conservative it is.

Calculate

Your turn — Chargaff

3A sample of double-stranded DNA contains 32% adenine. Calculate the percentage of guanine.
%
Hint: A = T = 32%, so A + T = 64%. The remaining 36% is shared equally between C and G.
ATP

ATP — the universal energy currency

ATP is a phosphorylated nucleotide: adenine + ribose + three phosphate groups.

ATP + H₂O → ADP + Picatalysed by ATP hydrolase · releases about 30.5 kJ mol⁻¹
  • The energy released is immediately usable in a single reaction and in a small, manageable quantity — unlike glucose, which would release far too much at once.
  • ATP is not a long-term store: it is unstable and is continually resynthesised from ADP + Pi by ATP synthase during respiration and photosynthesis.
  • The released inorganic phosphate can phosphorylate another molecule, making it more reactive — for example phosphorylating glucose at the start of glycolysis.
Water & inorganic ions

Why water is not just a background solvent

Water is polar: oxygen is δ⁻, hydrogens δ⁺, so molecules form hydrogen bonds with each other. Every property below follows from that one fact.

  • High specific heat capacity — hydrogen bonds absorb a lot of energy before the temperature rises, so aquatic habitats and cell contents are thermally stable.
  • High latent heat of vaporisation — evaporating water carries away a lot of heat: the basis of sweating and of transpirational cooling.
  • Cohesion (and adhesion) — water columns in xylem do not break under tension, and surface tension supports pond-skaters.
  • Excellent solvent — polar solutes and ions dissolve, so they can be transported and can react in solution.
  • Metabolite — a reactant in hydrolysis and in photolysis; a product of condensation and of respiration.

Inorganic ions, and what they actually do: Fe²⁺ in the haem group binds oxygen; PO₄³⁻ forms the backbone of DNA and the phosphate groups of ATP; H⁺ concentration determines pH and therefore enzyme activity, and drives chemiosmosis; Na⁺ establishes the gradient used in co-transport of glucose and amino acids.

Quick check

Water as a coolant

?A mammal sweats to lower its body temperature. Which property of water explains why evaporation of sweat is so effective?
Quick check

Interpreting Meselson and Stahl

?After one round of replication in ¹⁴N medium, DNA that was originally fully ¹⁵N-labelled forms a single band of intermediate density. Which model does this immediately rule out?
Sort it

Which class of molecule?

Tap a card, then tap the class of biological molecule it belongs to.

🍚 Carbohydrate

🧬 Protein

🧈 Lipid

Match it

Bond, molecule and function

Tap an item on the left, then its partner on the right.

Statement
Term
Recap

The big ideas to take away

Polymerisation: condensation forms a bond and releases H₂O; hydrolysis uses H₂O to break it

Carbohydrates: α-glucose → starch/glycogen (helical, branched, compact, insoluble); β-glucose → cellulose (alternate inversion, straight chains, H-bonded microfibrils)

Lipids: triglyceride = glycerol + 3 fatty acids joined by ester bonds (3 condensations); phospholipids are amphipathic → bilayer

Proteins: 1° sequence → 2° α-helix/β-pleated sheet (H bonds) → 3° (ionic, disulfide, hydrogen, hydrophobic interactions) → 4° multiple polypeptides + prosthetic groups

Enzymes: induced fit lowers activation energy; competitive inhibitors bind the active site (overcome by ↑[substrate]); non-competitive bind allosterically and change the active site shape (not overcome)

Nucleic acids: phosphodiester backbone; antiparallel; A–T (2 H-bonds), C–G (3); replication is semi-conservative (helicase, DNA polymerase)

ATP: hydrolysed by ATP hydrolase to ADP + Pi, releasing ~30.5 kJ mol⁻¹; resynthesised by ATP synthase

Water & ions: high specific heat capacity, high latent heat of vaporisation, cohesion, solvent, metabolite; Fe²⁺ in haem, PO₄³⁻ in ATP/DNA, H⁺ sets pH, Na⁺ drives co-transport

That is the whole of AQA 3.1 Biological molecules. Press Finish to see your score.

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